From: James Tursa on 30 Apr 2010 03:58 "Matt Fig" <spamanon(a)yahoo.com> wrote in message <hrdrsm$n4s$1(a)fred.mathworks.com>... > > I was implying that (IMO), the OP was looking for something else. You're probably right ... James Tursa
From: us on 30 Apr 2010 06:49 "AS" > So, the question now reduces to finding a function to give me the number of digits in a number. For example: > 12353 --> 5 > 32.7182 --> 6 > .9945 --> 4 > > Any thoughts on that? yes - how could this ...ever... work(?)... because, what you see is not what you have... and - whoever thinks (including mathematica) HAS to make some second guessing, ie, approximation (maybe based on some +/-EPS arithmetic)... thus, you're better off if you specify the # of digits you want to look at... format long; n=32.7182 % <- what you type... % n = 32.718200000000003 % <- what you have... % -or- n=32.71820004 % <- now you have a more exotic number... % n = 32.718200039999999 n=32.71820005 % n = 32.718200050000000 % <- just so happens(!) % whatever has to deal with your request, sees the ...what you have... only... us
|
Pages: 1 Prev: Audio Peak Next: Finding missing frequencies in speech signal |