Matrix generation
in [Matlab]
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From: Martin on 26 Jun 2010 11:16 "us " <us(a)neurol.unizh.ch> wrote in message <i04v41$l8e$1(a)fred.mathworks.com>... > "Martin " > > It did not work. > > > > B=[ > > 9 5 > > 23 4 > > 66 7 > > 75 2 > > ]; > > A=zeros(10); > > A(B(:,1)=B(:,2); > > ??? A(B(:,1)=B(:,2); > > | > > Error: The expression to the left of the equals sign is not a valid target for an assignment. > > > > well... of course... > you made a typo > > A(B(:,1) > % must read > A(B(:,1)) > % as shown in the original solution... > > us I was wondering how I could automate this task. I have 1000 files like file B (tot_000.dat, tot_001.dat, and so forth). What would be a simple way to load each file, do the matrix creation, and output it to a new file? Thank You!
From: us on 26 Jun 2010 13:08 "Martin " > I was wondering how I could automate this task. I have 1000 files like file B (tot_000.dat, tot_001.dat, and so forth). What would be a simple way to load each file, do the matrix creation, and output it to a new file? Thank You! a hint: http://matlabwiki.mathworks.com/MATLAB_FAQ#How_can_I_process_a_sequence_of_files.3F us
From: Martin on 26 Jun 2010 17:50 I did for k=1:9 load(sprintf('/data/tot_00%d.dat',k)); end which worked. Once I increase the number of files k above 9, I have problems. The file names are tot_001 through tot_999. How do I format the tot_%d so I can read 001 through 999? Thank You. "us " <us(a)neurol.unizh.ch> wrote in message <i05c5k$c67$1(a)fred.mathworks.com>... > "Martin " > > I was wondering how I could automate this task. I have 1000 files like file B (tot_000.dat, tot_001.dat, and so forth). What would be a simple way to load each file, do the matrix creation, and output it to a new file? Thank You! > > a hint: > > http://matlabwiki.mathworks.com/MATLAB_FAQ#How_can_I_process_a_sequence_of_files.3F > > us
From: us on 26 Jun 2010 18:02 "Martin " <nikolom(a)gmail.com> wrote in message <i05smu$8f8$1(a)fred.mathworks.com>... > I did > > for k=1:9 > load(sprintf('/data/tot_00%d.dat',k)); > end > > which worked. Once I increase the number of files k above 9, I have problems. The file names are tot_001 through tot_999. How do I format the tot_%d so I can read 001 through 999? > > Thank You. one of the solutions for i=0:50:150 fnam=sprintf('file_%3.3d',i); disp(fnam); end %{ file_000 file_050 file_100 file_150 %} % for more on formatting, see help fprintf; us
From: Martin on 26 Jun 2010 18:18
I think I have figured out how to read all 999 files. I can process them in a do loop. The final step is to figure out how to automate generating 999 files containing the output. My input file names are tot_001 through tot_999. After I generate the output (a square matrix), how do I assign each output to file names Y_001 through Y_999? Thank You! "Martin " <nikolom(a)gmail.com> wrote in message <i05smu$8f8$1(a)fred.mathworks.com>... > I did > > for k=1:9 > load(sprintf('/data/tot_00%d.dat',k)); > end > > which worked. Once I increase the number of files k above 9, I have problems. The file names are tot_001 through tot_999. How do I format the tot_%d so I can read 001 through 999? > > Thank You. > > > > "us " <us(a)neurol.unizh.ch> wrote in message <i05c5k$c67$1(a)fred.mathworks.com>... > > "Martin " > > > I was wondering how I could automate this task. I have 1000 files like file B (tot_000.dat, tot_001.dat, and so forth). What would be a simple way to load each file, do the matrix creation, and output it to a new file? Thank You! > > > > a hint: > > > > http://matlabwiki.mathworks.com/MATLAB_FAQ#How_can_I_process_a_sequence_of_files.3F > > > > us |