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From: Ostap S. B. M. Bender Jr. on 22 Dec 2009 21:32
On Dec 22, 1:54 pm, "apda" <nos...(a)nospam.com> wrote:
> http://www.youtube.com/watch?v=qUUS63kkH-Y
>
> JSH is a numerical BIGOT, uses 7 ignores 17
>
> Some might try to shoe-horn factors of 7 back into the base factorization,
> by claiming that the result from the ring of algebraic integers shows that
> somehow 7 got split up, so let's consider that notion by introducing more
> functions:
>
> w_1(x)*w_2(x) = 7, and
>
> (5a_1(x) + 7)*(a_2(x) + 7) = (5b_1(x)*w_1(x) + 7)*(5b_2(x)*w_2(x) + 7)
>
> and go backwards-reversing how I started this post-by now dividing 7 out:
>
> (5a_1(x) + 7)*(a_2(x) + 7)/7 = (5b_1(x) + w_2(x))*(5b_2(x) + w_1(x))
>
> and notice it isn't gone on the right! The functions w_1(x) and w_2(x) are
> still there as a part of the factorization, but
>
> 175x^2 - 15x + 2 = (f(x) + 2)*(g(x) + 1)
>
> doesn't have w_1(x) and w_2(x) in it, and 7 is not a part of that
> factorization, as why should it be?
>
> I could have multiplied by 13 or some other number.
>
> So there is no way LOGICALLY that 7 can be trapped into the original
> factorization.
>
> The trouble here though is that people who resist the results above resist
> them because they see the mathematical result as a human failure which they
> can't accept because they get taught in school that mathematics is perfect
> and that past mathematicians were perfect on all the important details, and
> couldn't have made a mistake that would let it be true.
>

So, how is this going to help you "make millions"?
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