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From: S. Masih on 27 Sep 2009 12:39
Hi,
when I transform my image into log scale, I face problems showing that image with the following error:
>> M=double(imread('Mammogram.jpeg'));
>> LogM=log(1/512+M);
>> imshow(LogM,[])
??? Error using ==> checkDisplayRange at 22
HIGH must be greater than LOW.

Error in ==> imageDisplayValidateParams at 57
common_args.DisplayRange = checkDisplayRange(common_args.DisplayRange,mfilename);

Error in ==> imageDisplayParseInputs at 79
common_args = imageDisplayValidateParams(common_args);

Error in ==> imshow at 199
[common_args,specific_args] = ...

How can I solve this problem?
Thanks for your attention
From: Ishtiaq Ahmad on 19 Oct 2009 03:11
Convert image1 in to double by
"image1=double(image1)" then take log i.e.
s(i,j)=log(image1(i,j))

Chears



lekosmoth(a)yahoo.com wrote in message <1189968464.304874.39280(a)w3g2000hsg.googlegroups.com>...
> Hi,
>
> I am trying to get a log value for an image. This is what I have done
> so far...
>
> image1=imread(image.jpg)
> [m,n]=size(image1)
>
> for j=1:n
> for i=1:m
>
> s(i,j)=log(image1(i,j))
>
> end
> end
>
> When i do this I get an error msg saying 'log' is not defined for
> values of class 'uint8'. How can I correct this.
>
> Thanks,
> LS
>
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