Newton's law of gravitational attraction
in [Relativity]
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From: Jonah Thomas on 13 Oct 2009 12:06 NoEinstein <noeinstein(a)bellsouth.net> wrote: > Dear Dougie Boy, the leech: Not a soul in the world cares about having > your... 'respect'. Mentally, you are a NON entity. NE It's an unmoderated newsgroup and you have the right to post as you see fit. But that was unkind.
From: NoEinstein on 13 Oct 2009 12:08 On Oct 13, 11:29 am, PD <thedraperfam...(a)gmail.com> wrote: > PD: You are off-your-rocker. Go into a small room and talk to yourself. No one with half a brain reads your replies. I only scan down to your first foot-in-the-mouth nonsense. NE > > On Oct 12, 7:32 pm, NoEinstein <noeinst...(a)bellsouth.net> wrote: > > > On Oct 10, 11:28 am, PD <thedraperfam...(a)gmail.com> wrote: > > > Dear Side-Stepping PD, the Parasite Dunce: WORK is NOT the same as > > KE! > > The contribution to the energy that changes KE is called work. Please > consult your 7th grade science book. > > > Distance of fall always includes a COASTING component. If the > > fall distance in one second, 16.087 feet, is taken as a datum and > > called 'd', the coasting distances (hidden) within the parabolic time > > vs. distance curve are as follows: Second 1, coasting distance 'zero'; > > Second 2, coasting distance 2d; Second 3, coasting distance 4d; and > > Second 4, coasting distance, 6d. The distances 'left' over are > > increasing one 'd', or 16.087 feet, each secondand that is a LINEAR > > increase in NON COASTING distance of fall, consistent with KE being a > > LINEARELY increasing quantity. > > Sorry, but no. The contribution to energy as it increases each second > is the product of a force times the distance covered in that second. > This is known by every 7th grader but it still seems to elude you. Why > didn't you ask a question about this in the 7th grade? > > > > > It would be possible to convert KE to useful work done at impact or > > slow-down. But such would be a tacked-on, different physics problem > > concerned with the weight of the object(s) impacted. Knowing you, you > > will weasel out by insisting that the discussion be on work, not KE. > > Like I've told you, the existing definition of work is the only > > correct term in the chapters on mechanics, > > Good, and then you'll also notice right next to the definition of work > something called the Work-Energy theorem. > > > > > which I have otherwise > > correctly re written for the benefit of science. NoEinstein > > > > On Oct 10, 10:21 am, NoEinstein <noeinst...(a)bellsouth.net> wrote: > > > > > On Oct 8, 1:01 pm, PD <thedraperfam...(a)gmail.com> wrote: > > > > > Dear PD, the Parasite Dunce: An object's "distance of fall" isn't an > > > > "energy" component! > > > > Of course it is. Please consult on the definition of work, which is > > > how a force makes an energy contribution. > > > This contribution is the force times the distance the force acts > > > through. > > > The distance is indeed a factor in the energy contribution. > > > > I'm astounded -- ASTOUNDED, I tell you! -- that you have forgotten > > > this basic fact that 7th graders know. > > > It is in fact the basis for the playground see-saw, not to mention the > > > block-and-tackle pulley system. > > > > > The only force acting on a dropped object is the > > > > uniform (per unit weight) force of gravity. An object in space that > > > > is traveling 1,000 miles per hour, after traveling 1,000 miles, will > > > > impact with the identical KE as a like-size object that traveled one > > > > million miles at 1,000 miles per hour. > > > > But if it is traveling at a constant 1000 miles per hour, then there > > > is obviously no force acting on the object. > > > If there were a force acting on it, it would continue to accelerate. > > > Since there is no force acting on it, then there is no contribution to > > > the energy whether it is traveling a thousand miles or a million > > > miles. > > > > If you want to know how a force contributes to the energy, then > > > consider cases where the force is present. Looking at cases where > > > there is no force acting on the object any more will not help you > > > understand the basics. > > > > > Distance of travel has NO > > > > direct influence on the object's KE. Try to get that through your > > > > hard head! Noeinstein > > > > I'm sorry, NoEinstein, but this is REALLY basic, 7th grade stuff. > > > Nobody that failed to learn the material from the 7th grade should be > > > allowed to be licensed as an architect, in my opinion. > > > > > > On Oct 8, 10:46 am, NoEinstein <noeinst...(a)bellsouth.net> wrote: > > > > > > > On Oct 7, 7:48 pm, PD <thedraperfam...(a)gmail.com> wrote: > > > > > > > Dear PD, the Parasite Dunce: The INPUT energy is the UNIFORM force of > > > > > > gravity. > > > > > > No sir. The input energy is the PRODUCT of the force of gravity and > > > > > the distance the force acts through. > > > > > This is a simple fact, verified by experiment. > > > > > And as an object falls, though the force is uniform, the distance per > > > > > second increases each second, and so the product is not uniform though > > > > > the force is uniform. > > > > > I've explained this to you a half-dozen times, and you still don't > > > > > seem to understand this. Do you have a reading comprehension problem? > > > > > > > To have the "output" KE be the square of the time, > > > > > > immediately, violates the LAW OF THE CONSERVATION OF ENERGY: energy IN > > > > > > must = energy OUT! NoEinstein > > > > > > Sorry, no, the INPUT energy is also increasing as the square of time, > > > > > as I've explained several times. Energy is conserved.- Hide quoted text - > > > > - Show quoted text -- Hide quoted text - > > - Show quoted text -
From: David Bostwick on 13 Oct 2009 12:31 In article <20091013120625.16d7a065.jethomas5(a)gmail.com>, Jonah Thomas <jethomas5(a)gmail.com> wrote: >NoEinstein <noeinstein(a)bellsouth.net> wrote: > >> Dear Dougie Boy, the leech: Not a soul in the world cares about having >> your... 'respect'. Mentally, you are a NON entity. =97 NE =97 > >It's an unmoderated newsgroup and you have the right to post as you see >fit. > >But that was unkind. Killfiles can be your friend.
From: PD on 13 Oct 2009 12:37 On Oct 13, 11:08 am, NoEinstein <noeinst...(a)bellsouth.net> wrote: > On Oct 13, 11:29 am, PD <thedraperfam...(a)gmail.com> wrote: > > PD: You are off-your-rocker. Go into a small room and talk to > yourself. No one with half a brain reads your replies. I only scan > down to your first foot-in-the-mouth nonsense. NE Interesting how you project that "no one" reads my replies. How do you know? Is this from the same pool of information that tells you that intelligent readers agree with your posts, even though there is not a one that has come out and said that? As for what you read of my replies, I'm not surprised. You're not here to have a conversation about anything. You're here to hear yourself talk. And you take pride in the fact (and consider it an accomplishment) to do so on an unmoderated newsgroup. While you're at it, congratulate yourself for breathing without help today. > > > > > On Oct 12, 7:32 pm, NoEinstein <noeinst...(a)bellsouth.net> wrote: > > > > On Oct 10, 11:28 am, PD <thedraperfam...(a)gmail.com> wrote: > > > > Dear Side-Stepping PD, the Parasite Dunce: WORK is NOT the same as > > > KE! > > > The contribution to the energy that changes KE is called work. Please > > consult your 7th grade science book. > > > > Distance of fall always includes a COASTING component. If the > > > fall distance in one second, 16.087 feet, is taken as a datum and > > > called 'd', the coasting distances (hidden) within the parabolic time > > > vs. distance curve are as follows: Second 1, coasting distance 'zero'; > > > Second 2, coasting distance 2d; Second 3, coasting distance 4d; and > > > Second 4, coasting distance, 6d. The distances 'left' over are > > > increasing one 'd', or 16.087 feet, each secondand that is a LINEAR > > > increase in NON COASTING distance of fall, consistent with KE being a > > > LINEARELY increasing quantity. > > > Sorry, but no. The contribution to energy as it increases each second > > is the product of a force times the distance covered in that second. > > This is known by every 7th grader but it still seems to elude you. Why > > didn't you ask a question about this in the 7th grade? > > > > It would be possible to convert KE to useful work done at impact or > > > slow-down. But such would be a tacked-on, different physics problem > > > concerned with the weight of the object(s) impacted. Knowing you, you > > > will weasel out by insisting that the discussion be on work, not KE. > > > Like I've told you, the existing definition of work is the only > > > correct term in the chapters on mechanics, > > > Good, and then you'll also notice right next to the definition of work > > something called the Work-Energy theorem. > > > > which I have otherwise > > > correctly re written for the benefit of science. NoEinstein > > > > > On Oct 10, 10:21 am, NoEinstein <noeinst...(a)bellsouth.net> wrote: > > > > > > On Oct 8, 1:01 pm, PD <thedraperfam...(a)gmail.com> wrote: > > > > > > Dear PD, the Parasite Dunce: An object's "distance of fall" isn't an > > > > > "energy" component! > > > > > Of course it is. Please consult on the definition of work, which is > > > > how a force makes an energy contribution. > > > > This contribution is the force times the distance the force acts > > > > through. > > > > The distance is indeed a factor in the energy contribution. > > > > > I'm astounded -- ASTOUNDED, I tell you! -- that you have forgotten > > > > this basic fact that 7th graders know. > > > > It is in fact the basis for the playground see-saw, not to mention the > > > > block-and-tackle pulley system. > > > > > > The only force acting on a dropped object is the > > > > > uniform (per unit weight) force of gravity. An object in space that > > > > > is traveling 1,000 miles per hour, after traveling 1,000 miles, will > > > > > impact with the identical KE as a like-size object that traveled one > > > > > million miles at 1,000 miles per hour. > > > > > But if it is traveling at a constant 1000 miles per hour, then there > > > > is obviously no force acting on the object. > > > > If there were a force acting on it, it would continue to accelerate.. > > > > Since there is no force acting on it, then there is no contribution to > > > > the energy whether it is traveling a thousand miles or a million > > > > miles. > > > > > If you want to know how a force contributes to the energy, then > > > > consider cases where the force is present. Looking at cases where > > > > there is no force acting on the object any more will not help you > > > > understand the basics. > > > > > > Distance of travel has NO > > > > > direct influence on the object's KE. Try to get that through your > > > > > hard head! Noeinstein > > > > > I'm sorry, NoEinstein, but this is REALLY basic, 7th grade stuff. > > > > Nobody that failed to learn the material from the 7th grade should be > > > > allowed to be licensed as an architect, in my opinion. > > > > > > > On Oct 8, 10:46 am, NoEinstein <noeinst...(a)bellsouth.net> wrote: > > > > > > > > On Oct 7, 7:48 pm, PD <thedraperfam...(a)gmail.com> wrote: > > > > > > > > Dear PD, the Parasite Dunce: The INPUT energy is the UNIFORM force of > > > > > > > gravity. > > > > > > > No sir. The input energy is the PRODUCT of the force of gravity and > > > > > > the distance the force acts through. > > > > > > This is a simple fact, verified by experiment. > > > > > > And as an object falls, though the force is uniform, the distance per > > > > > > second increases each second, and so the product is not uniform though > > > > > > the force is uniform. > > > > > > I've explained this to you a half-dozen times, and you still don't > > > > > > seem to understand this. Do you have a reading comprehension problem? > > > > > > > > To have the "output" KE be the square of the time, > > > > > > > immediately, violates the LAW OF THE CONSERVATION OF ENERGY: energy IN > > > > > > > must = energy OUT! NoEinstein > > > > > > > Sorry, no, the INPUT energy is also increasing as the square of time, > > > > > > as I've explained several times. Energy is conserved.- Hide quoted text - > > > > > - Show quoted text -- Hide quoted text - > > > - Show quoted text -
From: doug on 13 Oct 2009 14:03
NoEinstein wrote: > On Oct 13, 12:13 am, doug <x...(a)xx.com> wrote: > > Dougie Boy, the leech, is a brainless android programmed to be the > anti-thesis of science truths. � NE � I notice you are unable to defend your nonsense. > >>NoEinstein wrote: >> >>>On Oct 10, 11:28 am, PD <thedraperfam...(a)gmail.com> wrote: >> >>>Dear Side-Stepping PD, the Parasite Dunce: WORK is NOT the same as >>>KE! >> >>Wrong again john. >> >> Distance of fall always includes a COASTING component. >> >>Wrong again john. >> >>If the >> >> >>>fall distance in one second, 16.087 feet, is taken as a datum and >>>called 'd', the coasting distances (hidden) within the parabolic time >>>vs. distance curve are as follows: Second 1, coasting distance 'zero'; >>>Second 2, coasting distance 2d; Second 3, coasting distance 4d; and >>>Second 4, coasting distance, 6d. The distances 'left' over are >>>increasing one 'd', or 16.087 feet, each second�and that is a LINEAR >>>increase in NON COASTING distance of fall, consistent with KE being a >>>LINEARELY increasing quantity. >> >>Wrong again john. >> >> >> >> >>>It would be possible to convert KE to useful work done at impact or >>>slow-down. But such would be a tacked-on, different physics problem >>>concerned with the weight of the object(s) impacted. Knowing you, you >>>will weasel out by insisting that the discussion be on work, not KE. >> >>More stupidity john. >> >> >>>Like I've told you, the existing definition of work is the only >>>correct term in the chapters on mechanics, which I have otherwise >>>correctly re written for the benefit of science. � NoEinstein � >> >>No, you have just demonstrated your complete stupidity. >> >> >> >> >> >> >>>>On Oct 10, 10:21 am, NoEinstein <noeinst...(a)bellsouth.net> wrote: >> >>>>>On Oct 8, 1:01 pm, PD <thedraperfam...(a)gmail.com> wrote: >> >>>>>Dear PD, the Parasite Dunce: An object's "distance of fall" isn't an >>>>>"energy" component! >> >>>>Of course it is. Please consult on the definition of work, which is >>>>how a force makes an energy contribution. >>>>This contribution is the force times the distance the force acts >>>>through. >>>>The distance is indeed a factor in the energy contribution. >> >>>>I'm astounded -- ASTOUNDED, I tell you! -- that you have forgotten >>>>this basic fact that 7th graders know. >>>>It is in fact the basis for the playground see-saw, not to mention the >>>>block-and-tackle pulley system. >> >>>>>The only force acting on a dropped object is the >>>>>uniform (per unit weight) force of gravity. An object in space that >>>>>is traveling 1,000 miles per hour, after traveling 1,000 miles, will >>>>>impact with the identical KE as a like-size object that traveled one >>>>>million miles at 1,000 miles per hour. >> >>>>But if it is traveling at a constant 1000 miles per hour, then there >>>>is obviously no force acting on the object. >>>>If there were a force acting on it, it would continue to accelerate. >>>>Since there is no force acting on it, then there is no contribution to >>>>the energy whether it is traveling a thousand miles or a million >>>>miles. >> >>>>If you want to know how a force contributes to the energy, then >>>>consider cases where the force is present. Looking at cases where >>>>there is no force acting on the object any more will not help you >>>>understand the basics. >> >>>>>Distance of travel has NO >>>>>direct influence on the object's KE. Try to get that through your >>>>>hard head! � Noeinstein � >> >>>>I'm sorry, NoEinstein, but this is REALLY basic, 7th grade stuff. >>>>Nobody that failed to learn the material from the 7th grade should be >>>>allowed to be licensed as an architect, in my opinion. >> >>>>>>On Oct 8, 10:46 am, NoEinstein <noeinst...(a)bellsouth.net> wrote: >> >>>>>>>On Oct 7, 7:48 pm, PD <thedraperfam...(a)gmail.com> wrote: >> >>>>>>>Dear PD, the Parasite Dunce: The INPUT energy is the UNIFORM force of >>>>>>>gravity. >> >>>>>>No sir. The input energy is the PRODUCT of the force of gravity and >>>>>>the distance the force acts through. >>>>>>This is a simple fact, verified by experiment. >>>>>>And as an object falls, though the force is uniform, the distance per >>>>>>second increases each second, and so the product is not uniform though >>>>>>the force is uniform. >>>>>>I've explained this to you a half-dozen times, and you still don't >>>>>>seem to understand this. Do you have a reading comprehension problem? >> >>>>>>>To have the "output" KE be the square of the time, >>>>>>>immediately, violates the LAW OF THE CONSERVATION OF ENERGY: energy IN >>>>>>>must = energy OUT! � NoEinstein � >> >>>>>>Sorry, no, the INPUT energy is also increasing as the square of time, >>>>>>as I've explained several times. Energy is conserved.- Hide quoted text - >> >>>>- Show quoted text -- Hide quoted text - >> >>- Show quoted text - > > |