String Parse Help for novice
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From: Karl DeSaulniers on 13 Jun 2010 18:35 On Jun 13, 2010, at 5:31 PM, Ashley Sheridan wrote: > On Sun, 2010-06-13 at 17:27 -0500, Karl DeSaulniers wrote: > >> On Jun 13, 2010, at 5:23 PM, Ashley Sheridan wrote: >> >>> On Sun, 2010-06-13 at 18:13 -0400, Rick Dwyer wrote: >>> >>>> Hello List. >>>> >>>> I need to parse the PATH portion of URL. I have assigned the path >>>> portion to a variable using the following: >>>> >>>> $thepath = parse_url($url); >>>> >>>> >>>> Now I need to break each portion of the path down into its own >>>> variable. The problem is, the path can vary considerably as >>>> follows: >>>> >>>> /mydirectory/mysubdirectory/anothersubdirectory/mypage.php >>>> >>>> vs. >>>> >>>> /mydirectory/mypage.php >>>> >>>> How do I get the either of the above url paths broken out so the >>>> variables equal the following >>>> >>>> $dir1 = mydirectory >>>> $dir2 = mysubdirectory >>>> $dir3 = anothersubdirectory >>>> $page = mypage.php >>>> >>>> ...etc... if there were 5 more subdirectories... they would be >>>> dynamically assigned to a variable. >>>> >>>> Thanks for any help. >>>> >>>> --Rick >>>> >>>> >>>> >>> >>> >>> $filename = basename($path); >>> $parts = explode('/', $path); >>> $directories = array_pop($parts); >>> >>> Now you have your directories in the $directories array and the >>> filename >>> in $filename. >>> >>> Thanks, >>> Ash >>> http://www.ashleysheridan.co.uk >>> >>> >> >> >> Hi Ash, >> What about the "//" in the beginning? >> >> >> Karl DeSaulniers >> Design Drumm >> http://designdrumm.com >> >> > > > As your example string didn't have a double slash I didn't write code > for that, but it's easy enough to remove 0-length strings from the > $directories array. > > Thanks, > Ash > http://www.ashleysheridan.co.uk > > :) Rick's example, but how in your example do we look for a double forward slash? THX Karl DeSaulniers Design Drumm http://designdrumm.com
From: Rick Dwyer on 13 Jun 2010 18:35 OK, I get the following error: Warning: basename() expects parameter 1 to be string, array given in.... When I use the following: $thepath = parse_url($url); $filename = basename($thepath); Is my variable thepath not automatically string? --Rick On Jun 13, 2010, at 6:23 PM, Ashley Sheridan wrote: > On Sun, 2010-06-13 at 18:13 -0400, Rick Dwyer wrote: >> >> Hello List. >> >> I need to parse the PATH portion of URL. I have assigned the path >> portion to a variable using the following: >> >> $thepath = parse_url($url); >> >> >> Now I need to break each portion of the path down into its own >> variable. The problem is, the path can vary considerably as follows: >> >> /mydirectory/mysubdirectory/anothersubdirectory/mypage.php >> >> vs. >> >> /mydirectory/mypage.php >> >> How do I get the either of the above url paths broken out so the >> variables equal the following >> >> $dir1 = mydirectory >> $dir2 = mysubdirectory >> $dir3 = anothersubdirectory >> $page = mypage.php >> >> ...etc... if there were 5 more subdirectories... they would be >> dynamically assigned to a variable. >> >> Thanks for any help. >> >> --Rick >> >> >> > > $filename = basename($path); > $parts = explode('/', $path); > $directories = array_pop($parts); > > Now you have your directories in the $directories array and the > filename in $filename. > > Thanks, > Ash > http://www.ashleysheridan.co.uk > >
From: Karl DeSaulniers on 13 Jun 2010 18:39 On Jun 13, 2010, at 5:35 PM, Rick Dwyer wrote: > OK, I get the following error: > > Warning: basename() expects parameter 1 to be string, array given > in.... > > When I use the following: > > $thepath = parse_url($url); > $filename = basename($thepath); > > Is my variable thepath not automatically string? > > --Rick > > try echo($url); and see Karl DeSaulniers Design Drumm http://designdrumm.com
From: Ashley Sheridan on 13 Jun 2010 18:40 On Sun, 2010-06-13 at 17:35 -0500, Karl DeSaulniers wrote: > On Jun 13, 2010, at 5:31 PM, Ashley Sheridan wrote: > > > On Sun, 2010-06-13 at 17:27 -0500, Karl DeSaulniers wrote: > > > >> On Jun 13, 2010, at 5:23 PM, Ashley Sheridan wrote: > >> > >>> On Sun, 2010-06-13 at 18:13 -0400, Rick Dwyer wrote: > >>> > >>>> Hello List. > >>>> > >>>> I need to parse the PATH portion of URL. I have assigned the path > >>>> portion to a variable using the following: > >>>> > >>>> $thepath = parse_url($url); > >>>> > >>>> > >>>> Now I need to break each portion of the path down into its own > >>>> variable. The problem is, the path can vary considerably as > >>>> follows: > >>>> > >>>> /mydirectory/mysubdirectory/anothersubdirectory/mypage.php > >>>> > >>>> vs. > >>>> > >>>> /mydirectory/mypage.php > >>>> > >>>> How do I get the either of the above url paths broken out so the > >>>> variables equal the following > >>>> > >>>> $dir1 = mydirectory > >>>> $dir2 = mysubdirectory > >>>> $dir3 = anothersubdirectory > >>>> $page = mypage.php > >>>> > >>>> ...etc... if there were 5 more subdirectories... they would be > >>>> dynamically assigned to a variable. > >>>> > >>>> Thanks for any help. > >>>> > >>>> --Rick > >>>> > >>>> > >>>> > >>> > >>> > >>> $filename = basename($path); > >>> $parts = explode('/', $path); > >>> $directories = array_pop($parts); > >>> > >>> Now you have your directories in the $directories array and the > >>> filename > >>> in $filename. > >>> > >>> Thanks, > >>> Ash > >>> http://www.ashleysheridan.co.uk > >>> > >>> > >> > >> > >> Hi Ash, > >> What about the "//" in the beginning? > >> > >> > >> Karl DeSaulniers > >> Design Drumm > >> http://designdrumm.com > >> > >> > > > > > > As your example string didn't have a double slash I didn't write code > > for that, but it's easy enough to remove 0-length strings from the > > $directories array. > > > > Thanks, > > Ash > > http://www.ashleysheridan.co.uk > > > > > > :) Rick's example, but how in your example do we look for a double > forward slash? > THX > > Karl DeSaulniers > Design Drumm > http://designdrumm.com > > You don't look for one, that's the point. The explode() breaks the string into an array at every occurrence of a '/' character. This will leave zero length strings in the array if there is a double // (which wasn't in any given example in this thread that I saw) When you use the array, just don't do anything with empty elements! Thanks, Ash http://www.ashleysheridan.co.uk
From: Karl DeSaulniers on 13 Jun 2010 18:41 On Jun 13, 2010, at 5:35 PM, Rick Dwyer wrote: > OK, I get the following error: > > Warning: basename() expects parameter 1 to be string, array given > in.... > > When I use the following: > > $thepath = parse_url($url); > $filename = basename($thepath); > > Is my variable thepath not automatically string? > > --Rick > Oops I meant echo($the_path); or echo both and see. Karl DeSaulniers Design Drumm http://designdrumm.com
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