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From: JJ on 20 Mar 2010 16:17 Hi all, here is a question I wanted to ask about, regarding this concept of the Universe being 4-dimensional. The question is, how is this 4-dimensionality reflected in mathematic equations used to solve physics problems? For example, my understanding is (correct me if I am wrong) that before "time" was added as one of the dimensions, some of the calculations were done with just 3 dimensions and adding the dimension of time helped in solving some of the calculations. Are the dimensions in reflected in the equations as exponents of some kind? Thanks in advance,
From: BURT on 20 Mar 2010 16:26 On Mar 20, 1:17 pm, JJ <sa...(a)temporaryinbox.com> wrote: > Hi all, > > here is a question I wanted to ask about, regarding this concept of > the Universe being 4-dimensional. > > The question is, how is this 4-dimensionality reflected in mathematic > equations used to solve physics problems? > > For example, my understanding is (correct me if I am wrong) that > before "time" was added as one of the dimensions, some of the > calculations were done with just 3 dimensions and adding the dimension > of time helped in solving some of the calculations. Are the dimensions > in reflected in the equations as exponents of some kind? > > Thanks in advance, The higher dimension is driving the expansion of the universe. But it is a 4th dimension's space that we cannot place inside or outside the univertse. But it is the interior oif the hypersphere model. The universe is in the closed surface of a 4 dimensional round geometry. Mitch Raemsch
From: Androcles on 20 Mar 2010 16:31 "JJ" <santa(a)temporaryinbox.com> wrote in message news:19df96bb-07b8-4b5e-b277-6c7f5b006cf9(a)q21g2000yqm.googlegroups.com... > Hi all, > > here is a question I wanted to ask about, regarding this concept of > the Universe being 4-dimensional. > > The question is, how is this 4-dimensionality reflected in mathematic > equations used to solve physics problems? > > For example, my understanding is (correct me if I am wrong) that > before "time" was added as one of the dimensions, some of the > calculations were done with just 3 dimensions and adding the dimension > of time helped in solving some of the calculations. Are the dimensions > in reflected in the equations as exponents of some kind? > > Thanks in advance, Time is not a vector, it has no additive inverse. http://mathworld.wolfram.com/VectorSpace.html No physics problems are solved with sci-fi by failed mathematicians. 'Really, this is what is meant by the Fourth Dimension, though some people who talk about the Fourth Dimension do not know they mean it. It is only another way of looking at Time. There is no difference between Time and any of the three dimensions of Space except that our consciousness moves along with it.' -- Herbert George Wells - "The Time Machine" - 1895. You're welcome in advance, Androcles. >
From: Darwin123 on 20 Mar 2010 18:01 On Mar 20, 4:17 pm, JJ <sa...(a)temporaryinbox.com> wrote: > Hi all, > > here is a question I wanted to ask about, regarding this concept of > the Universe being 4-dimensional. > > The question is, how is this 4-dimensionality reflected in mathematic > equations used to solve physics problems? I think the answer is in terms of matrix theory. A transformation can be considered the change associated with a change in the observer. If the change in a parameter is expressible in terms of a unitary transformation, then the parameter can be called a dimension. Assuming that the change in observer causes a unitary transformation simplifies the problem a great deal, no matter what field of physics the problem is in. The time evolution operator is expressible as a unitary transformation. The concept of dimension is generally used for parameter that can be transformed as a tensor. This means that the linear transformations are in some ways analogous to a rotation. This means that discussion is usually confined to transformations that preserve some quantity analogous to length. Thus, to be called a dimension you need the linear transformations to be expressed as unitary matrices. Example: In 3-D Euclidean space, points are expressed as vectors that can undergo a rotation. A rotation is defined as a linear transformation that doesn't change the length of the vector. Thus, the three geometric parameters are called dimensions because there is a physically meaningful transformation (the rotation) that preserves length. Counter example: Temperature is usually not called a dimension since there it does not transform with rotation, or with anything like a rotation. There is no physically meaningful transformation that includes temperature that can be expressed in terms of a unitary matrix. Thus, you generally DON'T find temperature expressed as a dimension. There is no "length" associated with temperature. Thus, the concept of rotation has no meaning. Gibbs managed to express some thermodynamics problems in terms of geometry. So, I believe there are special cases where temperature is called a dimension. However, these are exceptions that prove the rule. Temperature is seldom called a dimension because there is seldom a unitary transformation that shows how a change in observer results in a change in temperature. I think this concept extends through Galilean invariant physics (Newtons laws), Lorentz invariant physics (special relativity), covariant physics (general relativity) and quantum mechanics. A parameter is called a dimension if it transforms as a tensor with a unitary matrix. In special relativity, the use of time as a "dimension" is tied with the proper time being invariant to the Lorentz transformation. The Lorentz transformation can be expressed in terms of a unitary matrix. The proper time in SR is analogous to length in the Euclidean case. So if a parameter can be included in a unitary transformation, then could be called a dimension. There has to be a length that is unchanged. Time is a dimension because observers in different places and different times can connect their observations through a unitary matrix (i.e., the Lorentz transformation).
From: Sue... on 20 Mar 2010 18:39
On Mar 20, 4:17 pm, JJ <sa...(a)temporaryinbox.com> wrote: > Hi all, > > here is a question I wanted to ask about, regarding this concept of > the Universe being 4-dimensional. > > The question is, how is this 4-dimensionality reflected in mathematic > equations used to solve physics problems? > > For example, my understanding is (correct me if I am wrong) that > before "time" was added as one of the dimensions, some of the > calculations were done with just 3 dimensions and adding the dimension > of time helped in solving some of the calculations. Are the dimensions > in reflected in the equations as exponents of some kind? > ============ > Thanks in advance, Does that violate causality ? :-) << the four-dimensional space-time continuum of the theory of relativity, in its most essential formal properties, shows a pronounced relationship to the three-dimensional continuum of Euclidean geometrical space. In order to give due prominence to this relationship, however, we must replace the usual time co-ordinate t by an imaginary magnitude sqrt(-1) ct proportional to it. Under these conditions, the natural laws satisfying the demands of the (special) theory of relativity assume mathematical forms, in which the time co-ordinate plays exactly the same rôle as the three space co-ordinates. >> http://www.bartleby.com/173/17.html << if you know about complex numbers you will notice that the space part enters as if it were imaginary R2 = (ct)2 + (ix)2 + (iy)2 + (iz)2 = (ct)2 + (ir)2 where i^2 = -1 as usual. This turns out to be the essence of the fabric (or metric) of spacetime geometry - that space enters in with the imaginary factor i relative to time. >> http://www.aoc.nrao.edu/~smyers/courses/astro12/speedoflight.html http://en.wikipedia.org/wiki/Complex_number "Space-time" http://farside.ph.utexas.edu/teaching/em/lectures/node113.html Sue... |