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This Week's Finds in Mathematical Physics (Week 280) Also available at http://math.ucr.edu/home/baez/week280.html September 27, 2009 This Week's Finds in Mathematical Physics (Week 280) John Baez I have a lot to talk about, since I just got back from a quantum gravity summer school in Corfu. I felt like Rip Van Winkle, the character who fell asleep for 20 ye... 28 Sep 2009 15:55
Fitch's Symbolic Logic format for Euclid's IP #152; 2nd ed; Euclid's.. 1) Definition of prime Haven't you found a definition of prime you can understand yet ? 2) Hypothetical assumption, suppose set of primes 2,3,5,7,.. is finite with P_k the last and final prime finite => last => final => finite hypothesis => assumption => hypothesis 3) Multiply the lot and add 1 (Eu... 27 Sep 2009 14:35
@ECHO OFF (TM) MEAMI.ORG @ECHO OFF ECHO Hello Universe! Copywrite(C) 2009 Martin Musatov. All rights reserved. PAUSE @\windows\ie7\iexplore.exe meami.org @"c:\program files\internet exploder\iexplore.exe 'http:// www.meami.org'"@open http:\\www.meami.org" #include <windows.h> void main (void) { ShellExecute (NULL, "open", "http://w... 22 Sep 2009 19:42
1(pi)/x,y,z = f X,Y/X,Ypi/t2*f X(x) (X,Y) = X and Y / Z once Z= 1pi 1978 - Fuckwit: Please don't post your "Special Ed. " homework here. ... 22 Sep 2009 19:42
zeta zero just for fun : what is the simplest way of proving that the first zero of zeta(s) on the critical line has indeed real part 1/2 ? ... 27 Sep 2009 16:47
Black Holes Are An Optical Effect Black holes are visual effects. They do not physically exist as if you were to approach one it would be the same as a heat mirage that looks like water. The 'black hole' would give way to par equal visual space and stars would be visual past and through it (or where it is seen to have been by the human brain). You ... 6 Oct 2009 03:23
product of tangents problem Leonard Wapner asked about the behaviour of a(n) = (tan 1)(tan 2) ... (tan n) in 2006: < http://groups.google.com/group/sci.math/msg/fa3878fa776a992b > . If n is very close to an odd multiple of pi/2, the tangent of n will be large in absolute value. One of the convergents in the continued fraction expansio... 25 Sep 2009 23:19
symmetric tensor dimension hi, How does one compute the dimension of a nth ranked symmetric tensor? ... 23 Sep 2009 14:27
N[(1/2)-k*(k-1/2)*(-3)/Factorial[k], 10000] Martin M. Musatov, 11/14/08, mmm(a)gmx.us N[(1/2)-k*(k-1/2)*(-3)/Factorial[k], 10000] 0.5000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000... 20 Sep 2009 09:35 |