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From: Dravid on 4 Feb 2010 08:52
Hi all,
Am using lpc2478 for 6.5 TFT LCD development in that am using
256Mb(K4S561632E-FROM SAMSUNG) SDRAM for LCD FRAME BUFFER. can anyone help
me to solve the sdram initialization problem,
i have attached the sdram init coding can anyone suggest me to solve the
sdram initalizing problem.


void sdramInit(void)
{
volatile unsigned short i,dummy;
PINSEL5 &= 0XF0FCFCC0;
PINSEL5 |= 0X05010115;
PINMODE5 &= 0xF0FCFCC0;
PINMODE5 |= 0x0A02022A;
PINSEL6 |= 0X55555555;
PINMODE6 |= 0XAAAAAAAA;
PINSEL8 &= 0XC0000000;
PINSEL8 |= 0X15555555;
PINMODE8 &= 0XC0000000;
PINMODE8 |= 0X2AAAAAAA;
PCONP |=0X800;
EMC_CTRL =1;
EMC_DYN_RD_CFG =1;
EMC_DYN_RASCAS0 |=0X00000303;
EMC_DYN_RP = 2;
EMC_DYN_RAS = 3;
EMC_DYN_SREX= 1;
EMC_DYN_APR = 2;
EMC_DYN_DAL = 3;
EMC_DYN_WR = 2;
EMC_DYN_RC = 3;
EMC_DYN_RFC = 3;
EMC_DYN_XSR = 7;
EMC_DYN_RRD = 1;
EMC_DYN_MRD = 1;
EMC_DYN_CFG0= 0X00000680;
EMC_DYN_CTRL= 0X183; //Issue SDRAM NOP (no operation) command ;
for(i=0; i<0x40; i++)
{
__asm
{
NOP
}
}
mdelay(200);
EMC_DYN_CTRL|=0x103; // Issue SDRAM PALL (precharge all) command.
EMC_DYN_RFSH = 0X2;
for(i= 128; i; --i); // > 128 clk
EMC_DYN_RFSH = 0x1c;
EMC_DYN_CTRL|=0x83;
//Issue SDRAM MODE command.
dummy = *((volatile unsigned short*)(LCD_FRAME_BUFFER | (22 << 11 )));
EMC_DYN_CTRL = 0x3; //Issue SDRAM norm command ;
EMC_DYN_CFG0|=0x80000; //Buffer enabled for accesses to DCS0 chip
}


Regards,
Dravid.



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