From: neddie on
On Jun 2, 12:37 am, "Ron M." <strmbr...(a)hotmail.com> wrote:
> On May 28, 9:50 am, "ian field" <gangprobing.al...(a)ntlworld.com>
> wrote:
>
>
>
> > "JosephKK" <quiettechb...(a)yahoo.com> wrote in message
>
> >news:hv9vv51dda7rsa0g5srjc2bgncd1362vd5(a)4ax.com...
> > On Thu, 27 May 2010 12:04:50 -0700 (PDT), "Ron M."
>
> > <strmbr...(a)hotmail.com> wrote:
> > >On May 27, 2:12 am, ehsjr <eh...(a)nospamverizon.net> wrote:
> > >> Ron M. wrote:
> > >> > On May 26, 3:11 pm, "ian field" <gangprobing.al...(a)ntlworld.com>
> > >> > wrote:
>
> > >> >><op...(a)hotmail.com> wrote in message
>
> > >> >>news:8885382a-f931-45f8-977b-4cbb931c0864(a)q8g2000vbm.googlegroups.com...
>
> > >> >>>Once you have your 9V battery on top of your 12V rail (21V gate
> > >> >>>pull-up
> > >> >>>supply) you connect the rail via a pull-up resistor
>
> > >> >>Geez! Using a P-Channel MOSFET like the IRF5305 would be so much
> > >> >>simpler. Why has he latched onto the use of a N-Channel MOSFET?
>
> > >> >>***************
>
> > >> >>Sounds like he already has the N-channel devices, and is using a
> > >> >>significant
> > >> >>number, so changing route halfway and buying up a batch of P-channel
> > >> >>devices
> > >> >>might be too much over budget.
>
> > >> >>P-channel devices are more expensive and less efficient than N-channel
> > >> >>and
> > >> >>the OP might not have been able to find a reasonably priced P device
> > >> >>that he
> > >> >>liked for the current rating he wanted.
>
> > >> > Ok Ian. If I only need a max of 6 amps and am driving it with 12 on
> > >> > gate would that be sufficient for the channel to open enough? I think
> > >> > the easiest way to do this is just build a test circuit and try it..
> > >> > All it will cost me is $1.80. It would be simpler and then I would
> > >> > know for sure. I'm still just having difficulty grasping the extra
> > >> > rail concept. I see the specs but can't figure out why I have to go so
> > >> > much higher than the source for it to conduct enough for my needs. I
> > >> > think a remedial class on MOSFET operation is definitely in order for
> > >> > me.
>
> > >> Essentially, you are using the mosfet as a switch, so the
> > >> voltage at the source pin will be almost equal to the
> > >> voltage at the drain pin when the mosfet conducts.
>
> > >> +12 -------------+ +12 ----+
> > >> | |
> > >> ___|D |
> > >> || o
> > >> ||<. ~ \
> > >> G_____||_|_ ~ o
> > >> |S |
> > >> [Load] [Load]
> > >> | |
> > >> Gnd -------------+ Gnd ----+
>
> > >> To make your mosfet conduct (in effect, closing the switch)
> > >> the voltage at g must be raised *above* the voltage at s
> > >> by *at least* the "gate threshold voltage". And good design
> > >> is to raise it more than that minimum, to ensure that the
> > >> mosfet is turned on hard.
>
> > >> In your case, with your mosfet, a 12 volt supply and a 6 amp
> > >> load current, the gate should be raised to about 20 volts.
> > >> That makes the gate to source voltage about 8 volts, and ensures
> > >> that the mosfet is turned on completely.
>
> > >> Ed- Hide quoted text -
>
> > >> - Show quoted text -
>
> > >Just had a thought. Went back and looked at the requirements of the
> > >actual e-match and what a bonehead I have been. They require 1/2 amp
> > >guaranteed fire current. So with that in mind maybe if I pad the Drain
> > >down some with a resistor maybe I can still get within the full turn
> > >on voltage. Just throwing things out there now but it might work.
>
> > If you can handle the change, use NFET to ground switching and put the
> > relays on the positive rail.
> > Alternatively, use PFET to switch the positive rail, the reduction in
> > complexity can buy a worthy change in FET price.
>
> > I'm starting to get the impression this guy won't take sound advice!- Hide quoted text -
>
> > - Show quoted text -
>
> No it's not that. I am having to wrap myself around all this and still
> keep my base design. This is just the output circuit. I have other
> circuitry considerations that I must take into account. I have already
> designed and tested the sequencing circuits and they function great. I
> don't want to have to go back and re-design the whole thing to
> accommodate just the outputs. That is why I am so hard up to not
> change my control side. I am using 555 as pulse timing and buffer for
> the outputs. This part of the circuitry must remain. I know I am being
> rather rigid but this section cannot change as the pulse shaping is
> critical for it to function correctly. I will eventually get it to
> work correctly with enough current carrying capacity to do what it
> needs to. I was just entertaining different thoughts on accomplishing
> it. Now that I have all of these different suggestions I wll get some
> parts and start bread boarding to see what works and what don't. Sorry
> for taking you guys on this roller coaster. I will come back and let
> all of you know what worked and what didn't. That is if you're at all
> interested. THANKS once again to all who have responded. L8R

A simple method of getting the extra voltage needed for the drive for
the N channel
fet is a BATTERY!!! Just add it in "on top"of the supply for the fets.
It will have to be changed when it goes flat , but the current draw is
not big and it will probably
last a long time.All you need then is a couple of resistors and 2
transistors.
From: ian field on

"neddie" <seegoon99(a)yahoo.com> wrote in message
news:e6534cd8-07af-4844-b35c-85bccdfbdc07(a)m33g2000vbi.googlegroups.com...
On Jun 2, 12:37 am, "Ron M." <strmbr...(a)hotmail.com> wrote:
> On May 28, 9:50 am, "ian field" <gangprobing.al...(a)ntlworld.com>
> wrote:
>
>
>
> > "JosephKK" <quiettechb...(a)yahoo.com> wrote in message
>
> >news:hv9vv51dda7rsa0g5srjc2bgncd1362vd5(a)4ax.com...
> > On Thu, 27 May 2010 12:04:50 -0700 (PDT), "Ron M."
>
> > <strmbr...(a)hotmail.com> wrote:
> > >On May 27, 2:12 am, ehsjr <eh...(a)nospamverizon.net> wrote:
> > >> Ron M. wrote:
> > >> > On May 26, 3:11 pm, "ian field" <gangprobing.al...(a)ntlworld.com>
> > >> > wrote:
>
> > >> >><op...(a)hotmail.com> wrote in message
>
> > >> >>news:8885382a-f931-45f8-977b-4cbb931c0864(a)q8g2000vbm.googlegroups.com...
>
> > >> >>>Once you have your 9V battery on top of your 12V rail (21V gate
> > >> >>>pull-up
> > >> >>>supply) you connect the rail via a pull-up resistor
>
> > >> >>Geez! Using a P-Channel MOSFET like the IRF5305 would be so much
> > >> >>simpler. Why has he latched onto the use of a N-Channel MOSFET?
>
> > >> >>***************
>
> > >> >>Sounds like he already has the N-channel devices, and is using a
> > >> >>significant
> > >> >>number, so changing route halfway and buying up a batch of
> > >> >>P-channel
> > >> >>devices
> > >> >>might be too much over budget.
>
> > >> >>P-channel devices are more expensive and less efficient than
> > >> >>N-channel
> > >> >>and
> > >> >>the OP might not have been able to find a reasonably priced P
> > >> >>device
> > >> >>that he
> > >> >>liked for the current rating he wanted.
>
> > >> > Ok Ian. If I only need a max of 6 amps and am driving it with 12 on
> > >> > gate would that be sufficient for the channel to open enough? I
> > >> > think
> > >> > the easiest way to do this is just build a test circuit and try it.
> > >> > All it will cost me is $1.80. It would be simpler and then I would
> > >> > know for sure. I'm still just having difficulty grasping the extra
> > >> > rail concept. I see the specs but can't figure out why I have to go
> > >> > so
> > >> > much higher than the source for it to conduct enough for my needs.
> > >> > I
> > >> > think a remedial class on MOSFET operation is definitely in order
> > >> > for
> > >> > me.
>
> > >> Essentially, you are using the mosfet as a switch, so the
> > >> voltage at the source pin will be almost equal to the
> > >> voltage at the drain pin when the mosfet conducts.
>
> > >> +12 -------------+ +12 ----+
> > >> | |
> > >> ___|D |
> > >> || o
> > >> ||<. ~ \
> > >> G_____||_|_ ~ o
> > >> |S |
> > >> [Load] [Load]
> > >> | |
> > >> Gnd -------------+ Gnd ----+
>
> > >> To make your mosfet conduct (in effect, closing the switch)
> > >> the voltage at g must be raised *above* the voltage at s
> > >> by *at least* the "gate threshold voltage". And good design
> > >> is to raise it more than that minimum, to ensure that the
> > >> mosfet is turned on hard.
>
> > >> In your case, with your mosfet, a 12 volt supply and a 6 amp
> > >> load current, the gate should be raised to about 20 volts.
> > >> That makes the gate to source voltage about 8 volts, and ensures
> > >> that the mosfet is turned on completely.
>
> > >> Ed- Hide quoted text -
>
> > >> - Show quoted text -
>
> > >Just had a thought. Went back and looked at the requirements of the
> > >actual e-match and what a bonehead I have been. They require 1/2 amp
> > >guaranteed fire current. So with that in mind maybe if I pad the Drain
> > >down some with a resistor maybe I can still get within the full turn
> > >on voltage. Just throwing things out there now but it might work.
>
> > If you can handle the change, use NFET to ground switching and put the
> > relays on the positive rail.
> > Alternatively, use PFET to switch the positive rail, the reduction in
> > complexity can buy a worthy change in FET price.
>
> > I'm starting to get the impression this guy won't take sound advice!-
> > Hide quoted text -
>
> > - Show quoted text -
>
> No it's not that. I am having to wrap myself around all this and still
> keep my base design. This is just the output circuit. I have other
> circuitry considerations that I must take into account. I have already
> designed and tested the sequencing circuits and they function great. I
> don't want to have to go back and re-design the whole thing to
> accommodate just the outputs. That is why I am so hard up to not
> change my control side. I am using 555 as pulse timing and buffer for
> the outputs. This part of the circuitry must remain. I know I am being
> rather rigid but this section cannot change as the pulse shaping is
> critical for it to function correctly. I will eventually get it to
> work correctly with enough current carrying capacity to do what it
> needs to. I was just entertaining different thoughts on accomplishing
> it. Now that I have all of these different suggestions I wll get some
> parts and start bread boarding to see what works and what don't. Sorry
> for taking you guys on this roller coaster. I will come back and let
> all of you know what worked and what didn't. That is if you're at all
> interested. THANKS once again to all who have responded. L8R

A simple method of getting the extra voltage needed for the drive for
the N channel
fet is a BATTERY!!! Just add it in "on top"of the supply for the fets.
It will have to be changed when it goes flat , but the current draw is
not big and it will probably
last a long time.All you need then is a couple of resistors and 2
transistors.

Do try to keep up - I suggested that days ago.


From: Kevin McMurtrie on
In article <8hvNn.20$EM2.15(a)newsfe10.ams2>,
"ian field" <gangprobing.alien(a)ntlworld.com> wrote:

> "neddie" <seegoon99(a)yahoo.com> wrote in message
> news:e6534cd8-07af-4844-b35c-85bccdfbdc07(a)m33g2000vbi.googlegroups.com...
> On Jun 2, 12:37 am, "Ron M." <strmbr...(a)hotmail.com> wrote:
> > On May 28, 9:50 am, "ian field" <gangprobing.al...(a)ntlworld.com>
> > wrote:
> >
> >
> >
> > > "JosephKK" <quiettechb...(a)yahoo.com> wrote in message
> >
> > >news:hv9vv51dda7rsa0g5srjc2bgncd1362vd5(a)4ax.com...
> > > On Thu, 27 May 2010 12:04:50 -0700 (PDT), "Ron M."
> >
> > > <strmbr...(a)hotmail.com> wrote:
> > > >On May 27, 2:12 am, ehsjr <eh...(a)nospamverizon.net> wrote:
> > > >> Ron M. wrote:
> > > >> > On May 26, 3:11 pm, "ian field" <gangprobing.al...(a)ntlworld.com>
> > > >> > wrote:
> >
> > > >> >><op...(a)hotmail.com> wrote in message
> >
> > > >> >>news:8885382a-f931-45f8-977b-4cbb931c0864(a)q8g2000vbm.googlegroups.com
> > > >> >>...
> >
> > > >> >>>Once you have your 9V battery on top of your 12V rail (21V gate
> > > >> >>>pull-up
> > > >> >>>supply) you connect the rail via a pull-up resistor
> >
> > > >> >>Geez! Using a P-Channel MOSFET like the IRF5305 would be so much
> > > >> >>simpler. Why has he latched onto the use of a N-Channel MOSFET?
> >
> > > >> >>***************
> >
> > > >> >>Sounds like he already has the N-channel devices, and is using a
> > > >> >>significant
> > > >> >>number, so changing route halfway and buying up a batch of
> > > >> >>P-channel
> > > >> >>devices
> > > >> >>might be too much over budget.
> >
> > > >> >>P-channel devices are more expensive and less efficient than
> > > >> >>N-channel
> > > >> >>and
> > > >> >>the OP might not have been able to find a reasonably priced P
> > > >> >>device
> > > >> >>that he
> > > >> >>liked for the current rating he wanted.
> >
> > > >> > Ok Ian. If I only need a max of 6 amps and am driving it with 12 on
> > > >> > gate would that be sufficient for the channel to open enough? I
> > > >> > think
> > > >> > the easiest way to do this is just build a test circuit and try it.
> > > >> > All it will cost me is $1.80. It would be simpler and then I would
> > > >> > know for sure. I'm still just having difficulty grasping the extra
> > > >> > rail concept. I see the specs but can't figure out why I have to go
> > > >> > so
> > > >> > much higher than the source for it to conduct enough for my needs.
> > > >> > I
> > > >> > think a remedial class on MOSFET operation is definitely in order
> > > >> > for
> > > >> > me.
> >
> > > >> Essentially, you are using the mosfet as a switch, so the
> > > >> voltage at the source pin will be almost equal to the
> > > >> voltage at the drain pin when the mosfet conducts.
> >
> > > >> +12 -------------+ +12 ----+
> > > >> | |
> > > >> ___|D |
> > > >> || o
> > > >> ||<. ~ \
> > > >> G_____||_|_ ~ o
> > > >> |S |
> > > >> [Load] [Load]
> > > >> | |
> > > >> Gnd -------------+ Gnd ----+
> >
> > > >> To make your mosfet conduct (in effect, closing the switch)
> > > >> the voltage at g must be raised *above* the voltage at s
> > > >> by *at least* the "gate threshold voltage". And good design
> > > >> is to raise it more than that minimum, to ensure that the
> > > >> mosfet is turned on hard.
> >
> > > >> In your case, with your mosfet, a 12 volt supply and a 6 amp
> > > >> load current, the gate should be raised to about 20 volts.
> > > >> That makes the gate to source voltage about 8 volts, and ensures
> > > >> that the mosfet is turned on completely.
> >
> > > >> Ed- Hide quoted text -
> >
> > > >> - Show quoted text -
> >
> > > >Just had a thought. Went back and looked at the requirements of the
> > > >actual e-match and what a bonehead I have been. They require 1/2 amp
> > > >guaranteed fire current. So with that in mind maybe if I pad the Drain
> > > >down some with a resistor maybe I can still get within the full turn
> > > >on voltage. Just throwing things out there now but it might work.
> >
> > > If you can handle the change, use NFET to ground switching and put the
> > > relays on the positive rail.
> > > Alternatively, use PFET to switch the positive rail, the reduction in
> > > complexity can buy a worthy change in FET price.
> >
> > > I'm starting to get the impression this guy won't take sound advice!-
> > > Hide quoted text -
> >
> > > - Show quoted text -
> >
> > No it's not that. I am having to wrap myself around all this and still
> > keep my base design. This is just the output circuit. I have other
> > circuitry considerations that I must take into account. I have already
> > designed and tested the sequencing circuits and they function great. I
> > don't want to have to go back and re-design the whole thing to
> > accommodate just the outputs. That is why I am so hard up to not
> > change my control side. I am using 555 as pulse timing and buffer for
> > the outputs. This part of the circuitry must remain. I know I am being
> > rather rigid but this section cannot change as the pulse shaping is
> > critical for it to function correctly. I will eventually get it to
> > work correctly with enough current carrying capacity to do what it
> > needs to. I was just entertaining different thoughts on accomplishing
> > it. Now that I have all of these different suggestions I wll get some
> > parts and start bread boarding to see what works and what don't. Sorry
> > for taking you guys on this roller coaster. I will come back and let
> > all of you know what worked and what didn't. That is if you're at all
> > interested. THANKS once again to all who have responded. L8R
>
> A simple method of getting the extra voltage needed for the drive for
> the N channel
> fet is a BATTERY!!! Just add it in "on top"of the supply for the fets.
> It will have to be changed when it goes flat , but the current draw is
> not big and it will probably
> last a long time.All you need then is a couple of resistors and 2
> transistors.
>
> Do try to keep up - I suggested that days ago.

I've seen spec sheets for chips that have a chain of LEDs on one side
and a chain of photo diodes on the other side. I always wondered which
they more frequently used for - precision scientific instruments or
hacks.
--
I won't see Google Groups replies because I must filter them as spam
From: JosephKK on
On Wed, 02 Jun 2010 23:08:37 -0700, Kevin McMurtrie
<mcmurtrie(a)pixelmemory.us> wrote:

>In article <8hvNn.20$EM2.15(a)newsfe10.ams2>,
> "ian field" <gangprobing.alien(a)ntlworld.com> wrote:
>
>> "neddie" <seegoon99(a)yahoo.com> wrote in message
>> news:e6534cd8-07af-4844-b35c-85bccdfbdc07(a)m33g2000vbi.googlegroups.com...
>> On Jun 2, 12:37 am, "Ron M." <strmbr...(a)hotmail.com> wrote:
>> > On May 28, 9:50 am, "ian field" <gangprobing.al...(a)ntlworld.com>
>> > wrote:
>> >
<snip>

>> > No it's not that. I am having to wrap myself around all this and still
>> > keep my base design. This is just the output circuit. I have other
>> > circuitry considerations that I must take into account. I have already
>> > designed and tested the sequencing circuits and they function great. I
>> > don't want to have to go back and re-design the whole thing to
>> > accommodate just the outputs. That is why I am so hard up to not
>> > change my control side. I am using 555 as pulse timing and buffer for
>> > the outputs. This part of the circuitry must remain. I know I am being
>> > rather rigid but this section cannot change as the pulse shaping is
>> > critical for it to function correctly. I will eventually get it to
>> > work correctly with enough current carrying capacity to do what it
>> > needs to. I was just entertaining different thoughts on accomplishing
>> > it. Now that I have all of these different suggestions I wll get some
>> > parts and start bread boarding to see what works and what don't. Sorry
>> > for taking you guys on this roller coaster. I will come back and let
>> > all of you know what worked and what didn't. That is if you're at all
>> > interested. THANKS once again to all who have responded. L8R
>>
>> A simple method of getting the extra voltage needed for the drive for
>> the N channel
>> fet is a BATTERY!!! Just add it in "on top"of the supply for the fets.
>> It will have to be changed when it goes flat , but the current draw is
>> not big and it will probably
>> last a long time.All you need then is a couple of resistors and 2
>> transistors.
>>
>> Do try to keep up - I suggested that days ago.
>
>I've seen spec sheets for chips that have a chain of LEDs on one side
>and a chain of photo diodes on the other side. I always wondered which
>they more frequently used for - precision scientific instruments or
>hacks.

How about a link or something?
From: Ron M. on
On Jun 1, 6:37 pm, "Ron M." <strmbr...(a)hotmail.com> wrote:
> On May 28, 9:50 am, "ian field" <gangprobing.al...(a)ntlworld.com>
> wrote:
>
>
>
>
>
> > "JosephKK" <quiettechb...(a)yahoo.com> wrote in message
>
> >news:hv9vv51dda7rsa0g5srjc2bgncd1362vd5(a)4ax.com...
> > On Thu, 27 May 2010 12:04:50 -0700 (PDT), "Ron M."
>
> > <strmbr...(a)hotmail.com> wrote:
> > >On May 27, 2:12 am, ehsjr <eh...(a)nospamverizon.net> wrote:
> > >> Ron M. wrote:
> > >> > On May 26, 3:11 pm, "ian field" <gangprobing.al...(a)ntlworld.com>
> > >> > wrote:
>
> > >> >><op...(a)hotmail.com> wrote in message
>
> > >> >>news:8885382a-f931-45f8-977b-4cbb931c0864(a)q8g2000vbm.googlegroups.com...
>
> > >> >>>Once you have your 9V battery on top of your 12V rail (21V gate
> > >> >>>pull-up
> > >> >>>supply) you connect the rail via a pull-up resistor
>
> > >> >>Geez! Using a P-Channel MOSFET like the IRF5305 would be so much
> > >> >>simpler. Why has he latched onto the use of a N-Channel MOSFET?
>
> > >> >>***************
>
> > >> >>Sounds like he already has the N-channel devices, and is using a
> > >> >>significant
> > >> >>number, so changing route halfway and buying up a batch of P-channel
> > >> >>devices
> > >> >>might be too much over budget.
>
> > >> >>P-channel devices are more expensive and less efficient than N-channel
> > >> >>and
> > >> >>the OP might not have been able to find a reasonably priced P device
> > >> >>that he
> > >> >>liked for the current rating he wanted.
>
> > >> > Ok Ian. If I only need a max of 6 amps and am driving it with 12 on
> > >> > gate would that be sufficient for the channel to open enough? I think
> > >> > the easiest way to do this is just build a test circuit and try it..
> > >> > All it will cost me is $1.80. It would be simpler and then I would
> > >> > know for sure. I'm still just having difficulty grasping the extra
> > >> > rail concept. I see the specs but can't figure out why I have to go so
> > >> > much higher than the source for it to conduct enough for my needs. I
> > >> > think a remedial class on MOSFET operation is definitely in order for
> > >> > me.
>
> > >> Essentially, you are using the mosfet as a switch, so the
> > >> voltage at the source pin will be almost equal to the
> > >> voltage at the drain pin when the mosfet conducts.
>
> > >> +12 -------------+ +12 ----+
> > >> | |
> > >> ___|D |
> > >> || o
> > >> ||<. ~ \
> > >> G_____||_|_ ~ o
> > >> |S |
> > >> [Load] [Load]
> > >> | |
> > >> Gnd -------------+ Gnd ----+
>
> > >> To make your mosfet conduct (in effect, closing the switch)
> > >> the voltage at g must be raised *above* the voltage at s
> > >> by *at least* the "gate threshold voltage". And good design
> > >> is to raise it more than that minimum, to ensure that the
> > >> mosfet is turned on hard.
>
> > >> In your case, with your mosfet, a 12 volt supply and a 6 amp
> > >> load current, the gate should be raised to about 20 volts.
> > >> That makes the gate to source voltage about 8 volts, and ensures
> > >> that the mosfet is turned on completely.
>
> > >> Ed- Hide quoted text -
>
> > >> - Show quoted text -
>
> > >Just had a thought. Went back and looked at the requirements of the
> > >actual e-match and what a bonehead I have been. They require 1/2 amp
> > >guaranteed fire current. So with that in mind maybe if I pad the Drain
> > >down some with a resistor maybe I can still get within the full turn
> > >on voltage. Just throwing things out there now but it might work.
>
> > If you can handle the change, use NFET to ground switching and put the
> > relays on the positive rail.
> > Alternatively, use PFET to switch the positive rail, the reduction in
> > complexity can buy a worthy change in FET price.
>
> > I'm starting to get the impression this guy won't take sound advice!- Hide quoted text -
>
> > - Show quoted text -
>
> No it's not that. I am having to wrap myself around all this and still
> keep my base design. This is just the output circuit. I have other
> circuitry considerations that I must take into account. I have already
> designed and tested the sequencing circuits and they function great. I
> don't want to have to go back and re-design the whole thing to
> accommodate just the outputs. That is why I am so hard up to not
> change my control side. I am using 555 as pulse timing and buffer for
> the outputs. This part of the circuitry must remain. I know I am being
> rather rigid but this section cannot change as the pulse shaping is
> critical for it to function correctly. I will eventually get it to
> work correctly with enough current carrying capacity to do what it
> needs to. I was just entertaining different thoughts on accomplishing
> it. Now that I have all of these different suggestions I wll get some
> parts and start bread boarding to see what works and what don't. Sorry
> for taking you guys on this roller coaster. I will come back and let
> all of you know what worked and what didn't. That is if you're at all
> interested. THANKS once again to all who have responded. L8R- Hide quoted text -
>
> - Show quoted text -

Got it. I believe someone here suggested moving the MOSFET to the
source side and the switching and load to the drain side. Also re-
positioned the steering diodes to the drain side. That was the ticket.
Now the Vsg is correct and the MOSFET turns on beautifully. All I
needed was to sit back and re-think the whole thing. Also saved myself
$100 in relays to boot. To all that have assisted on this a big THANKS
is in order. Especially Ian for the kick in the pants to get my brain
working again. I'll post a link of the fireworks display that I use
the thing on but it will be October before that happens. Once again
THANKS to all.