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From: Alan Chalker on 4 May 2010 22:56 "Amitabh Verma" <amtukv(a)gmail.com> wrote in message <hrptas$6q5$1(a)fred.mathworks.com>... > > I had a few questions on the above from the contest blog. Does the Longevity contest end at midnight Tues, UTC or run into Wed. ? > > Is the score the cumulative time spent in lead or the longest entry that was in lead ? > > Thanks. > > Best, > Amitabh > Another question is whether it's based upon submission time or scoring time. Also, please note both the stats page and the twitter feed seem to be missing some of the leaders. For example, right now leader 259 is an entry from Yi Cao, and 260 is one of my entries. However, if you look at entry # 4012 submitted by Amitabh Verma, it was in the lead for a while and should be listed as 260.
From: Alan Chalker on 5 May 2010 00:50 "Alan Chalker" <alancNOSPAM(a)osc.edu> wrote in message <hrqmo5$rac$1(a)fred.mathworks.com>... > Another question is whether it's based upon submission time or scoring time. Also, please note both the stats page and the twitter feed seem to be missing some of the leaders. For example, right now leader 259 is an entry from Yi Cao, and 260 is one of my entries. However, if you look at entry # 4012 submitted by Amitabh Verma, it was in the lead for a while and should be listed as 260. Just to clarify, depending on what your actual meaning of the mini-contest rules is and whats going on with the stats page is likely to determine who the mini-contest winner is. As of right now, the stats page shows the 2 longest entries as mine and then Yi Cao's: 259 Yi Cao tomorrow is another day. Tue 20:47 0.02% 2.96 260 Alan Chalker Auto tweaker Tue 23:45 0.00% 4.14 However I'm not sure these are correctly indicating the actual durations.
From: Oliver Woodford on 5 May 2010 05:14 "Robert Macrea" wrote > A Third Way carries out an initial scan using two rectangular overlapping scans, with the second a grid offset by half a grid width. Between them these scans take up about 80% of the available queries, and they each give a different, coarse version of the image. Every pixel has two estimated values, and if you form a combined image from their means you see an image with pixel blocks half the size of the initial scans. In effect you have faked the resolution you could get with 1.6x the permitted number of scans, which sounds good. In particular it should make smoothing more effective. Robert, sounds like we're on the same wavelength here. You are suggesting, in more concrete form, an approach I have suggested a couple of times already. Indeed, my Super Slim entry implements the first stage of just such a method, but using two overlapping scans to get 9 times the resolution rather than your 4. I think it's definitely a winning approach, but like yourself I haven't the time to implement it fully. Oliver
From: Sergey Y. on 5 May 2010 08:03 "Matthew Simoneau" <matthew(a)mathworks.com> wrote in message <hrnuck$jsr$1(a)fred.mathworks.com>... > Sergey, the contest ends Wednesday at 16:00 UTC (or 12:00 EDT): > > http://www.timeanddate.com/worldclock/fixedtime.html?month=5&day=5&year=2010&hour=16&min=0&sec=0&p1=0 > > (Remember the 10-entry-per-hour limit as we approach the deadline.) > > With respect to additional mid-contest challenges, Ned announced a longevity prize for Tuesday on the contest blog. Sorry for being so slow. What about 10-entry-per-hour limit? I can not find it.
From: Helen Chen on 5 May 2010 08:59
"Sergey Y." <ivssnn(a)yahoo.com> wrote in message <hrrmpo$k7f$1(a)fred.mathworks.com>... > > Sorry for being so slow. What about 10-entry-per-hour limit? > I can not find it. Sergey - It is 10 entries per 10 minutes not per hour. If you submit 10 entries, you will see a message that tells this. Helen |