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From: CNN on 27 Jul 2010 11:15
Good day
I'm trying to get the percentage sign printed in a string in my m-file. So I tried to test my options and I'm not getting the answer I expected. Could anyone tell me what I doing wrong here?
str1 = {num2str(sum(a),'%%')}
or
str1 = sprintf('%%',sum(a))

where a = 1:2:20

I just need str1 to contain one value '100%'

Thanks in advance.
From: Jim Rockford on 27 Jul 2010 11:18
On Jul 27, 11:15 am, "CNN " <cnln2...(a)yahoo.co.uk> wrote:
> Good day
> I'm trying to get the percentage sign printed in a string in my m-file.  So I tried to test my options and I'm not getting the answer I expected. Could anyone tell me what I doing wrong here?
> str1 = {num2str(sum(a),'%%')}
> or
> str1 = sprintf('%%',sum(a))
>
> where a = 1:2:20
>
> I just need str1 to contain one value '100%'
>
> Thanks in advance.


How about

str1=strcat(num2str(sum(a)),'%')
From: Rick Branch on 27 Jul 2010 11:39
On Jul 27, 11:15 am, "CNN " <cnln2...(a)yahoo.co.uk> wrote:
> Good day
> I'm trying to get the percentage sign printed in a string in my m-file.  So I tried to test my options and I'm not getting the answer I expected. Could anyone tell me what I doing wrong here?
> str1 = {num2str(sum(a),'%%')}
> or
> str1 = sprintf('%%',sum(a))
>
> where a = 1:2:20
>
> I just need str1 to contain one value '100%'
>
> Thanks in advance.

sprintf('%d%%', sum(a))
From: CNN on 27 Jul 2010 16:16
Rick Branch <rbranch6364(a)gmail.com> wrote in message <36681641-ae66-474d-8756-877c12fb1603(a)e35g2000vbl.googlegroups.com>...
> On Jul 27, 11:15 am, "CNN " <cnln2...(a)yahoo.co.uk> wrote:
> > Good day
> > I'm trying to get the percentage sign printed in a string in my m-file.  So I tried to test my options and I'm not getting the answer I expected. Could anyone tell me what I doing wrong here?
> > str1 = {num2str(sum(a),'%%')}
> > or
> > str1 = sprintf('%%',sum(a))
> >
> > where a = 1:2:20
> >
> > I just need str1 to contain one value '100%'
> >
> > Thanks in advance.
>
> sprintf('%d%%', sum(a))

Thanks, both answers worked. But I don't understand the format '%d%%'. I know '%d' formats 'sum(a)' as an integer so do the remaining %% provide the percentage sign? If that is the case, why didn't it work for me? Do I really have to indicate that it is an integer first?
From: us on 27 Jul 2010 16:24
On Jul 27, 10:16 pm, "CNN " <cnln2...(a)yahoo.co.uk> wrote:
> Rick Branch <rbranch6...(a)gmail.com> wrote in message <36681641-ae66-474d-8756-877c12fb1...(a)e35g2000vbl.googlegroups.com>...
> > On Jul 27, 11:15 am, "CNN " <cnln2...(a)yahoo.co.uk> wrote:
> > > Good day
> > > I'm trying to get the percentage sign printed in a string in my m-file.  So I tried to test my options and I'm not getting the answer I expected. Could anyone tell me what I doing wrong here?
> > > str1 = {num2str(sum(a),'%%')}
> > > or
> > > str1 = sprintf('%%',sum(a))
>
> > > where a = 1:2:20
>
> > > I just need str1 to contain one value '100%'
>
> > > Thanks in advance.
>
> > sprintf('%d%%', sum(a))
>
> Thanks, both answers worked. But I don't understand the format '%d%%'. I know '%d' formats 'sum(a)' as an integer so do the remaining %% provide the percentage sign? If that is the case, why didn't it work for me? Do I really have to indicate that it is an integer first?  

well...
YES... how could it possibly be otherwise(?)... a built-in, magic
thought-reader (albeit, CSSMers are still waiting for that particular
tbx by steve eddins)...

more wisdom may be collected by typing this into the command window

doc sprintf;

us
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