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From: a boy on 1 Feb 2010 06:12
Ramsey Number R(3,k)\[Congruent]1,3,4 mod 5



o o o o o
....o o o o o ...
o o o

Conjecture: The vertexes of Ramsey critical graph G(3,k) can be arranged as
interlacing with 2 vertexes and 3 vertexes. So,

R(3,k)-1=0,2,3 mod 5, R(3,k)=1,3,4 mod 5

R(3,10) is between [40,43]. If my conjecture is true, then R(3,10) can be
41 or 43 only; R(3,11) is in [46, 51], I think R(3,11) can not be 47 or 50.


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