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From: us on 15 May 2010 06:40
"pier "
> i tried also function RESHAPE but as output obtained only 1 matrix even if customized

well, yes... did your really try to get your hands dirty...

m=ceil(5*rand(12,52)); % <- your ori mat...
mr=reshape(m,[12,4,13]); % <- 13 submats of size 12x4 each...
% eg, let's access submat #12
sm=mr(:,:,12);
% once you tot this far, however, you have to carefully look at it and
% see whether the packing order is correct...
% you may have to look at PERMUTE...

us
From: pier on 15 May 2010 06:58
Many thx for the example....
now i undestand!!!!!
:D
thx
From: pier on 16 May 2010 06:04
hi another little question.....
i understand the use of reshape but now i have another matrix 192x13
using reshape(B=reshape(A,[12,13,16]) i want to obtaine 16 matrix 12x13 but i realize
that with this reshape matrix B will be composed yes 12 x13 but instead taking the first 12 rows,the second 12 rows etc...it will take the colomuns!!!!!!!!!!!!
can somebody tell me what can i do?please
From: us on 16 May 2010 06:15
"pier " <bombociccio1(a)libero.it> wrote in message <hslunv$s6m$1(a)fred.mathworks.com>...
> Many thx for the example....
> now i undestand!!!!!
> :D
> thx

welll... in my last replay there was a significant little addition at the very end:
....% you may have to look at PERMUTE...

did you(?)...

us
From: pier on 16 May 2010 06:41
i haven't notice
:P

for the moment i do this:
B=reshape(A',[12,13,16])
the when i recall submat
(B(:,:,1))'
having the right size of rows and column

using Permute is better than this??)
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