From: G on
Henri

Relativity breaks down completely when it tries to make statements
about what
light is doing when not being observed.

Intriguing: don't you mean "measured" and does it affect only light or
time
as well, aging... twins

G

From: G on
BZ

"The shifts in frequency/wavelenght observed are simply due to changes
in
distance between source and detector as the waves are being emitted and

detected. "

See how radar works : Frequency changes, wavelenght changes , speed is
the same

http://electronics.howstuffworks.com/radar.htm

http://www.crh.noaa.gov/dtx/1953beecher/radarDoppler.php

http://www.escortstore.com/policrdr.htm

G

From: The Ghost In The Machine on
In sci.physics, bz
<bz+sp(a)ch100-5.chem.lsu.edu>
wrote
on Wed, 27 Apr 2005 01:02:28 +0000 (UTC)
<Xns9644CBDF14A7AWQAHBGMXSZHVspammote(a)130.39.198.139>:
> jgreen(a)seol.net.au (Jim Greenfield) wrote in
> news:e7b5cc5d.0504261558.5dfdc8c2(a)posting.google.com:
>
>> bz <bz+sp(a)ch100-5.chem.lsu.edu> wrote in message
>> news:<Xns96314A7BC2DA3WQAHBGMXSZHVspammote(a)130.39.198.139>...
>>> jgreen(a)seol.net.au (Jim Greenfield) wrote in
>>> news:e7b5cc5d.0504062211.6957dcb5(a)posting.google.com:
>>>
>>> > ertain crystals emmit light of a fixed frequency. What is the
>>> > chemical reaction within the crystal, which causes it to alter its
>>> > emmitted wavelength, according as to how it is observed???
>>> > Hint: the wavelength emmitted by the crystal does NOT alter from its
>>> > point of view; the Doppler shift noted by the observer is due to the
>>> > change in VELOCITY.
>>> >
>>>
>>> The relative velocity between source and observer.
>>> NOT the velocity of the photons.
>>
>> DHR's claim c invariant
>> c= fu
>> We know u is invariant, because the ruby does NOT change into a
>> sapphire.
>> We know that SOMETHING changes due to the motion, as we observe the
>> doppler.
>> A little grade seven algebra tells YOU, and even Wormey, that in a
>> three part equation, when one changes (in this case f) then another
>> MUST change-----
>> it is NOT u because the ruby remained a ruby, so it IIIIIISSSSSSSSSS
>> c!!!!!!!!!
>
> Buy yourself a police lidar.
>
> stand by the road and take the doppler speed reading of an approaching car.
>
> ride in a car and take the doppler speed reading of an approaching sign.
>
> ride in a car and take the doppler speed reading of an approaching car.
>
> stand by the road, have someone with the lidar ride in a car and YOU
> measure the doppler shift of the lidar as it approaches you.
>
> In all cases, the lidar frequency remains a constant, as far as the lidar
> is concerned.
>
> In all cases, the results are consistent with the lidar photons traveling
> at a constant speed of c with relation to the source, with relation to the
> detector and with relation to any observers.
>
> The shifts in frequency/wavelenght observed are simply due to changes in
> distance between source and detector as the waves are being emitted and
> detected.
>
> If you have sufficiently sensitive equipment to measure the time-of-flight
> of the photons from the lidar, you will find that it does NOT change as the
> speed of the source or detector changes.

It would have to be pretty sensitive to pick up an error of
5 parts per quadrillion (a car is usually traveling around
30 m/s = 67.1 mph = 10^-7 c; gamma =~ 1 + 5 * 10^-15).

If lidar uses 500 nm light, 2 * 10^14 wavelengths of that light
would be 100,000 km long, wrapping around the world 2 1/2 times,
or a little more than 1/4 the distance from Earth to Moon.

[rest snipped]

--
#191, ewill3(a)earthlink.net
It's still legal to go .sigless.
From: Henri Wilson on
On 26 Apr 2005 20:48:26 -0700, "G" <gehan(a)dialog.lk> wrote:

>Henri
>
>But given the sameness (if we can assume it I think its called
>Isotropy)
>or constant expansion of the universe we can assume that the average
>for a subset of the stars of the universe will be close to the average
>for the entire universe, corrected for galalctive expansion.Surely
>there must be someone with the data and brains to do this sort of
>calucation. At NASA maybe?
>
>G

Nah! It isn't true.

Like I said, if you add up all the vector momenta in a sphere, it might equate
to zero at one particular point....but you don't know how that sphere is moving
wrt other similar spheres.

HW.
www.users.bigpond.com/hewn/index.htm

Sometimes I feel like a complete failure.
The most useful thing I have ever done is prove Einstein wrong.
From: Henri Wilson on
On Tue, 26 Apr 2005 19:19:52 -0700, "N:dlzc D:aol T:com \(dlzc\)" <N: dlzc1
D:cox T:net(a)nospam.com> wrote:

>Dear G:
>
>"G" <gehan(a)dialog.lk> wrote in message
>news:1114496604.017531.211310(a)g14g2000cwa.googlegroups.com...
>> David
>>
>> So basically in laymans terms we can say the
>> speed of light is s/t where s is the distance
>> between source and target and t is the time
>> between elapsed between switching on the
>> light source and the illumination of the target?
>> (all in the same frame)
>
>No. The speed of light is an established contant. By
>convention, it is a fixed value. The time is the measurement.
>The distance is the inference.
>
>> I thought the metre was defined in terms of
>> wavelenght
>
>It was from ~1963 until 1983. Wavelengths (and counters) are
>still used to measure things very accurately. But not
>"correctly".
>
>David A. Smith
>

'c' is universal constant. It also happens to be the speed of light relative
to its source.


HW.
www.users.bigpond.com/hewn/index.htm

Sometimes I feel like a complete failure.
The most useful thing I have ever done is prove Einstein wrong.