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From: Ben Bacarisse on 18 Apr 2010 13:03
"Dr. David Kirkby" <david.kirkby(a)onetel.net> writes:

> On Apr 14, 6:17 pm, Seebs <usenet-nos...(a)seebs.net> wrote:
>> On 2010-04-14, pk <p...(a)pk.invalid> wrote:
>>
>> > IIUC, shouldn't it be more like
>>
>> > awk -v points=3 -f thisfile.awk:
>>
>> > { a[NR % points] = $1;
>> >   if(NR>=points) {
>> >     total = 0;
>> >     for (i = 0; i < points; ++i) { total = total + a[i]; }
>> >     print (total / points);
>> >   }
>> > }
>>
>> Maybe!  A lot of people don't have a clear definition of what they mean
>> by a "moving average", I just figured I'd illustrate the simplest case...
<snip>
>
> Thank you for that. It works perfectly. In my case, the number of data
> points is much greater than the likely number of points I want to
> average over, so extra test added is not strictly necessary.

Probably too late, but there is something unsettling about adding up the
total every time. I'd write it like this:

{ total += $1 - a[NR % points]; a[NR % points] = $1 }
NR >= points { print total / points }

--
Ben.
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