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From: Trevor Rabey on 4 May 2010 06:31 I am new to Mathematica and going at snail's pace. I would like to plot: 8x - x^2 + 14y - y^2 = 49 Anyone? -- Trevor Rabey
From: Murray Eisenberg on 5 May 2010 06:04 It's really a question of what kind of plot you want, since you do not have either x or y as an explicit function of x. Moreover, it's unclear whether you want to regard this as a 2-dimensional curve or as a 3-dimensional surface. In either case, some version of a contour plot will directly give what I think you are asking for: ContourPlot[8x -x^2 + 14y - y^2 == 49, {x, 0, 12}, {y, 0, 12}, Frame->False, Axes->True, AxesLabel->{x,y}] ContourPlot3D[8x - x^2 + 14y - y^2 == 49, {x,0,10}, {y,0,12}, {z,-5,5}, AxesLabel->{x,y,z}] On 5/4/2010 6:30 AM, Trevor Rabey wrote: > I am new to Mathematica and going at snail's pace. > I would like to plot: > > 8x - x^2 + 14y - y^2 = 49 > > Anyone? > > -- > Trevor Rabey > -- Murray Eisenberg murray(a)math.umass.edu Mathematics & Statistics Dept. Lederle Graduate Research Tower phone 413 549-1020 (H) University of Massachusetts 413 545-2859 (W) 710 North Pleasant Street fax 413 545-1801 Amherst, MA 01003-9305
From: Laszlo Sturmann on 5 May 2010 06:04 Trevor Rabey wrote: > I am new to Mathematica and going at snail's pace. > I would like to plot: > > 8x - x^2 + 14y - y^2 = 49 > > Anyone? > > -- > Trevor Rabey > > > The points which satisfy the condition obviously lay on a circle (x-4)^2+(y-7)^2=16 and you can plot it with ContourPlot[8 x - x^2 + 14 y - y^2 == 49, {x, -5, 10}, {y, 0, 15}] LS
From: Alois Steindl on 5 May 2010 06:05 Am 04.05.2010 12:31, schrieb Trevor Rabey: > I am new to Mathematica and going at snail's pace. > I would like to plot: > > 8x - x^2 + 14y - y^2 = 49 > > Anyone? > > -- > Trevor Rabey > Hello, in order to accelerate your progress, you could think of buying a book about Mathematica. Also the Help pages, which come with the program, contain a lot of useful informations. Of course these are not intended to serve as introductions. In your case ContourPlot might help. Alois
From: Bill Rowe on 5 May 2010 06:06
On 5/4/10 at 6:30 AM, trevorATperfectproject.com.au(a)giganews.com (Trevor Rabey) wrote: >I am new to Mathematica and going at snail's pace. I would like to >plot: >8x - x^2 + 14y - y^2 = 49 Here is one way to plot it: sol = Solve[8 x - x^2 + 14 y - y^2 == 49, y]; curve = {{x, y /. First(a)sol}, {x, y /. Last(a)sol}}; ParametricPlot[curve, {x, -1, 8}, PlotStyle -> ColorData[1][1]] Another way would be to use ContourPlot |