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From: Bob Hanlon on 15 Sep 2009 04:24
Alternatively, I get the expected form when I use Simplify on the output of DSolve


Bob Hanlon

---- fizzy <fizzycist(a)knology.net> wrote:

=============
oops...I goofed...I meant 1/a^2 D[T[t],{t,2}] with the rest the same....

I tried it again with a fresh kernel and, for TraditionalForm, I still get the same form of output of Exp and e^.......however, when I asked for the form of the output in StandardForm then I get the form e^ for the outputs....

jerry blimbaum
----- Original Message -----
From: Bob Hanlon
To: fizzy ; mathgroup(a)smc.vnet.net
Sent: Sunday, September 13, 2009 8:14 AM
Subject: Re: Output of TraditionalForm for Exp



I get a different (simpler) result.

$Version

7.0 for Mac OS X x86 (64-bit) (February 19, 2009)

eqn = 1/a^2 D[T[t], t] + b D[T[t], t] + c^2 T[t] == 0;

soln = T[t] /. DSolve[eqn, T[t], t][[1]]

C[1]/E^((a^2*c^2*t)/(a^2*b + 1))

eqn /. NestList[D[#, t] &, T[t] -> soln, 1] // Simplify

True

Recommend that you start with a clean kernel.


Bob Hanlon

---- fizzy <fizzycist(a)knology.net> wrote:

=============
Diff Eqn: 1/a^2 D[T[t],t] + b D[T[t],t] + c^2 T[t] == 0

Solution to this gives the following in TraditionalForm =
output:....V7.01....

C1 Exp[1/2 t (a^2 (-b) - a Sqrt[a^2 b^2 -4 c^2])] + C2 e^(1/2 t =
(Sqrt[a^2 b^2 -4 c^2] - a^2 b)]) .....

where the second part, i.e. e^( )...the exponent part, ( ) , is =
actuallly on the same line as the ^ as it would be if I used the power =
exponent from the Basic Math pallette.....


Q:....why this difference in output??....why arent both 'e' raised to =
the power of, etc??...

I realize I can fix this with a rule and HoldForm but why doesnt =
TradForm use only one of the output forms especially in the same output?

thanks....jerry blimbaum


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