From: 2.7182818284590... on 25 Jul 2010 16:43 How can this reaction occur if you don't have the starting material to begin with: Be2+ 2e- -----> Be E= +1.70 Au3+ 3e- -----> Au E= +1.29 Both, the Be2+ and Au3+ are in solution. There is no Be or Au. Moreover, both of these cations WANT to become reduced. The Be2+ *wants* to become reduced MORESO than the Au3+, however, the Au3+ can't lose any more electrons. Please help me understand this basic challenge. The V for the above is E= +2.99, by the way.
From: Robert Higgins on 25 Jul 2010 20:05 On Jul 25, 4:43 pm, "2.7182818284590..." <tangent1...(a)gmail.com> wrote: > How can this reaction occur if you don't have the starting material to > begin with: > > Be2+ 2e- -----> Be E= +1.70 > Au3+ 3e- -----> Au E= +1.29 > > Both, the Be2+ and Au3+ are in solution. There is no Be or Au. > Moreover, both of these cations WANT to become reduced. The Be2+ > *wants* to become reduced MORESO than the Au3+, however, the Au3+ > can't lose any more electrons. > > Please help me understand this basic challenge. The V for the above > is E= +2.99, by the way. Hint: Do your own homework. BTW, these are simple problems, and the fact that you can't solve them suggests you need to study.
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