From: JEMebius on
Kaba wrote:
> Ron wrote:
>> On Jun 5, 7:23 am, Kaba <n...(a)here.com> wrote:
>>> Stephen Montgomery-Smith wrote:
>>>> Kaba wrote:
>>>>> Hi,
>>>>> This is part of the first question for chapter 1 of "Applied numerical
>>>>> linear algebra" book, but I just can't come up with a solution:
>>>>> If A and B are orthogonal matrices, and det(A) = -det(B), show that
>>>>> A + B is singular.
>>>>> Any hints?
>>>> Here is my attempt. If A is orthogonal, then the determinant is either
>>>> 1 or minus 1. WLOG det(A) = 1. Now
>>>> A+B = A(I + A^{-1} B)
>>>> so WLOG A=I, and B is an orthogonal matrix whose determinant is -1.
>>> Could you be more specific why WLOG here?
>>>
>> I suspect the idea is this. A is invertible so A+B is singular if and
>> only if I+A^{-1}B is singular. So we simply consider the case where
>> A=I and B is an orthogonal matrix of determinant -1. The argument is
>> essentially the same as the earlier one using the fact that an
>> orthogonal matrix of determinant -1 has -1 as an eigenvalue.
>
> Ok, I see, it works:)
>


Typesetting tip: A^-1 instaed of A^(-1)

The Thunderbird EMail/Newsgroup program interprets "^" (caret) as exponentiation.
I guess all such programs do so.

The string following "^" is converted to superscript as far as it looks like a number,
positive or negative, integer or non-integer.

My guess: any character other than 0 1 2 3 4 5 6 7 8 9 + - . stops the superscript mode.

Check: A^0, A^+1, A^1, A^+1.2345, A^1.2345, A^-6, A^-6.7890, A^.5, A^-.5

Johan E. Mebius