Non linear differential equation
in [Matlab]
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From: Gaurav Khare on 30 Apr 2010 14:48 Hi everyone, I want to get the solution of this non linear differential equation in MATLAB. d2A(t)+24.815*A+1714.56*A(t)^3+42.13*A(t)^2=.51*cos(w*t) A(0)=0 d(A)=0 w=5 d2 = double derivative with respect to time d= first derivative with respect to time. somebody please provide me with the solution code...thank you...
From: Gaurav Khare on 1 May 2010 01:27 Can somebody at least tell me how to get an approx solution for this equation I want to draw a plot of A versus time. It's urgent... "Gaurav Khare" <gkhare.iitkgp(a)gmail.com> wrote in message <hrf8l4$hf8$1(a)fred.mathworks.com>... > Hi everyone, > I want to get the solution of this non linear differential equation in MATLAB. > > d2A(t)+24.815*A+1714.56*A(t)^3+42.13*A(t)^2=.51*cos(w*t) > > A(0)=0 > d(A)=0 > w=5 > d2 = double derivative with respect to time > d= first derivative with respect to time. > > somebody please provide me with the solution code...thank you...
From: Torsten Hennig on 2 May 2010 22:31 > Can somebody at least tell me how to get an approx > solution for this equation > I want to draw a plot of A versus time. > It's urgent... > > "Gaurav Khare" <gkhare.iitkgp(a)gmail.com> wrote in > message <hrf8l4$hf8$1(a)fred.mathworks.com>... > > Hi everyone, > > I want to get the solution of this non linear > differential equation in MATLAB. > > > > > d2A(t)+24.815*A+1714.56*A(t)^3+42.13*A(t)^2=.51*cos(w* > t) > > > > A(0)=0 > > d(A)=0 > > w=5 > > d2 = double derivative with respect to time > > d= first derivative with respect to time. > > > > somebody please provide me with the solution > code...thank you... Write your equation as a system of two first-order differential equations y' = z z' = -24.815y - 1714.56y^3 - 42.13y^2 + 0.51*cos(w*t) y(0) = z(0) = 0 and use ODE45 to solve. Best wishes Torsten.
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