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From: Mayayana on 7 Aug 2010 08:47 | Yes I will be the first to admit that i do not have any knowledge on bit | operations but so far this has not stopped me from getting useful code to | work to my requirements. I have read the article that Kevin Provance | suggested at that has not helped me to understand the problem I have. | As you said I had tried the prints to the intermediate window and I get this | result | | ? (17 and 16) <> 16 Result False | ? (16 and 16) <> 16 Result False | is this the correct answer? it seem from what you said it is. OK | Since it's a bit flag you're comparing bit values. It's misleading because "And" doesn't make sense until you know that. The values in binary are: 16: 00010000 17: 00010001 So 17 And 16 = 16 because that is the sum of the shared bits. By doing x And 16 you can check whether the 16 bit is set. It doesn't matter which other bits are or are not set. "And" is just a simple masking device. (If that doesn't make sense you might want to look up how decimal/hex/binary values express numbers and how that relates to bits.
From: LondonLad on 7 Aug 2010 10:28 Hi Mayayana Thank for your very clear explanation what would be the bit answer that is equal and allow code within the if statement to function. 'if the object is not a folder If (WFDSource.dwFileAttributes And FILE_ATTRIBUTE_DIRECTORY) <> FILE_ATTRIBUTE_DIRECTORY Then other code End if I thought that the author was making sure that it was a folder its seems to me that when it is a folder it still does not become equal and therefore does not satisfy the question. I would appreciate further help if you can. "Mayayana" wrote: > | Yes I will be the first to admit that i do not have any knowledge on bit > | operations but so far this has not stopped me from getting useful code to > | work to my requirements. I have read the article that Kevin Provance > | suggested at that has not helped me to understand the problem I have. > | As you said I had tried the prints to the intermediate window and I get > this > | result > | > | ? (17 and 16) <> 16 Result False > | ? (16 and 16) <> 16 Result False > | is this the correct answer? it seem from what you said it is. OK > | > > Since it's a bit flag you're comparing bit values. It's > misleading because "And" doesn't make sense > until you know that. The values in binary are: > > 16: 00010000 > 17: 00010001 > > So 17 And 16 = 16 because that is the sum of the shared > bits. By doing x And 16 you can check whether the 16 bit is > set. It doesn't matter which other bits are or are not set. "And" > is just a simple masking device. (If that doesn't make sense > you might want to look up how decimal/hex/binary values > express numbers and how that relates to bits. > > > > . >
From: Henning on 7 Aug 2010 14:35 OBS! 'if the object is *not* a folder /Henning "LondonLad" <LondonLad(a)discussions.microsoft.com> skrev i meddelandet news:68992D5B-C45F-47AF-9497-C7BE19587CB1(a)microsoft.com... > Hi Mayayana > Thank for your very clear explanation what would be the bit answer that is > equal and allow code within the if statement to function. > > 'if the object is not a folder > If (WFDSource.dwFileAttributes And FILE_ATTRIBUTE_DIRECTORY) <> > FILE_ATTRIBUTE_DIRECTORY Then > > other code > > End if > > I thought that the author was making sure that it was a folder its seems > to > me that when it is a folder it still does not become equal and therefore > does > not satisfy the question. > > I would appreciate further help if you can. > > "Mayayana" wrote: > >> | Yes I will be the first to admit that i do not have any knowledge on >> bit >> | operations but so far this has not stopped me from getting useful code >> to >> | work to my requirements. I have read the article that Kevin Provance >> | suggested at that has not helped me to understand the problem I have. >> | As you said I had tried the prints to the intermediate window and I get >> this >> | result >> | >> | ? (17 and 16) <> 16 Result False >> | ? (16 and 16) <> 16 Result False >> | is this the correct answer? it seem from what you said it is. OK >> | >> >> Since it's a bit flag you're comparing bit values. It's >> misleading because "And" doesn't make sense >> until you know that. The values in binary are: >> >> 16: 00010000 >> 17: 00010001 >> >> So 17 And 16 = 16 because that is the sum of the shared >> bits. By doing x And 16 you can check whether the 16 bit is >> set. It doesn't matter which other bits are or are not set. "And" >> is just a simple masking device. (If that doesn't make sense >> you might want to look up how decimal/hex/binary values >> express numbers and how that relates to bits. >> >> >> >> . >>
From: Henning on 7 Aug 2010 15:17 A little too fast, again... If you want If (WFD.....) to satisfy when it is a Dir, then change <> to =. /Henning "Henning" <computer_hero(a)coldmail.com> skrev i meddelandet news:i3k91o$s7a$1(a)news.eternal-september.org... > OBS! 'if the object is *not* a folder > > /Henning > > "LondonLad" <LondonLad(a)discussions.microsoft.com> skrev i meddelandet > news:68992D5B-C45F-47AF-9497-C7BE19587CB1(a)microsoft.com... >> Hi Mayayana >> Thank for your very clear explanation what would be the bit answer that >> is >> equal and allow code within the if statement to function. >> >> 'if the object is not a folder >> If (WFDSource.dwFileAttributes And FILE_ATTRIBUTE_DIRECTORY) <> >> FILE_ATTRIBUTE_DIRECTORY Then >> >> other code >> >> End if >> >> I thought that the author was making sure that it was a folder its seems >> to >> me that when it is a folder it still does not become equal and therefore >> does >> not satisfy the question. >> >> I would appreciate further help if you can. >> >> "Mayayana" wrote: >> >>> | Yes I will be the first to admit that i do not have any knowledge on >>> bit >>> | operations but so far this has not stopped me from getting useful code >>> to >>> | work to my requirements. I have read the article that Kevin Provance >>> | suggested at that has not helped me to understand the problem I have. >>> | As you said I had tried the prints to the intermediate window and I >>> get >>> this >>> | result >>> | >>> | ? (17 and 16) <> 16 Result False >>> | ? (16 and 16) <> 16 Result False >>> | is this the correct answer? it seem from what you said it is. OK >>> | >>> >>> Since it's a bit flag you're comparing bit values. It's >>> misleading because "And" doesn't make sense >>> until you know that. The values in binary are: >>> >>> 16: 00010000 >>> 17: 00010001 >>> >>> So 17 And 16 = 16 because that is the sum of the shared >>> bits. By doing x And 16 you can check whether the 16 bit is >>> set. It doesn't matter which other bits are or are not set. "And" >>> is just a simple masking device. (If that doesn't make sense >>> you might want to look up how decimal/hex/binary values >>> express numbers and how that relates to bits. >>> >>> >>> >>> . >>> > >
From: Larry Serflaten on 7 Aug 2010 15:22 "LondonLad" <LondonLad(a)discussions.microsoft.com> wrote > 'if the object is not a folder > If (WFDSource.dwFileAttributes And FILE_ATTRIBUTE_DIRECTORY) <> > FILE_ATTRIBUTE_DIRECTORY Then > > I thought that the author was making sure that it was a folder That code tests to see if the attributes say its NOT a folder. If (MyValue And SOMETEST) = SOMETEST Then ' The tested attribute is present If (MyValue And SOMETEST) <> SOMETEST Then ' The tested attribute is not present LFS
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