SendKeys/MySendKeys (Karl)
in [Visual Basic]
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From: Karl E. Peterson on 2 Apr 2010 18:10 Juergen Thuemmler wrote: > Hi Karl, > >> Works here, too. Now I just need to find a bit more elegant way to handle >> that StuffBuffer routine. It's sorely in need of a GoSub, don't ya think? >> <g> > > may be, if you like it ;-) But I don't believe it would better... Heh, couldn't do it. Ended up with this: Private Sub StuffShift(ByVal KeyCode As Integer, Optional Press As Boolean) ' ADDED 02-Apr-2010 ' Effectively a GoSub from StuffBuffer... With m_Events(m_EvtPtr) .wVK = KeyCode If Not Press Then .dwFlags = KEYEVENTF_KEYUP End If End With m_EvtPtr = m_EvtPtr + 1 End Sub > I forgot somethig regarding "{~}": Oh oh. Is that a stinkin' AltGr char too??? > Private Sub ProcessNamedKey() > Dim EndPtr As Long, i As Long, repeat As Long > Dim this As String > Dim pieces As Variant '() As String > Dim vk As Integer > Dim capped As Boolean, extend As Boolean, AltGr As Boolean '<<<### > > EndPtr = InStr(m_DatPtr + 2, m_Data, "}") > ' No need to do anything if endgroup immediately follows beginning. > If EndPtr > (m_DatPtr + 1) Then > ' Extract group of characters. > this = Mid$(m_Data, m_DatPtr + 1, EndPtr - m_DatPtr - 1) > > ' Break into pieces, if possible. > pieces = Split(this, " ") > > ' Second element, if avail, is number of times to repeat stroke. > If UBound(pieces) > 0 Then repeat = Val(pieces(1)) > If repeat < 1 Then repeat = 1 > > ' Attempt to retrieve named keycode, or else retrieve standard code. > vk = GetNamedKey(CStr(pieces(0))) > If ByteHi(vk) = 6 Then AltGr = True '<<<### > If vk Then > ' Is this an extended key? > extend = IsExtendedKey(this) > Else > ' Not a standard named key. > vk = VkKeyScan(Asc(this)) > If ByteHi(vk) = 6 Then AltGr = True '<<<### > capped = CBool(ByteHi(vk) And 1) > vk = ByteLo(vk) > End If > > ' Stuff buffer as many times as required. > For i = 1 To repeat > Call StuffBuffer(vk, capped, extend, AltGr) '<<<### > Next i > > ' Advance data pointer to closing parenthesis. > m_DatPtr = EndPtr > End If > End Sub Is this an actual or theoretical problem one? Assuming a good reason to do it, would this work just as well: AltGr = CBool(ByteHi(vk) And 6) For i = 1 To repeat ... Just trying to understand the multiple tests there. Thanks... Karl -- ..NET: It's About Trust! http://vfred.mvps.org
From: Juergen Thuemmler on 3 Apr 2010 05:40 Hi Karl, > Oh oh. Is that a stinkin' AltGr char too??? Oh yes ;-) > Is this an actual or theoretical problem one? Assuming a good reason to > do it, would this work just as well: > > AltGr = CBool(ByteHi(vk) And 6) > For i = 1 To repeat > ... > > Just trying to understand the multiple tests there. Because you use vk for different values: If vk Then ' Is this an extended key? extend = IsExtendedKey(this) Else ' Not a standard named key. vk = VkKeyScan(Asc(this)) '<<<### If ByteHi(vk) = 6 Then AltGr = True capped = CBool(ByteHi(vk) And 1) vk = ByteLo(vk) '<<<### End If Of course, all could be solved in many other, may be better ways... Juergen.
From: Karl E. Peterson on 5 Apr 2010 14:03 Juergen Thuemmler wrote: > Hi Karl, > >> Oh oh. Is that a stinkin' AltGr char too??? > > Oh yes ;-) Grumble... >> Is this an actual or theoretical problem one? Assuming a good reason to do >> it, would this work just as well: >> >> AltGr = CBool(ByteHi(vk) And 6) >> For i = 1 To repeat >> ... >> >> Just trying to understand the multiple tests there. > > Because you use vk for different values: > > If vk Then > ' Is this an extended key? > extend = IsExtendedKey(this) > Else > ' Not a standard named key. > vk = VkKeyScan(Asc(this)) '<<<### > If ByteHi(vk) = 6 Then AltGr = True > capped = CBool(ByteHi(vk) And 1) > vk = ByteLo(vk) '<<<### > End If Oh jeez, yeah, you're a lot closer to the code than I am at this point. So, of course, that Else is stripping off the shift chars from the actual keystroke. Makes sense to stick it in there. I don't think the earlier call to GetNamedKey would ever generate such a sequence, though, right? Thanks... Karl -- ..NET: It's About Trust! http://vfred.mvps.org
From: Clive Lumb on 6 Apr 2010 04:17 "Karl E. Peterson" <karl(a)exmvps.org> a �crit dans le message de groupe de discussion : #Q$vdpO1KHA.2028(a)TK2MSFTNGP05.phx.gbl... > Juergen Thuemmler wrote: >> Hi Karl, >> >>> Oh oh. Is that a stinkin' AltGr char too??? >> >> Oh yes ;-) > > Grumble... > >>> Is this an actual or theoretical problem one? Assuming a good reason to >>> do it, would this work just as well: >>> >>> AltGr = CBool(ByteHi(vk) And 6) >>> For i = 1 To repeat >>> ... >>> >>> Just trying to understand the multiple tests there. >> >> Because you use vk for different values: >> >> If vk Then >> ' Is this an extended key? >> extend = IsExtendedKey(this) >> Else >> ' Not a standard named key. >> vk = VkKeyScan(Asc(this)) '<<<### >> If ByteHi(vk) = 6 Then AltGr = True >> capped = CBool(ByteHi(vk) And 1) >> vk = ByteLo(vk) '<<<### >> End If > > Oh jeez, yeah, you're a lot closer to the code than I am at this point. > So, of course, that Else is stripping off the shift chars from the actual > keystroke. Makes sense to stick it in there. I don't think the earlier > call to GetNamedKey would ever generate such a sequence, though, right? > > Thanks... Karl > > -- > .NET: It's About Trust! > http://vfred.mvps.org Just FYI, I replaced VkKeyScan by VkKeyScanEx (which requires the keyboard layout as a parameter) and nearly everything works with no other code changes. The ~and ` are still slightly problematic though, specially if you send `[
From: Karl E. Peterson on 6 Apr 2010 14:06
Clive Lumb wrote: > > "Karl E. Peterson" <karl(a)exmvps.org> a �crit dans le message de groupe de > discussion : #Q$vdpO1KHA.2028(a)TK2MSFTNGP05.phx.gbl... >> Juergen Thuemmler wrote: >>> Hi Karl, >>> >>>> Oh oh. Is that a stinkin' AltGr char too??? >>> >>> Oh yes ;-) >> >> Grumble... >> >>>> Is this an actual or theoretical problem one? Assuming a good reason to >>>> do it, would this work just as well: >>>> >>>> AltGr = CBool(ByteHi(vk) And 6) >>>> For i = 1 To repeat >>>> ... >>>> >>>> Just trying to understand the multiple tests there. >>> >>> Because you use vk for different values: >>> >>> If vk Then >>> ' Is this an extended key? >>> extend = IsExtendedKey(this) >>> Else >>> ' Not a standard named key. >>> vk = VkKeyScan(Asc(this)) '<<<### >>> If ByteHi(vk) = 6 Then AltGr = True >>> capped = CBool(ByteHi(vk) And 1) >>> vk = ByteLo(vk) '<<<### >>> End If >> >> Oh jeez, yeah, you're a lot closer to the code than I am at this point. So, >> of course, that Else is stripping off the shift chars from the actual >> keystroke. Makes sense to stick it in there. I don't think the earlier >> call to GetNamedKey would ever generate such a sequence, though, right? > > Just FYI, > I replaced VkKeyScan by VkKeyScanEx (which requires the keyboard layout as a > parameter) and nearly everything works with no other code changes. The ~and ` > are still slightly problematic though, specially if you send `[ I wondered about that, at one point. Since I never use alt layouts, I just didn't know how that might go. In particular, what would happen if you were to use the default language identifier, and the user had toggled to a different keyboard layout? So are you just calling GetKeyboardLayout to fill that parameter? And would this avoid the all the issues we've been talking about in this thread? -- ..NET: It's About Trust! http://vfred.mvps.org |