From: 2.7182818284590... on
How can this reaction occur if you don't have the starting material to
begin with:

Be2+ 2e- -----> Be E= +1.70
Au3+ 3e- -----> Au E= +1.29


Both, the Be2+ and Au3+ are in solution. There is no Be or Au.
Moreover, both of these cations WANT to become reduced. The Be2+
*wants* to become reduced MORESO than the Au3+, however, the Au3+
can't lose any more electrons.

Please help me understand this basic challenge. The V for the above
is E= +2.99, by the way.
From: Robert Higgins on
On Jul 25, 4:43 pm, "2.7182818284590..." <tangent1...(a)gmail.com>
wrote:
> How can this reaction occur if you don't have the starting material to
> begin with:
>
> Be2+   2e-     ----->  Be       E= +1.70
> Au3+   3e-     ----->  Au       E= +1.29
>
> Both, the Be2+ and Au3+ are in solution.  There is no Be or Au.
> Moreover, both of these cations WANT to become reduced.  The Be2+
> *wants* to become reduced MORESO than the Au3+, however, the Au3+
> can't lose any more electrons.
>
> Please help me understand this basic challenge.  The V for the above
> is E= +2.99, by the way.

Hint: Do your own homework. BTW, these are simple problems, and the
fact that you can't solve them suggests you need to study.