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From: Paso Sivro on 21 May 2010 20:46
Hello!

Can somebody tell me where is the problme in the following code (timestep cant be increased). Thanx in advance!

clear
%function falling_apple
g= 9.81;
h(1,1)=10;
v(1,1)=10;
timestep=0.01;
index=1;

while (h(index)>0)
v(index+1,1)=v(index,1)-g*timestep;
h(index+1,1)=h(index,1)-v(index,1)*timestep;
index=index+1;
end

figure(1);
plot(v);
xlabel('timestep');
ylabel ('v[m/s]');

figure(2);
plot(h);
xlabel('timesptep');
xlabel('h[m]');

return
From: John D'Errico on 21 May 2010 21:05
"Paso Sivro" <findsivro(a)gmail.com> wrote in message <ht79gc$ip0$1(a)fred.mathworks.com>...
> Hello!
>
> Can somebody tell me where is the problme in the following code (timestep cant be increased). Thanx in advance!

Sure it can be increased.

timestep=1000000;

Perhaps you have some reason for asking this question?
Is this your homework assignment?

John
From: Matt Fig on 21 May 2010 21:25
Your velocity is getting smaller as the apple falls. Is that what one would expect? Also, your height should decrease parabolically, not linearly. You may need a break statement for the case where the height becomes less than zero.
From: Paso Sivro on 21 May 2010 21:35
What do you write it in MATLAB break?

"Matt Fig" <spamanon(a)yahoo.com> wrote in message <ht7bpi$dvq$1(a)fred.mathworks.com>...
> Your velocity is getting smaller as the apple falls. Is that what one would expect? Also, your height should decrease parabolically, not linearly. You may need a break statement for the case where the height becomes less than zero.
From: Matt Fig on 21 May 2010 21:41
Look at the help for BREAK.

>> help break
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