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From: tyler on 23 May 2010 02:39
These are 2 Law of Cosines equation, i need your help to solve this:

(r1+150)^2 = (r1+200)^2 + 499.1^2 -2*(r1+200) * 499.1 * cos(16.177 )

r1^2 = (r1+200)^2 + 1267.9^2 -2*(r1+200) * 1267.9* cos (teta - 16.177 )


Unknowns: r1, teta

please help me solve this using matlab!!!

Thanks

Tyler
From: Walter Roberson on 23 May 2010 11:09
tyler wrote:
> These are 2 Law of Cosines equation, i need your help to solve this:
>
> (r1+150)^2 = (r1+200)^2 + 499.1^2 -2*(r1+200) * 499.1 * cos(16.177 )
>
> r1^2 = (r1+200)^2 + 1267.9^2 -2*(r1+200) * 1267.9* cos (teta - 16.177 )
>
>
> Unknowns: r1, teta
>
> please help me solve this using matlab!!!

Expand the first equation in r1, and move everything to the same side.
You will be left with a quadratic equation independent of theta, which
you can solve directly using the usual formula. Substitute each of the
two roots into the second equation and isolate down to
cos(theta-16.177), take the arccos and add 16.177 to get the relevant
theta. No Law of Cosines needed.

Caution: be sure you know whether you are talking about 16 1/6 degrees
or 16 1/6 radians.
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