From: Karina on 25 Jan 2010 20:18 Dear Peter, for you code below, what seems to be the value of "siz"? And what means " invert quadrants due to fft shift"? What is the final result - which values? Would be very helpful! "Peter Bone" <peterbone(a)hotmail.com> wrote in message <ft4uti$a7o$1(a)fred.mathworks.com>... > "akane ajibana" <androalpha_v7(a)yahoo.com> wrote in message > <fsnera$t69$1(a)fred.mathworks.com>... > > hi everyone.. > > i have need help on template matching. i have an image that > > need to be match with 3 subimage(template images).can anyone > > teach me on the coding in Matlab > > The images cannot be different sizes so you will have to pad > out the smaller image with zeros to make it the same size. > The images must also be square. > > % fourier transform both images > fi = fft2(i); > fr = fft2(ref); > > % perform phase correlation (amplitude is normalized) > fc = fi .* conj(fr); > fcn = fc ./ abs(fc); > c = real(ifft2(fcn)); > > % find the peak in the correlation plane > [v index] = max(c(:)); > [y x] = ind2sub(siz,index); > % invert quadrants due to fft shift > mid = siz(1) / 2; > y = y - sign(y-mid-0.5) * mid; > x = x - sign(x-mid-0.5) * mid; > |