From: Bitrex on


If you put a reference current into the collector of one half of a
differential pair, and then take an output current from the collector of
the other transistor of a differential pair, the output current as a
fraction of the reference current will be compensated against variations
of Is. However, because of the dependence of VT on temperature Vbe will
now have a positive tempco, and the output current as a fraction of
the reference current will decrease with increasing temperature of the
pair. I'm wondering what strategies the analog designers here have used
to compensate for this second-order temperature dependence? TIA!
From: miso on
On May 8, 5:19 pm, Bitrex <bit...(a)de.lete.earthlink.net> wrote:
> If you put a reference current into the collector of one half of a
> differential pair, and then take an output current from the collector of
> the other transistor of a differential pair, the output current as a
> fraction of the reference current will be compensated against variations
> of Is.  However, because of the dependence of VT on temperature Vbe will
>   now have a positive tempco, and the output current as a fraction of
> the reference current will decrease with increasing temperature of the
> pair. I'm wondering what strategies the analog designers here have used
> to compensate for this second-order temperature dependence? TIA!

Your really need to explain your circuit better. I have a gut feeling
you don't mean a differential pair since the collectors would be high
impedance and just form gain stages if fed a reference current.

From: John Larkin on
On Sat, 08 May 2010 20:19:15 -0400, Bitrex
<bitrex(a)de.lete.earthlink.net> wrote:

>
>
>If you put a reference current into the collector of one half of a
>differential pair,

You've lost me already. What do you mean by putting a current into the
collector of a diff pair? Normally one stuffs a current into the
paralleled emitters.

Can you post a schematic?

John




and then take an output current from the collector of
>the other transistor of a differential pair, the output current as a
>fraction of the reference current will be compensated against variations
>of Is. However, because of the dependence of VT on temperature Vbe will
> now have a positive tempco, and the output current as a fraction of
>the reference current will decrease with increasing temperature of the
>pair. I'm wondering what strategies the analog designers here have used
>to compensate for this second-order temperature dependence? TIA!

From: Bitrex on
John Larkin wrote:
> On Sat, 08 May 2010 20:19:15 -0400, Bitrex
> <bitrex(a)de.lete.earthlink.net> wrote:
>
>>
>> If you put a reference current into the collector of one half of a
>> differential pair,
>
> You've lost me already. What do you mean by putting a current into the
> collector of a diff pair? Normally one stuffs a current into the
> paralleled emitters.
>
> Can you post a schematic?
>
> John
>
>

Sorry for not being more clear - in the meantime I was able to find a
website that has an example of the circuit configuration I am talking
about here, figure 3:

http://www.uni-bonn.de/~uzs159/

It appears from the text the most common way to compensate the 1/T
temperature dependence of the circuit is to use a resistor with a
positive temperature coefficient in the circuit that provides the
control voltage. To make it work well I guess you would want to bind
the differential pair to the tempco resistor with some kind of thermally
conductive adhesive.



>
> and then take an output current from the collector of
>> the other transistor of a differential pair, the output current as a
>> fraction of the reference current will be compensated against variations
>> of Is. However, because of the dependence of VT on temperature Vbe will
>> now have a positive tempco, and the output current as a fraction of
>> the reference current will decrease with increasing temperature of the
>> pair. I'm wondering what strategies the analog designers here have used
>> to compensate for this second-order temperature dependence? TIA!
>
From: miso on
On May 8, 8:01 pm, Bitrex <bit...(a)de.lete.earthlink.net> wrote:
> John Larkin wrote:
> > On Sat, 08 May 2010 20:19:15 -0400, Bitrex
> > <bit...(a)de.lete.earthlink.net> wrote:
>
> >> If you put a reference current into the collector of one half of a
> >> differential pair,
>
> > You've lost me already. What do you mean by putting a current into the
> > collector of a diff pair? Normally one stuffs a current into the
> > paralleled emitters.
>
> > Can you post a schematic?
>
> > John
>
> Sorry for not being more clear - in the meantime I was able to find a
> website that has an example of the circuit configuration I am talking
> about here, figure 3:
>
> http://www.uni-bonn.de/~uzs159/
>
> It appears from the text the most common way to compensate the 1/T
> temperature dependence of the circuit is to use a resistor with a
> positive temperature coefficient in the circuit that provides the
> control voltage.  To make it work well I guess you would want to bind
> the differential pair to the tempco resistor with some kind of thermally
> conductive adhesive.
>
>
>
> >  and then take an output current from the collector of
> >> the other transistor of a differential pair, the output current as a
> >> fraction of the reference current will be compensated against variations
> >> of Is.  However, because of the dependence of VT on temperature Vbe will
> >>  now have a positive tempco, and the output current as a fraction of
> >> the reference current will decrease with increasing temperature of the
> >> pair. I'm wondering what strategies the analog designers here have used
> >> to compensate for this second-order temperature dependence? TIA!

Looks like frames did you a disservice. It this the page in question?
http://www.uni-bonn.de/~uzs159/expo_tutorial/index.html

If not, then right click on the link in question and open it in
another window to get the correct URL.