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From: Fred on 21 Jul 2010 11:48 On Jul 21, 6:32 am, "G. A. Edgar" <ed...(a)math.ohio-state.edu.invalid> wrote: > A remark on the definition of "algebraic function" ... > For example, we do not want to allow: f(x) = sqrt(1-x^2) for > x rational in (-1,1) and f(x) = -sqrt(1-x^2) for x irrational > in (-1,1). Why don't we want to allow that? Even more so, don't we want to allow | x| to be algebraic since it satisfies the polynomial y^2 - x^2? --Fred
From: G. A. Edgar on 21 Jul 2010 21:44 In article <b71bab5e-1793-4ca2-b822-d6661fb37071(a)g19g2000yqc.googlegroups.com>, Fred <f.richman(a)comcast.net> wrote: > On Jul 21, 6:32�am, "G. A. Edgar" <ed...(a)math.ohio-state.edu.invalid> > wrote: > > > A remark on the definition of "algebraic function" ... > > > For example, we do not want to allow: f(x) = sqrt(1-x^2) for > > x rational in (-1,1) and f(x) = -sqrt(1-x^2) for x irrational > > in (-1,1). > > Why don't we want to allow that? Even more so, don't we want to allow | > x| to be algebraic since it satisfies the polynomial y^2 - x^2? > > --Fred No, we don't. At least I don't. But then I would start with an analytic function defined on a domain of the complex plane. Or maybe defined on a Riemann surface. -- G. A. Edgar http://www.math.ohio-state.edu/~edgar/
From: Fred on 22 Jul 2010 22:08 On Jul 21, 9:44 pm, "G. A. Edgar" <ed...(a)math.ohio-state.edu.invalid> wrote: > In article > <b71bab5e-1793-4ca2-b822-d6661fb37...(a)g19g2000yqc.googlegroups.com>, > > Fred<f.rich...(a)comcast.net> wrote: > > On Jul 21, 6:32 am, "G. A. Edgar" <ed...(a)math.ohio-state.edu.invalid> > > wrote: > > > > A remark on the definition of "algebraic function" ... > > > > For example, we do not want to allow: f(x) = sqrt(1-x^2) for > > > x rational in (-1,1) and f(x) = -sqrt(1-x^2) for x irrational > > > in (-1,1). > > > Why don't we want to allow that? Even more so, don't we want to > > allow |x| to be algebraic since it satisfies the polynomial > > y^2 - x^2? > > > --Fred > > No, we don't. At least I don't. But then I would start with an > analytic function defined on a domain of the complex plane. Or > maybe defined on a Riemann surface. > > --G. A. Edgar I guess it all depends on where one is coming from. My motivation is the definition of "algebraic function" given in most calculus books. They clearly consider |x| to be algebraic because it is sqrt x^2. --Fred
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