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From: Masami Hiramatsu on 9 Mar 2010 10:30
From : Ananth N Mavinakayanahalli <ananth(a)in.ibm.com>

When freeing the instruction slot, the arithmetic to calculate the index
of the slot in the page needs to account for the total size of the
instruction on the various architectures.

Calculate the index correctly when freeing the out-of-line execution slot.

Signed-off-by: Ananth N Mavinakayanahalli <ananth(a)in.ibm.com>
Signed-off-by: Masami Hiramatsu <mhiramat(a)redhat.com>
Reported-by: Sachin Sant <sachinp(a)in.ibm.com>
Reported-by: Heiko Carstens <heiko.carstens(a)de.ibm.com>
---
Index: linux-8mar/kernel/kprobes.c
===================================================================
--- linux-8mar.orig/kernel/kprobes.c 2010-03-08 17:10:33.000000000 +0530
+++ linux-8mar/kernel/kprobes.c 2010-03-08 17:12:12.000000000 +0530
@@ -259,7 +259,8 @@
struct kprobe_insn_page *kip;

list_for_each_entry(kip, &c->pages, list) {
- long idx = ((long)slot - (long)kip->insns) / c->insn_size;
+ long idx = ((long)slot - (long)kip->insns) /
+ (c->insn_size * sizeof(kprobe_opcode_t));
if (idx >= 0 && idx < slots_per_page(c)) {
WARN_ON(kip->slot_used[idx] != SLOT_USED);
if (dirty) {
--
Masami Hiramatsu
e-mail: mhiramat(a)redhat.com
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Prev: usb-serial: optimize sysrq function calls
Next: [RFC PATCH v3 05/11] swiotlb: add swiotlb_set_default_size()