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From: Ghuloum, Anwar on 13 Jun 2007 08:05 Is it possible to put conditional clauses (i.e. If[.]) in the VertexRenderingFunction option for TreeForm (or any primitive that this option applies to)? I wanted to selectively label vertices based on label content, but Mathematica was complaining that "If" is not a graphics primitive or directive. (Basically, I'm trying to draw a tree where only the leaves have labels: TreeForm[{{a, b}, {c, {d}}}, VertexRenderingFunction -> (If[#2 == List, {}, Text[#2, #1]] &)] ) In general, I was having a hard time finding information at the documentation center on the limitations on how I can generate graphics primitives.but perhaps I'm not looking in the right place. Thanks in advance! -- Anwar Ghuloum Microprocessor Technology Lab, Intel
From: Jean-Marc Gulliet on 14 Jun 2007 05:38 Ghuloum, Anwar wrote: > Is it possible to put conditional clauses (i.e. If[.]) in the > VertexRenderingFunction option for TreeForm (or any primitive that this > option applies to)? I wanted to selectively label vertices based on label > content, but Mathematica was complaining that "If" is not a graphics > primitive or directive. > > > > (Basically, I'm trying to draw a tree where only the leaves have labels: > > TreeForm[{{a, b}, {c, {d}}}, VertexRenderingFunction -> (If[#2 == List, {}, > Text[#2, #1]] &)] > > ) > > > > In general, I was having a hard time finding information at the > documentation center on the limitations on how I can generate graphics > primitives.but perhaps I'm not looking in the right place. > > > Thanks in advance! > > -- > > Anwar Ghuloum > > Microprocessor Technology Lab, Intel > > > Below we define a function with some conditions on it. In doing so, Mathematica sees only graphic primitive whenever it evaluates the VertexRenderingFunction option. (Arguably, the following example is written in a more Mathematica fashion.) If the second argument is a list, then the first definition (the less general definition indeed) is evaluated and the empty list is returned. Otherwise, the more general definition (the second in our case) is called and the graphic primitive Text is returned. myRender[r_, k_] := {} /; k == List myRender[r_, k_] := Text[k, r] TreeForm[{{a, b}, {c, {d}}}, VertexRenderingFunction -> (myRender[#1, #2] & )] Regards, Jean-Marc
From: Carl Woll on 14 Jun 2007 05:57 Ghuloum, Anwar wrote: >Is it possible to put conditional clauses (i.e. If[.]) in the >VertexRenderingFunction option for TreeForm (or any primitive that this >option applies to)? I wanted to selectively label vertices based on label >content, but Mathematica was complaining that "If" is not a graphics >primitive or directive. > > > >(Basically, I'm trying to draw a tree where only the leaves have labels: > >TreeForm[{{a, b}, {c, {d}}}, VertexRenderingFunction -> (If[#2 == List, {}, >Text[#2, #1]] &)] > >) > > Try using === instead of ==: TreeForm[{{a, b}, {c, {d}}}, VertexRenderingFunction -> (If[#2 === List, {}, Text[#2, #1]] &)] Alternatively, use the 4 argument form of If. Your problem was that If couldn't determine whether a==List was True or False. Hence it was left unevaluated, and the result wasn't a graphics directive. Carl Woll Wolfram Research > > >In general, I was having a hard time finding information at the >documentation center on the limitations on how I can generate graphics >primitives.but perhaps I'm not looking in the right place. > > >Thanks in advance! > >-- > >Anwar Ghuloum > >Microprocessor Technology Lab, Intel > > > >
From: Ghuloum, Anwar on 15 Jun 2007 05:16 Thanks to Jean-Marc and all who responded! -----Original Message----- From: Jean-Marc Gulliet [mailto:jeanmarc.gulliet(a)gmail.com] Sent: Thursday, June 14, 2007 2:24 AM Subject: Re: Question re: graphics primitives Ghuloum, Anwar wrote: > Is it possible to put conditional clauses (i.e. If[.]) in the > VertexRenderingFunction option for TreeForm (or any primitive that this > option applies to)? I wanted to selectively label vertices based on label > content, but Mathematica was complaining that "If" is not a graphics > primitive or directive. > > > > (Basically, I'm trying to draw a tree where only the leaves have labels: > > TreeForm[{{a, b}, {c, {d}}}, VertexRenderingFunction -> (If[#2 == List, {}, > Text[#2, #1]] &)] > > ) > > > > In general, I was having a hard time finding information at the > documentation center on the limitations on how I can generate graphics > primitives.but perhaps I'm not looking in the right place. > > > Thanks in advance! > > -- > > Anwar Ghuloum > > Microprocessor Technology Lab, Intel > > > Below we define a function with some conditions on it. In doing so, Mathematica sees only graphic primitive whenever it evaluates the VertexRenderingFunction option. (Arguably, the following example is written in a more Mathematica fashion.) If the second argument is a list, then the first definition (the less general definition indeed) is evaluated and the empty list is returned. Otherwise, the more general definition (the second in our case) is called and the graphic primitive Text is returned. myRender[r_, k_] := {} /; k == List myRender[r_, k_] := Text[k, r] TreeForm[{{a, b}, {c, {d}}}, VertexRenderingFunction -> (myRender[#1, #2] & )] Regards, Jean-Marc
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