Makefile: set targets from a list
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From: Rui Maciel on 20 Mar 2010 16:08 Is it possible to define targets from a given list? For example, let's say that I have the following files: a.c++, a.h++ b.c++, b.h++ c.c++, c.h++ And let's say we have the following list defined in a makefile: LIST = a b c Is it possible to built the following targets from that list? a.o: a.c++ a.h++ gcc -c a.c++ -o a.o b.o: b.c++ b.h++ gcc -c b.c++ -o b.o c.o: c.c++ c.h++ gcc -c c.c++ -o c.o Thanks in advance, Rui Maciel
From: Pascal J. Bourguignon on 20 Mar 2010 17:26 Rui Maciel <rui.maciel(a)gmail.com> writes: > Is it possible to define targets from a given list? For example, let's say that I have the > following files: > > a.c++, a.h++ > b.c++, b.h++ > c.c++, c.h++ > > > And let's say we have the following list defined in a makefile: > > LIST = a b c > > Is it possible to built the following targets from that list? > > a.o: a.c++ a.h++ > gcc -c a.c++ -o a.o > > > b.o: b.c++ b.h++ > gcc -c b.c++ -o b.o > > > c.o: c.c++ c.h++ > gcc -c c.c++ -o c.o > Just write: %.o : %.c++ %.h++ gcc -c %.c++ -o %.o and have a target depending on the .o files you want: all : a.o b.o c.o From your LIST, I don't know if it's possible to derive with GNU make builtins a.o b.o c.o, but from: SOURCES=a.c++ b.c++ c.c++ or SOURCES=$(shell echo *.c++) you could build: OBJECTS=$(SOURCES:.c++=.o) and then just write: all:$(OBJECTS) To sum up: #------------------------------------ PGM=mypgm SOURCES=$(shell echo *.c++) LIBS=-lm # ... #------------------------------------ OBJECTS=$(SOURCES:.c++=.o) all : $(PGM) $(PGM) : $(OBJECTS) g++ -o $(PGM) $(OBJECTS) $(LIBS) %.o:%.c++ %.h++ g++ -c $< -o $@ clean: - rm -f *.o $(PGM) #------------------------------------ So, with only test.c++ and test.h++ in the directory with this Makefile you can type: make -k and have make execute: g++ -c test.c++ -o test.o g++ -o mypgm test.o -lm -- __Pascal Bourguignon__
From: Rui Maciel on 21 Mar 2010 09:41 Pascal J. Bourguignon wrote: > Rui Maciel <rui.maciel(a)gmail.com> writes: > >> Is it possible to define targets from a given list? For example, let's >> say that I have the following files: >> >> a.c++, a.h++ >> b.c++, b.h++ >> c.c++, c.h++ >> >> >> And let's say we have the following list defined in a makefile: >> >> LIST = a b c >> >> Is it possible to built the following targets from that list? >> >> a.o: a.c++ a.h++ >> gcc -c a.c++ -o a.o >> >> >> b.o: b.c++ b.h++ >> gcc -c b.c++ -o b.o >> >> >> c.o: c.c++ c.h++ >> gcc -c c.c++ -o c.o >> > > > Just write: > > %.o : %.c++ %.h++ > gcc -c %.c++ -o %.o > > > and have a target depending on the .o files you want: > > all : a.o b.o c.o > > > From your LIST, I don't know if it's possible to derive with GNU make > builtins a.o b.o c.o, but from: > > SOURCES=a.c++ b.c++ c.c++ > > or > > SOURCES=$(shell echo *.c++) > > you could build: > > OBJECTS=$(SOURCES:.c++=.o) > > and then just write: > > all:$(OBJECTS) > > > To sum up: > > #------------------------------------ > PGM=mypgm > SOURCES=$(shell echo *.c++) > LIBS=-lm # ... > #------------------------------------ > OBJECTS=$(SOURCES:.c++=.o) > all : $(PGM) > $(PGM) : $(OBJECTS) > g++ -o $(PGM) $(OBJECTS) $(LIBS) > %.o:%.c++ %.h++ > g++ -c $< -o $@ > clean: > - rm -f *.o $(PGM) > #------------------------------------ > > > So, with only test.c++ and test.h++ in the directory with this Makefile > you can type: > > make -k > > and have make execute: > > g++ -c test.c++ -o test.o > g++ -o mypgm test.o -lm I've tried it out and it appears that it works just as expected. Good stuff. Thanks for the help, Rui Maciel
From: Thad Smith on 28 Mar 2010 22:23
Rui Maciel wrote: > Pascal J. Bourguignon wrote: > >> Rui Maciel <rui.maciel(a)gmail.com> writes: >> >>> Is it possible to define targets from a given list? For example, let's >>> say that I have the following files: >>> >>> a.c++, a.h++ >>> b.c++, b.h++ >>> c.c++, c.h++ >>> >>> >>> And let's say we have the following list defined in a makefile: >>> >>> LIST = a b c >>> >>> Is it possible to built the following targets from that list? >>> >>> a.o: a.c++ a.h++ >>> gcc -c a.c++ -o a.o >>> >>> >>> b.o: b.c++ b.h++ >>> gcc -c b.c++ -o b.o >>> >>> >>> c.o: c.c++ c.h++ >>> gcc -c c.c++ -o c.o Yes, but does that express all the dependencies? Does b.o depend on a.h++, for example? -- Thad |