From: Alejandro Michelin Salomon on 29 Sep 2010 16:10 David : Try this : $a = explode('-', '2010-01-23'); $b = array( $a[1], $a[2], $a[0] ); echo implode( '/', $b); // 01/23/2010 Alejandro M.S. -----Mensagem original----- De: David Mehler [mailto:dave.mehler(a)gmail.com] Enviada em: quarta-feira, 29 de setembro de 2010 16:12 Para: php-general Assunto: [PHP] converting a mysql date value Hello, I've got dates stored in a mysql database. The field is of type date so the value is something like: "2010-09-29" I'm wanting to display them as in U.S. dates as in month, day, year. I had a function that did this, now it is not working and I am perplexed as to why. Here's my echo statement: <?php echo sqlDateFormat($row['date']); ?> The $row['date'] is coming out of the mysql database. Here's the sqlDateFormat function: function sqlDateFormat($value) { $date = $value; $date = strtotime($date); $date = date('m-d-y', $date); return $date; } I'd appreciate any suggestions as to why this isn't working. Thanks. Dave. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
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