Modern Space Time.
in [Relativity]
|
From: BURT on 15 Apr 2010 22:17 On Apr 15, 7:08 pm, "Ken S. Tucker" <dynam...(a)vianet.on.ca> wrote: > On Apr 15, 12:51 pm, BURT <macromi...(a)yahoo.com> wrote: > > > > > > > On Apr 15, 9:44 am, "Ken S. Tucker" <dynam...(a)vianet.on.ca> wrote: > > > > On Apr 15, 7:35 am, "Ken S. Tucker" <dynam...(a)vianet.on.ca> wrote: > > > > > Hello Gents. > > > > > On Apr 14, 6:22 pm, rods <rodpi...(a)gmail.com> wrote: > > > > > > > Since you are working with right-angled triangles, you are doing > > > > > > trigonometry. > > > > > > Let b/c = sin x; then c/a = cos x and you have just derived > > > > > > sec x = 1 / sqrt(1 - sin^2 x) = 1 / cos x. > > > > > > I'm not sure why you think is is useful. > > > > > > --John Park > > > > > > Yes. That's it. I think it is useful because this is the Lorentz > > > > > transformation. > > > > > Take a look at Minkowski approach to the Lorentz transformation on > > > > > page 35 of this paper:http://www.univ-nancy2.fr/DepPhilo/walter/papers/einstd7.pdf. > > > > > regards, > > > > > Rodrigo > > > > > We live in Canada, our Baud rate is measured in seconds/byte, > > > > i.e. we're on dial-up, so I didn't download the big pdf. > > > > > Space & Time were redefined by international concensus formally in > > > > 1983, > > > > to produce Modern SpaceTime. > > > > The triangle geometry trig approach is a useful teaching tool, but > > > > it's nearly > > > > useless in GR. > > > > Some theoreticians still commonly use the old (1, -1,-1,-1) signature > > > > as > > > > a kind of gospel, although a transform to (1,1,1,1) has advantages. > > > > > We produced a brief (2 pages) on how to use MST in GR metrically, > > > > >http://physics.trak4.com/modern-spacetime.pdf > > > > > We went on to insure MST was compatible with all physics in a few > > > > briefs you can find here, > > > > >http://physics.trak4.com/ > > > > > I recommend a formal algebraic approach as set forth by GR. > > > > Regards > > > > Ken S. Tucker > > > > On Apr 15, 9:49 am, "Ken S. Tucker" <dynam...(a)vianet.on.ca> wrote: > > > > > Hello Gents. > > > > > On Apr 14, 6:22 pm, rods <rodpi...(a)gmail.com> wrote: > > > > > > > Since you are working with right-angled triangles, you are doing > > > > > > trigonometry. > > > > > > Let b/c = sin x; then c/a = cos x and you have just derived > > > > > > sec x = 1 / sqrt(1 - sin^2 x) = 1 / cos x. > > > > > > I'm not sure why you think is is useful. > > > > > > --John Park > > > > > > Yes. That's it. I think it is useful because this is the Lorentz > > > > > transformation. > > > > > Take a look at Minkowski approach to the Lorentz transformation on > > > > > page 35 of this paper:http://www.univ-nancy2.fr/DepPhilo/walter/papers/einstd7.pdf. > > > > > regards, > > > > > Rodrigo > > > > > We live in Canada, our Baud rate is measured in seconds/byte, > > > > i.e. we're on dial-up, so I didn't download the big pdf. > > > > > Space & Time were redefined by international concensus formally in > > > > 1983, > > > > to produce Modern SpaceTime. > > > > The triangle geometry trig approach is a useful teaching tool, but > > > > it's nearly > > > > useless in GR. > > > > Some theoreticians still commonly use the old (1, -1,-1,-1) signature > > > > as > > > > a kind of gospel, although a transform to (1,1,1,1) has advantages. > > > > > We produced a brief (2 pages) on how to use MST in GR metrically, > > > > >http://physics.trak4.com/modern-spacetime.pdf > > > > > We went on to insure MST was compatible with all physics in a few > > > > briefs you can find here, > > > > >http://physics.trak4.com/ > > > > > I recommend a formal algebraic approach as set forth by GR. > > > > Regards > > > > Ken S. Tucker > > > > I'd like to add that GR, in my experience, provides a very versatile > > > ability, using the logic of tensor analysis, to solve SpaceTime by > > > algebraic means, and the MST solution I posted was just one. > > > > In mathematical physics using tensor calculus logic, I refrain from > > > the outset of any coordinate systems conditions, such as metric > > > signatures as that practically cancels the purpose of tensor calculus, > > > I may sound nutsy, but I calculate in tensors with the indice being a > > > variable, to enable fractional dimensionality, and also operate in an > > > undefined number of dimensions. > > > > Afterward specialize to 4D (x,y,z,t) to obtain the prediction, > > > that can be communicated. > > > Regards > > > Ken S. Tucker > > Space time aether has a spherical geometry. Gravity is radial and > > inward immaterial flow straight to center. > > Mitch Raemsch > > You also need to consider gravitation reacting between two > fast moving objects, then how that should be solved. > Ken- Hide quoted text - > > - Show quoted text - The gravitational field moves equally with its mass center. Mitch Raemsch
From: xxein on 16 Apr 2010 23:36 On Apr 15, 10:08 pm, "Ken S. Tucker" <dynam...(a)vianet.on.ca> wrote: > On Apr 15, 12:51 pm, BURT <macromi...(a)yahoo.com> wrote: > > > > > > > On Apr 15, 9:44 am, "Ken S. Tucker" <dynam...(a)vianet.on.ca> wrote: > > > > On Apr 15, 7:35 am, "Ken S. Tucker" <dynam...(a)vianet.on.ca> wrote: > > > > > Hello Gents. > > > > > On Apr 14, 6:22 pm, rods <rodpi...(a)gmail.com> wrote: > > > > > > > Since you are working with right-angled triangles, you are doing > > > > > > trigonometry. > > > > > > Let b/c = sin x; then c/a = cos x and you have just derived > > > > > > sec x = 1 / sqrt(1 - sin^2 x) = 1 / cos x. > > > > > > I'm not sure why you think is is useful. > > > > > > --John Park > > > > > > Yes. That's it. I think it is useful because this is the Lorentz > > > > > transformation. > > > > > Take a look at Minkowski approach to the Lorentz transformation on > > > > > page 35 of this paper:http://www.univ-nancy2.fr/DepPhilo/walter/papers/einstd7.pdf. > > > > > regards, > > > > > Rodrigo > > > > > We live in Canada, our Baud rate is measured in seconds/byte, > > > > i.e. we're on dial-up, so I didn't download the big pdf. > > > > > Space & Time were redefined by international concensus formally in > > > > 1983, > > > > to produce Modern SpaceTime. > > > > The triangle geometry trig approach is a useful teaching tool, but > > > > it's nearly > > > > useless in GR. > > > > Some theoreticians still commonly use the old (1, -1,-1,-1) signature > > > > as > > > > a kind of gospel, although a transform to (1,1,1,1) has advantages. > > > > > We produced a brief (2 pages) on how to use MST in GR metrically, > > > > >http://physics.trak4.com/modern-spacetime.pdf > > > > > We went on to insure MST was compatible with all physics in a few > > > > briefs you can find here, > > > > >http://physics.trak4.com/ > > > > > I recommend a formal algebraic approach as set forth by GR. > > > > Regards > > > > Ken S. Tucker > > > > On Apr 15, 9:49 am, "Ken S. Tucker" <dynam...(a)vianet.on.ca> wrote: > > > > > Hello Gents. > > > > > On Apr 14, 6:22 pm, rods <rodpi...(a)gmail.com> wrote: > > > > > > > Since you are working with right-angled triangles, you are doing > > > > > > trigonometry. > > > > > > Let b/c = sin x; then c/a = cos x and you have just derived > > > > > > sec x = 1 / sqrt(1 - sin^2 x) = 1 / cos x. > > > > > > I'm not sure why you think is is useful. > > > > > > --John Park > > > > > > Yes. That's it. I think it is useful because this is the Lorentz > > > > > transformation. > > > > > Take a look at Minkowski approach to the Lorentz transformation on > > > > > page 35 of this paper:http://www.univ-nancy2.fr/DepPhilo/walter/papers/einstd7.pdf. > > > > > regards, > > > > > Rodrigo > > > > > We live in Canada, our Baud rate is measured in seconds/byte, > > > > i.e. we're on dial-up, so I didn't download the big pdf. > > > > > Space & Time were redefined by international concensus formally in > > > > 1983, > > > > to produce Modern SpaceTime. > > > > The triangle geometry trig approach is a useful teaching tool, but > > > > it's nearly > > > > useless in GR. > > > > Some theoreticians still commonly use the old (1, -1,-1,-1) signature > > > > as > > > > a kind of gospel, although a transform to (1,1,1,1) has advantages. > > > > > We produced a brief (2 pages) on how to use MST in GR metrically, > > > > >http://physics.trak4.com/modern-spacetime.pdf > > > > > We went on to insure MST was compatible with all physics in a few > > > > briefs you can find here, > > > > >http://physics.trak4.com/ > > > > > I recommend a formal algebraic approach as set forth by GR. > > > > Regards > > > > Ken S. Tucker > > > > I'd like to add that GR, in my experience, provides a very versatile > > > ability, using the logic of tensor analysis, to solve SpaceTime by > > > algebraic means, and the MST solution I posted was just one. > > > > In mathematical physics using tensor calculus logic, I refrain from > > > the outset of any coordinate systems conditions, such as metric > > > signatures as that practically cancels the purpose of tensor calculus, > > > I may sound nutsy, but I calculate in tensors with the indice being a > > > variable, to enable fractional dimensionality, and also operate in an > > > undefined number of dimensions. > > > > Afterward specialize to 4D (x,y,z,t) to obtain the prediction, > > > that can be communicated. > > > Regards > > > Ken S. Tucker > > Space time aether has a spherical geometry. Gravity is radial and > > inward immaterial flow straight to center. > > Mitch Raemsch > > You also need to consider gravitation reacting between two > fast moving objects, then how that should be solved. > Ken- Hide quoted text - > > - Show quoted text - xxein: Do you think you can talk at imbiciles better than I can?
From: BURT on 16 Apr 2010 23:55
On Apr 16, 8:36 pm, xxein <xx...(a)comcast.net> wrote: > On Apr 15, 10:08 pm, "Ken S. Tucker" <dynam...(a)vianet.on.ca> wrote: > > > > > > > On Apr 15, 12:51 pm, BURT <macromi...(a)yahoo.com> wrote: > > > > On Apr 15, 9:44 am, "Ken S. Tucker" <dynam...(a)vianet.on.ca> wrote: > > > > > On Apr 15, 7:35 am, "Ken S. Tucker" <dynam...(a)vianet.on.ca> wrote: > > > > > > Hello Gents. > > > > > > On Apr 14, 6:22 pm, rods <rodpi...(a)gmail.com> wrote: > > > > > > > > Since you are working with right-angled triangles, you are doing > > > > > > > trigonometry. > > > > > > > Let b/c = sin x; then c/a = cos x and you have just derived > > > > > > > sec x = 1 / sqrt(1 - sin^2 x) = 1 / cos x. > > > > > > > I'm not sure why you think is is useful. > > > > > > > --John Park > > > > > > > Yes. That's it. I think it is useful because this is the Lorentz > > > > > > transformation. > > > > > > Take a look at Minkowski approach to the Lorentz transformation on > > > > > > page 35 of this paper:http://www.univ-nancy2.fr/DepPhilo/walter/papers/einstd7.pdf. > > > > > > regards, > > > > > > Rodrigo > > > > > > We live in Canada, our Baud rate is measured in seconds/byte, > > > > > i.e. we're on dial-up, so I didn't download the big pdf. > > > > > > Space & Time were redefined by international concensus formally in > > > > > 1983, > > > > > to produce Modern SpaceTime. > > > > > The triangle geometry trig approach is a useful teaching tool, but > > > > > it's nearly > > > > > useless in GR. > > > > > Some theoreticians still commonly use the old (1, -1,-1,-1) signature > > > > > as > > > > > a kind of gospel, although a transform to (1,1,1,1) has advantages. > > > > > > We produced a brief (2 pages) on how to use MST in GR metrically, > > > > > >http://physics.trak4.com/modern-spacetime.pdf > > > > > > We went on to insure MST was compatible with all physics in a few > > > > > briefs you can find here, > > > > > >http://physics.trak4.com/ > > > > > > I recommend a formal algebraic approach as set forth by GR. > > > > > Regards > > > > > Ken S. Tucker > > > > > On Apr 15, 9:49 am, "Ken S. Tucker" <dynam...(a)vianet.on.ca> wrote: > > > > > > Hello Gents. > > > > > > On Apr 14, 6:22 pm, rods <rodpi...(a)gmail.com> wrote: > > > > > > > > Since you are working with right-angled triangles, you are doing > > > > > > > trigonometry. > > > > > > > Let b/c = sin x; then c/a = cos x and you have just derived > > > > > > > sec x = 1 / sqrt(1 - sin^2 x) = 1 / cos x. > > > > > > > I'm not sure why you think is is useful. > > > > > > > --John Park > > > > > > > Yes. That's it. I think it is useful because this is the Lorentz > > > > > > transformation. > > > > > > Take a look at Minkowski approach to the Lorentz transformation on > > > > > > page 35 of this paper:http://www.univ-nancy2.fr/DepPhilo/walter/papers/einstd7.pdf. > > > > > > regards, > > > > > > Rodrigo > > > > > > We live in Canada, our Baud rate is measured in seconds/byte, > > > > > i.e. we're on dial-up, so I didn't download the big pdf. > > > > > > Space & Time were redefined by international concensus formally in > > > > > 1983, > > > > > to produce Modern SpaceTime. > > > > > The triangle geometry trig approach is a useful teaching tool, but > > > > > it's nearly > > > > > useless in GR. > > > > > Some theoreticians still commonly use the old (1, -1,-1,-1) signature > > > > > as > > > > > a kind of gospel, although a transform to (1,1,1,1) has advantages. > > > > > > We produced a brief (2 pages) on how to use MST in GR metrically, > > > > > >http://physics.trak4.com/modern-spacetime.pdf > > > > > > We went on to insure MST was compatible with all physics in a few > > > > > briefs you can find here, > > > > > >http://physics.trak4.com/ > > > > > > I recommend a formal algebraic approach as set forth by GR. > > > > > Regards > > > > > Ken S. Tucker > > > > > I'd like to add that GR, in my experience, provides a very versatile > > > > ability, using the logic of tensor analysis, to solve SpaceTime by > > > > algebraic means, and the MST solution I posted was just one. > > > > > In mathematical physics using tensor calculus logic, I refrain from > > > > the outset of any coordinate systems conditions, such as metric > > > > signatures as that practically cancels the purpose of tensor calculus, > > > > I may sound nutsy, but I calculate in tensors with the indice being a > > > > variable, to enable fractional dimensionality, and also operate in an > > > > undefined number of dimensions. > > > > > Afterward specialize to 4D (x,y,z,t) to obtain the prediction, > > > > that can be communicated. > > > > Regards > > > > Ken S. Tucker > > > Space time aether has a spherical geometry. Gravity is radial and > > > inward immaterial flow straight to center. > > > Mitch Raemsch > > > You also need to consider gravitation reacting between two > > fast moving objects, then how that should be solved. > > Ken- Hide quoted text - > > > - Show quoted text - > > xxein: Do you think you can talk at imbiciles better than I can?- Hide quoted text - > > - Show quoted text - You impress me!! Mitch Raemsch |