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From: Rick Rothstein on 29 Mar 2010 11:59
I don't think you can just add the backslash like that because if it is not
needed then I think it will screw up the path (you would have two
backslashes next to each other with nothing between them). To handle the
situation you are describing would need code something like this I think
(using your code snippet as a base)...

Sub test()
Dim FileToOpen As String, Path As String

Path = ActiveWorkbook.Path
If Right(Path, 1) <> "\" Then Path = Path & "\"
FileToOpen = Dir(Path & "*" & "G016" & "*.xls")

If FileToOpen <> "" Then
Workbooks.Open Path & FileToOpen
End If
End Sub

--
Rick (MVP - Excel)



"OssieMac" <OssieMac(a)discussions.microsoft.com> wrote in message
news:8EDC37F9-06B4-4359-AD83-160280D932EA(a)microsoft.com...
>
> I think that the backslash should also be included in both lines. Seems to
> be OK without if the current default directory is also the activeworkbook
> directory but can one be sure of that.
>
> Sub test()
>
> Dim FileToOpen As String
>
> FileToOpen = Dir(ActiveWorkbook.Path & "\" & "*" & "G016" & "*.xls")
>
> If FileToOpen <> "" Then
> Workbooks.Open ActiveWorkbook.Path & "\" & FileToOpen
> End If
>
> End Sub
>
> --
> Regards,
>
> OssieMac
>
>
> "Rick Rothstein" wrote:
>
>> > Workbooks.Open FileToOpen
>>
>> The above line from your code should be this...
>>
>> Workbooks.Open ActiveWorkbook.Path & FileToOpen
>>
>> Since the Dir function returns only the file's name (without the path
>> associated with it).
>>
>> --
>> Rick (MVP - Excel)
>>
>>
>>
>> "Gary Keramidas" <gkeramidas(a)MSN.com> wrote in message
>> news:O$NCdzvzKHA.1236(a)TK2MSFTNGP06.phx.gbl...
>> > maybe something like this:
>> >
>> > Sub test()
>> > Dim FileToOpen As String
>> >
>> > FileToOpen = Dir(ActiveWorkbook.Path & "*" & "G016" & "*.xls")
>> > If FileToOpen <> "" Then
>> > Workbooks.Open FileToOpen
>> > End If
>> >
>> > End Sub
>> >
>> >
>> > --
>> >
>> >
>> > Gary Keramidas
>> > Excel 2003
>> >
>> >
>> > "shiloh13" <u59050(a)uwe> wrote in message news:a5b747aa8da6d(a)uwe...
>> >> Please Help!!
>> >>
>> >> I have a master file called "All Reports.xls" that opens up various
>> >> Reports
>> >> files(Ex: ABC_G016_GPUS.xls, BCD_G027_GPUS.xls, JKL_G034_GPUS.xls).
>> >> The
>> >> Report files are in the same network folder as the master file and are
>> >> updated frequently. The Report files also have names that constantly
>> >> change
>> >> when they are updated. The only part of the filename that does not
>> >> change
>> >> begins with "G" followed by 3 numbers. By reading previous posts, I
>> >> was
>> >> able
>> >> to figure out how to open the "G016" Report file with the code below.
>> >>
>> >> Workbooks.Open ActiveWorkbook.Path & "ABC_G016_GPUS.xls"
>> >>
>> >> How do I open the file by only the "G016" part of the filename? I
>> >> tried
>> >> the
>> >> code below, but it did not work:
>> >>
>> >> Workbooks.Open ActiveWorkbook.Path & "*" & G016 & "*.xls"
>> >>
>> >> I appreciate your help!!
>> >>
>> >
>> .
>>
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