From: OsherD on
From Osher Doctorow

The Fibonacci numbers actually start counting from 0:

1) F0 = 0
2) F1 = 1

Then F2 = F1 + F0 = 1 + 0 = 1. So my referring to 1, 1 as initial
values was incorrect - 0 and 1 are the first two values.

Osher Doctorow
From: OsherD on
From Osher Doctorow

Some arguably quark-triple relevant aspects of sqrt(3) (see
Wikipedia's "Square root of 3", Wolfram's "Equilateral Triangle",
Wolfram's "Theodorus' Constant", etc.):

1) Each angle of an equilateral triangle is pi/3 (which is 60
degrees).
2) tan(60 degrees) = sqrt(3).
3) The space diagonal of a unit cube has length sqrt(3).
4) The area of an equilateral triangle is (1/4)sqrt(3) s^2 where s is
the length of any side.
5) The altitude of an equilateral triangle is sqrt(3)/2.
6) The area of the circumcircle of an equilateral triangle is (1/3)pi
s^2, where s is the length of any side.

Osher Doctorow
From: OsherD on
From Osher Doctorow

The altitude of an equilateral triangle is [sqrt(3)/2)]s where s is
the length of any side. I omitted the s (typo).

Osher Doctorow
From: OsherD on
From Osher Doctorow

Here is a rather curious result resulting to (1 +/- sqrt(3)/2:

1) [(1/2)(1 + sqrt(3))]^2 + [(1/2)(1 - sqrt(3))]^2 = i^2 = -1 (so
the roots are sides of an imaginary right triange of hypoteneuse i).

because the first square on the left is (1/2)(sqrt(3)i - 1), while the
second square on the left is (-1/2)(1 + sqrt(3)i). So the values of
x from Gn = Gn-1 - Gn-2 obtained as (1 +/- sqrt(3))/2 (partly
analogous to the Golden ratio from the Fibonacci numbers) are sides of
an imaginary right triangle with hypoteneuse i.

Osher Doctorow

From: Igor on
On May 2, 8:38 pm, OsherD <mdocto...(a)ca.rr.com> wrote:
> From Osher Doctorow
>
> We have seen that, in analogy with the Fibonacci Numbers F_n or Fn:
>
> 1) Fn = Fn-1 + Fn-2,  n > 1
>
> the Probable Causation/Influence Differences y - x from P(A-->B) = 1 +
> y - x  in their sequence representation:
>
> 2) Gn = Gn-1 - Gn-2
>
> are related to a "limiting type" result partly analogous to the
> Fibonacci quotient Fn+1/Fn limit phi, where phi is the Golden Mean or
> Golden Ratio = (1 + sqrt(5))/2.    The partial analog for Gn is:
>
> 3) x = [1 +/- sqrt(3) i ]/2
>
> The exactly same procedure that produces phi from Fn, namely dividing
> both sides of (1) by Fn-1 and taking the limit as n --> infinity,
> yields (3) from (2) except that the limit in a strict sense does not
> exist (not surprising since it contains the imaginary i while Gn are
> real-valued).
>
> Since (3) arguably represents Unification of the 4 Fundamental
> Interactions as explained in the recent post here, it involves "new
> mathematics" and "new physics".
>
> There are some interesting consequences of putting various initial
> values G1, G2 into (2) and then calculating the resulting sequences of
> Gn, although unlike Fn where F1 = 1 = F2, the Gn sequences are quite
> different:
>
> 4) If G2 - G1 is different from both G1 and G2 and neither is 0 (and
> G2 - G1 is not 0), then Gn takes on 6 different values in sequence
> which keep repeating, namely G1, G2, G2 - G1, and their negatives.
>
> 5) If G2 - G1 equals one of G1 or G2 (usually G1 in that case) and
> neither is 0 and they are unequal, then Gn takes on 4 different values
> in sequence, namely G1, G2, and their negatives.  If one of G1 or G2
> is 0 or they are equal, then Gn has fewer than 4 different values.
>
> The 6 in (4) is 3! = 3 times 2 times 1, which again arguably relates
> back to quarks (the number of ways of selecting one quark from 3 or
> one edge from a triangle).   The 4 in (5) appears to relate to the
> "degeneration" of the triangle from 3 to 2 sides.
>
> For example, if we select G1 = 2 and G2 = 10, then we get:
>
> 6) G1 = 2, G2 = 10, G3 = 8, G4 = -2, G5 = -10, G2 = -8, G7 = 2, etc.
> (repeats).
>
> Osher Doctorow

But how is this related to quantum gravity?