=MAX(SUBTOTAL(9,OFFSET(B1,ROW(1:21),,3)))
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From: Martin on 14 May 2010 15:31 =MAX(SUBTOTAL(9,OFFSET(B1,ROW(1:21),,3))) I am trying to do this exact same formula, however, I need my array to calculate across columns instead of rows, I have substituted ROW with COLUMN but I get 0.00's. Any advice? Shane Devenshire wrote: There is one significant difference, try 01-Feb-10 There is one significant difference, try generalizing =MAX(B2:B22+B3:B23+B4:B24) to the max of 30 consecutive numbers. Then try generalizing =MAX(SUBTOTAL(9,OFFSET(B1,ROW(1:21),,3))) -- If this helps, please click the Yes button. Cheers, Shane Devenshire "T. Valko" wrote: Previous Posts In This Thread: On Friday, January 29, 2010 3:03 PM Desoto wrote: Best 3 Consecutive Months I have 10 years worth of monthly data and need to determine the best (or worst) three consecutive months for benchmarking purposes. How do I write a formula that provides me the value of the highest (or lowest) value for three consecutive months (perhaps array formula?). I want to avoid at all cost adding another column of data to the worksheet that provides a running three month average and then utilizing the MAX or MIN function to determine the value. Thanks in advance Rachel On Friday, January 29, 2010 3:46 PM Mike H wrote: Hi,It may be possible in a single formula but nothing springs to mind so here Hi, It may be possible in a single formula but nothing springs to mind so here is another solution. Say your data are in column A. Put this in (say) B1 and drag down =SUM(A1:A3) You now have a sum of every set of 3 consecutive cell so simply max and min this new range to get the highest and lowest values for 3 consecutive months. -- Mike When competing hypotheses are otherwise equal, adopt the hypothesis that introduces the fewest assumptions while still sufficiently answering the question. "Desoto" wrote: On Friday, January 29, 2010 3:49 PM Shane Devenshire wrote: Hi,Assuming you numbers are in B2:B24 with titles on row 1, enter the Hi, Assuming you numbers are in B2:B24 with titles on row 1, enter the following array formula: =MAX(SUBTOTAL(9,OFFSET(B1,ROW(1:21),,3))) For the 3 lowest you need to be a little more careful: =MIN(SUBTOTAL(9,OFFSET(B1,ROW(1:21),,3))) For an array formula you do not type the outer {}'s, you press SHIFT+CTRL+Enter to enter the formula not Enter. Of course this does not identify the location of those 3 consecutive items. -- If this helps, please click the Yes button. Cheers, Shane Devenshire "Desoto" wrote: On Friday, January 29, 2010 4:04 PM Glenn wrote: Shane Devenshire wrote:Array formula for the row number (within the list of Shane Devenshire wrote: Array formula for the row number (within the list of numbers) of the start of those 3 consecutive items: =MATCH( MAX(SUBTOTAL(9,OFFSET(B1,ROW(1:21),,3))), SUBTOTAL(9,OFFSET(B1,ROW(1:21),,3)), 0) On Friday, January 29, 2010 5:17 PM Desoto wrote: Absolutely PERFECT!!! Thanks Guys"Glenn" wrote: Absolutely PERFECT!!! Thanks Guys "Glenn" wrote: On Friday, January 29, 2010 5:43 PM Shane Devenshire wrote: Hi Glenn,Yes I knew that but since the original post did not ask for it, I Hi Glenn, Yes I knew that but since the original post did not ask for it, I just want to hint that they might want to know something else. If he wanted we could show him the full address of these results or we could conditionally format them. However, it is the core formula that I designed that was the critical element, I felt. -- If this helps, please click the Yes button. Cheers, Shane Devenshire "Glenn" wrote: On Friday, January 29, 2010 10:31 PM T. Valko wrote: Try these array formulas** Try these array formulas** : Max: =MAX(B2:B22+B3:B23+B4:B24) Min: =MIN(B2:B22+B3:B23+B4:B24) Note the 3 cell offset of the ranges. ** array formulas need to be entered using the key combination of CTRL,SHIFT,ENTER (not just ENTER). Hold down both the CTRL key and the SHIFT key then hit ENTER. -- Biff Microsoft Excel MVP On Saturday, January 30, 2010 9:06 AM Alojz wrote: Yours is very smart!"T. Valko" wrote: Yours is very smart! "T. Valko" wrote: On Saturday, January 30, 2010 11:10 AM T. Valko wrote: Thanks!--BiffMicrosoft Excel MVP Thanks! -- Biff Microsoft Excel MVP On Monday, February 01, 2010 5:22 PM Shane Devenshire wrote: There is one significant difference, try There is one significant difference, try generalizing =MAX(B2:B22+B3:B23+B4:B24) to the max of 30 consecutive numbers. Then try generalizing =MAX(SUBTOTAL(9,OFFSET(B1,ROW(1:21),,3))) -- If this helps, please click the Yes button. Cheers, Shane Devenshire "T. Valko" wrote: On Monday, February 01, 2010 6:11 PM T. Valko wrote: Yeah, that is true. Yeah, that is true. I would not use or suggest that formula for more than 3 or 4 consecutive cell intervals. While we are at it... If the range to calculate is B2:B24... ROW(1:21) is not very intuitive in addition to not being very robust. -- Biff Microsoft Excel MVP Submitted via EggHeadCafe - Software Developer Portal of Choice Get Silverlight 4 Installed: Tips and Tricks http://www.eggheadcafe.com/tutorials/aspnet/05910e41-3846-4db9-8e1b-f54c56a64ed9/get-silverlight-4-install.aspx
From: Shane Devenshire on 14 May 2010 19:31 How about a little more detail. What exactly do you want? How do you know you even want this formula? Tell us what you are trying to calculate, please. -- If this helps, please click the Yes button. Cheers, Shane Devenshire "unknown" wrote: >
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