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From: aegis on 14 Feb 2010 21:55 given the Frenet-Serret formula dT/ds =kN where T is the unit tangent vector and N is the unit normal vector: how does s' * dT/ds * s' = k(s')^2 * N ? where s' = ds/dt I'm working this out to prove: r'' = s''T + k(s')^2N where r is a vector. I don't see how I can express the left hand side as the right hand side of: s' * dT/ds * s' = k(s')^2 * N dT/ds = N but how can we relate s' * s' to k(s')^2? -- aegis |