From: brien colwell on 11 Jan 2010 05:29 I'd start with something simple like Cases[Tally[list], {a_, 1} :> a] On Sun, Jan 10, 2010 at 3:28 AM, George <gtatishvili(a)gmail.com> wrote: > Hi, > > I have a very big list of elements and I need Mathematica to give me > only those elements which occure only once... > > Could anybody advise me please how to write the code for that? > > Thks much > George > >
From: Albert Retey on 11 Jan 2010 05:30 Hi, > > I have a very big list of elements and I need Mathematica to give me > only those elements which occure only once... > > Could anybody advise me please how to write the code for that? > If you use version 6 or 7, maybe like this? list = RandomInteger[1000, 1000]; Cases[Tally[list], {x_, 1} :> x] hth, albert
From: Harvey P. Dale on 11 Jan 2010 05:31 Try this: Select[BinLists[{yourlist}],Length[#]==1&] Best, Harvey -----Original Message----- From: George [mailto:gtatishvili(a)gmail.com] Sent: Sunday, January 10, 2010 3:29 AM Subject: Occurrences in Mathematica Hi, I have a very big list of elements and I need Mathematica to give me only those elements which occure only once... Could anybody advise me please how to write the code for that? Thks much George
From: Ray Koopman on 11 Jan 2010 18:52 On Jan 10, 12:28 am, George <gtatishv...(a)gmail.com> wrote: > Hi, > > I have a very big list of elements and I need Mathematica to give me > only those elements which occure only once... > > Could anybody advise me please how to write the code for that? > > Thks much > George It takes longer for Cases to process the Tally result than it takes Tally to generate it. Pick is faster. In[1]:= Timing(a)Length[a = RandomInteger[999999,1*^6]] Out[1]= {0.05,1000000} In[2]:= Timing(a)Length[b = Tally@a] Out[2]= {1.59,631912} In[3]:= Timing(a)Length[c = Cases[b,{x_,1}:>x]] Out[3]= {1.73,367228} In[4]:= Timing(a)Length[d = Pick[Sequence@@Transpose@b,1]] Out[4]= {0.5,367228} In[5]:= c === d Out[5]= True
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