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From: Nicholas Kormanik on 8 Dec 2009 06:50

Trying to set up way to find the number of options contracts one can
purchase with a given amount of money. Could someone please edit the
code if needed? Or does this look okay as is?

Thanks.....


pricepercontract := .71
numbercontracts := x
feepercontract := .75
tradecomission := 9.99
totalcost := 25000

Solve[100*pricepercontract*numbercontracts*feepercontract +
tradecomission == totalcost, x]




From: DrMajorBob on 9 Dec 2009 05:44
I'd prefer something like

pricepercontract = .71;
feepercontract = .75;
tradecomission = 9.99;
totalcost = 25000;
limit = Rationalize[
100*pricepercontract*numbercontracts*feepercontract +
tradecomission <= totalcost]
Maximize[{numbercontracts, limit}, numbercontracts, Integers]

999/100 + (213 numbercontracts)/4 <= 25000

{469, {numbercontracts -> 469}}

Bobby

On Tue, 08 Dec 2009 05:43:30 -0600, Nicholas Kormanik
<nkormanik(a)gmail.com> wrote:

>
> Trying to set up way to find the number of options contracts one can
> purchase with a given amount of money. Could someone please edit the
> code if needed? Or does this look okay as is?
>
> Thanks.....
>
>
> pricepercontract := .71
> numbercontracts := x
> feepercontract := .75
> tradecomission := 9.99
> totalcost := 25000
>
> Solve[100*pricepercontract*numbercontracts*feepercontract +
> tradecomission == totalcost, x]
>
>
>
>


--
DrMajorBob(a)yahoo.com

From: Michael Stern on 9 Dec 2009 05:44
Also, a mathematica issue on top of your math issues -- you can't solve
for X in an equation that has no Xs.

Michael

Nicholas Kormanik wrote:
> Trying to set up way to find the number of options contracts one can
> purchase with a given amount of money. Could someone please edit the
> code if needed? Or does this look okay as is?
>
> Thanks.....
>
>
> pricepercontract := .71
> numbercontracts := x
> feepercontract := .75
> tradecomission := 9.99
> totalcost := 25000
>
> Solve[100*pricepercontract*numbercontracts*feepercontract +
> tradecomission == totalcost, x]
>
>
>
>
>

From: Michael Stern on 9 Dec 2009 05:41
This isn't really a Mathematica question so much as it is a basic math
question. Anyway, you have an error in that you have conflated the
number of shares (number of contracts*100) with the number of contracts,
and another error in that you are multiplying the fee times the price;
assuming that's a dollar fee, it makes no sense. Your basic equation
should look something like

total cost = ((dollar price per contract+ dollar fee per contract) *
number of contracts) + dollartradecommission

If you have been given your fee per contract or your commission in
percentage terms, the math will look a little different.

And in real life, I don't think I've ever seen both fee per contract and
commission; generally it's one or the other.

MS


On Dec 8, 2009, at 6:43 AM, Nicholas Kormanik wrote:

>
> Trying to set up way to find the number of options contracts one can
> purchase with a given amount of money. Could someone please edit the
> code if needed? Or does this look okay as is?
>
> Thanks.....
>
>
> pricepercontract := .71
> numbercontracts := x
> feepercontract := .75
> tradecomission := 9.99
> totalcost := 25000
>
> Solve[100*pricepercontract*numbercontracts*feepercontract +
> tradecomission == totalcost, x]
>
>
>
>


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