From: Barry Schwarz on 8 Aug 2010 17:54 On Sun, 8 Aug 2010 06:56:54 -0700 (PDT), Tom Abernathy <tom.abernathy(a)gmail.com> wrote: >If you have want to get the last one as another character variable >then use the SCAN function. > >last_date = scan(date,-1,'>'); You probably want scan(date, -1, '->'). > >If you want to convert it to an actual date then use the INPUT >function. > >ldate = input(last_date,??yymmdd.); >format ldate yymmddn8.; > > >On Aug 8, 8:27�am, Rob Roszkowski <rob.roszkow...(a)gmail.com> wrote: >> Hi everyone, >> >> I have a real problem on my hands that I need to resolve asap but I >> don't know how as I have never come across this problem. If anyone can >> figure this out I truly thank deeply. >> >> I have a data set (one of 100) where the date column comes up like >> this : >> >> Date: >> 20050122->20060121->20070120 >> 20050122->20060121->20070120 >> 20050122->20060121->20070120 >> 20050122->20060121->20070120 >> 20050122 >> 20050123 >> 20050122->20060121 >> 20050256 >> 20050122->20060121 -- Remove del for email
|
Pages: 1 Prev: ODS RTF - Grouping Next: Estimating the value for the functional form of the variance |