Prev: mySQL4VO DataServer
Next: Problem with 5333
From: hpeter on 8 Mar 2007 02:35 Has any one created a fast method to determine the area of a polygon? I saw some methods out there: http://www.efg2.com/Lab/Graphics/PolygonArea.htm Hernado
From: E�!k Visser on 8 Mar 2007 03:29 Hernando, > Has any one created a fast method to determine the area of a polygon? Yes, I did. http://www.sdn.nl/Default.aspx?tabid=50&itemid=1667 Erik "hpeter" <hpatino(a)rocketmail.com> schreef in bericht news:1173339340.051957.159450(a)c51g2000cwc.googlegroups.com... > Has any one created a fast method to determine the area of a polygon? > > I saw some methods out there: > > http://www.efg2.com/Lab/Graphics/PolygonArea.htm > > Hernado >
From: hpeter on 8 Mar 2007 10:46 Erik Your approach and example is very illustrative and simple. Thank you for providing it Hernando
From: G Schaller on 8 Mar 2007 10:48 Contact Fred Killet. He can help you. "hpeter" <hpatino(a)rocketmail.com> wrote in message news:1173339340.051957.159450(a)c51g2000cwc.googlegroups.com: > Has any one created a fast method to determine the area of a polygon? > > I saw some methods out there: > > http://www.efg2.com/Lab/Graphics/PolygonArea.htm > > Hernado
From: VONG on 8 Mar 2007 13:10
Hernando, This link will not materially help you, but I hope you like it nevertheless. It shows a simple physical instrument for measuring the area of ANY 2 dimensional enclosed shape. And there is the most elegant mathematical proof of how it works. I made one of these when I was a teenager and it it still in my garage somewhere. http://whistleralley.com/planimeter/planimeter.htm I have to say Erik's code is almost as elegant but infinitely faster. :o) Dave Francis "hpeter" <hpatino(a)rocketmail.com> wrote in message news:1173368800.962425.26530(a)30g2000cwc.googlegroups.com... > Erik > > Your approach and example is very illustrative and simple. Thank you > for providing it > > Hernando > |