From: Zach on 24 Mar 2010 14:32 Hello all- I have a query: SELECT [Sheaves Limits Query].Ratio, [Sheaves Limits Query].ASheave, [Sheaves Limits Query].BSheave, [Sheaves Limits Query].HPRating, [Sheaves Limits Query].ADiameter, [Sheaves Limits Query].BDiameter, [Sheaves Limits Query].CONVENTIONAL, [Sheaves Limits Query].ProposedBeltLength, [Sheaves Limits Query].MinProposedBeltLength, [Sheaves Limits Query].MaxPorposedBeltLength, [Sheaves Limits Query].ArcLength, ArcOfContact.ArcOfContact, ArcOfContact.CorrectionFactor, Belts.PartNumber, Belts.LinearLength, Belts.Type, Belts.LengthCorrectionFactor, [Sheaves Limits Query].SheaveType FROM [Sheaves Limits Query], ArcOfContact, Belts WHERE (((ArcOfContact.ArcOfContact)=[ArcLength] Or (ArcOfContact.ArcOfContact)>[ArcLength]-5) AND ((Belts.LinearLength)=[Proposedbeltlength] Or (Belts.LinearLength)<[ProposedBeltLength] And (Belts.LinearLength)>[ProposedBeltLength]-1.5) AND ((Belts.Type)=[SheaveType])); It does some calculations for me and cross references other tables/queries in order to run its calcs. my problem is that I need query result to be only for the first criteria that worked. for instance. If my criteria of: (((ArcOfContact.ArcOfContact)=[ArcLength] Or (ArcOfContact.ArcOfContact)>[ArcLength]-5) gives 2 results, due to it finding one that equaled exaxtly, and also found one within the -5, then it would show both. I want it to use the one that equaled exactly, but if null to use the other criteria. Hope that makes since. I realize i might not be doing it the "correct way". Just trying to get it to work. I've tried incorporating "Switch()" function & "Choose()" & "iif()". But can't get the result I am looking for. Any help is greatly appreciated!!!!!! Thanks! Zach
From: PieterLinden via AccessMonster.com on 24 Mar 2010 17:18 Zach wrote: >Hello all- >I have a query: > >SELECT [Sheaves Limits Query].Ratio, [Sheaves Limits Query].ASheave, >[Sheaves Limits Query].BSheave, [Sheaves Limits Query].HPRating, [Sheaves >Limits Query].ADiameter, [Sheaves Limits Query].BDiameter, [Sheaves Limits >Query].CONVENTIONAL, [Sheaves Limits Query].ProposedBeltLength, [Sheaves >Limits Query].MinProposedBeltLength, [Sheaves Limits >Query].MaxPorposedBeltLength, [Sheaves Limits Query].ArcLength, >ArcOfContact.ArcOfContact, ArcOfContact.CorrectionFactor, Belts.PartNumber, >Belts.LinearLength, Belts.Type, Belts.LengthCorrectionFactor, [Sheaves Limits >Query].SheaveType >FROM [Sheaves Limits Query], ArcOfContact, Belts >WHERE (((ArcOfContact.ArcOfContact)=[ArcLength] Or >(ArcOfContact.ArcOfContact)>[ArcLength]-5) AND >((Belts.LinearLength)=[Proposedbeltlength] Or >(Belts.LinearLength)<[ProposedBeltLength] And >(Belts.LinearLength)>[ProposedBeltLength]-1.5) AND >((Belts.Type)=[SheaveType])); > >It does some calculations for me and cross references other tables/queries >in order to run its calcs. my problem is that I need query result to be only >for the first criteria that worked. for instance. >If my criteria of: >(((ArcOfContact.ArcOfContact)=[ArcLength] Or >(ArcOfContact.ArcOfContact)>[ArcLength]-5) >gives 2 results, due to it finding one that equaled exaxtly, and also found >one within the -5, then it would show both. I want it to use the one that >equaled exactly, but if null to use the other criteria. Hope that makes >since. I realize i might not be doing it the "correct way". Just trying to >get it to work. > >I've tried incorporating "Switch()" function & "Choose()" & "iif()". But >can't get the result I am looking for. Any help is greatly appreciated!!!!!! > >Thanks! >Zach One way might be to have separate queries for the mutually exclusive options and open them from a form. Then you can evaluate the criteria entered and choose the correct query to run in code. If you based a form on the unfiltered query, you could select options on your unbound form, and build the filter on the fly and pass the filter string you just built in when you open the form (DoCmd.OpenForm...) near the end of the list of arguments is the filter... just reference your filter string there. HTH, Pieter -- Message posted via http://www.accessmonster.com
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