From: Bob Cain on
Alan Smaill wrote:
> Phil Carmody <thefatphil_demunged(a)yahoo.co.uk> writes:
>>
>> Can I have a coffee without milk?
>> I'm sorry, we don't have any milk.
>> Ah, OK, how about a coffee without cream?
>
> like the silent "k" in "frying pan"
>

Note to Lester. The above contains demonstrations of wit. Perhaps,
by example, you can learn something both about wit and about
demonstration.


Bob
--

"Things should be described as simply as possible, but no simpler."

A. Einstein
From: Virgil on
In article <4626610e(a)news2.lightlink.com>,
Tony Orlow <tony(a)lightlink.com> wrote:

> Virgil wrote:
> > In article <46250ea8(a)news2.lightlink.com>,
> > Tony Orlow <tony(a)lightlink.com> wrote:
> >
> >> In all fairness to Lester
> >
> > Why bother to be fair to one who is so compulsively unfair?
>
> To set a good example?

But when you strive so hard in so many other other ways not to do so,
why this one exception?
From: Mike Kelly on
On Apr 18, 8:04 pm, Tony Orlow <t...(a)lightlink.com> wrote:
> Mike Kelly wrote:
> > On 18 Apr, 06:17, Tony Orlow <t...(a)lightlink.com> wrote:
> >> Mike Kelly wrote:
>
> >> < snippery >
>
> >>> You've lost me again. A bad analogy is like a diagonal frog.
> >>> --
> >>> mike.
> >> Transfinite cardinality makes very nice equivalence classes based almost
> >> solely on 'e',
>
> > Why "almost solely"?
>
> The successor relation is a relation not related to 'e' except in a
> particular model of the naturals upo which the rest is built.

What does this have to do with cardinality? Anyway, every relation in
set theory is built up solely from 'e'. You can keep denying this if
you like but it's just a rather bizarre thing to do.

> >> but in my opinion doesn't produce believable results.
>
> > Which "results" of cardinality are not believable? You don't think the
> > evens and the naturals and the rationals are mutually bijectible? Or
> > you do think the reals and the naturals are bijectible? Or did you
> > mean you have a problem not with what cardinality actually is but with
> > what you hallucinate cardinality to be?
>
> As long as transfinite "equivalence" classes are referred to as such,
> and not said to denote "equal" size or numerosity, then I have no problem.

Ahh, progress. Well, nice to see you are not an incurable crank. Well
done.

> >> I'm working on a better theory, bit by bit.
>
> > You have never managed to articulate a problem with what cardinality
> > actually says (all it says is which sets are bijectbile). You've never
> > managed to explain the motivation behind your "better theory". I don't
> > even know whether your ideas are supposed to be formulated in ZF or in
> > something else, possibly a new foundation of your own devising(or,
> > perhaps, never formalised at all?). FWIW I don't think it would be
> > very hard to define, say, "density in the naturals" in ZF. I just
> > don't see the motivation behind doing so.
>
> The idea is to create a method that works for comparing countable and
> uncountable sets alike, and properly defining the relationship between
> the two.

Well you haven't really elucidated anything there. But you're free to
keep trying.

> >> I think trying to base
> >> everything on 'e' is a mistake, since no infinite set can be defined
> >> without some form of '<'. I think the two need to be introduced together.
>
> > But you are, in fact, completely mistaken here. Several people have
> > told you this. You have some inability to acknowledge this. Oh well.

No response :-[

> > PS you snipped a lot of my post; maybe you found it boring. I find
> > your evasiveness quite interesting, though. What does cardinality
> > claim to tell that it can't?
>
> I suppose it's more the way it's spoken about. Leave out "size" and
> "equinumerous" and talk about "equivalence classes" and not "equality",
> and I have no problem

Great.

> with the consistency of standard theory.

Dunno what this has to do with consistency.

--
mike.

From: MoeBlee on
On Apr 18, 12:13 pm, Tony Orlow <t...(a)lightlink.com> wrote:
> MoeBlee wrote:
> > On Apr 17, 10:02 am, Tony Orlow <t...(a)lightlink.com> wrote:
>
> >> I am saying it's obvious that any countable set has a well ordering. It
> >> is not obvious for uncountable sets.
>
> > It's not only obvious, but it's trivial to prove that every countable
> > set has a well ordering.
>
> > So, just to be sure you understand, what is at stake with an axiom of
> > countable choice is not at all that every countable set has a well
> > ordering (since we don't need any choice principle to prove that) but
> > rather that for any countable set there is a function that chooses
> > exactly one member from every nonempty subset of that countable set
> > (and actually, we need concern ourselves only with denumerable sets,
> > since we don't need a choice principle to prove that for every finite
> > set there is a function that chooses exactly one member from every
> > nonempty subset of the finite set).
>
> > MoeBlee
>
> It's not trivial to prove any such thing for an uncountable set.

Right.

>That
> requires full Choice, does it not?

I'm pretty sure full choice is needed (not just dependent choice).

> In fact, it was Virgil, I believe,
> who said that was the MOTIVATION behind Zermelo's formulation of Choice,
> so that ALL sets could be considered well orderable.

Virgil may have said that, I don't know. Anyway, I said it also.

> However, while I
> see that a choice function produces a well ordering for any countable
> set, I don't see that it does for an uncountable set.

You MISSED my point COMPLETELY. We don't need choice to show that any
countable set has a well ordering. Think about it for a minute, and
you'll see how to prove it.

As to how choice provides a well ordering on any set S, most basically
(quite oversimplified), whenever we need to have a least element, we
let the choice function pick it for us. Again, that is wildly
oversimplified. But any set theory textbook will give you a proof. To
supplement Enderton and Suppes, I recommend Stoll, since Enderton and
Suppes use the axiom schema of replacement for certain of axiom of
choice equivalence proofs while Stoll proves some of those theorems
withOUT using the axiom schema of replacement.

> Maybe I am confused about something. Can a well ordering include an
> uncountable number of limit elements?

If I'm not mistaken, yes. We just need to see that there are ordinals
that have uncountably many members that are limit ordinals (I think
that is right).

> If so, then I can see how such a
> well ordering could occur. Are limit elements which are an infinite
> number of limit elements beyond the first what are called "inaccessible"
> limit ordinals?

I dont' think so, though I'm not expert on this. I know the definition
of 'inaccessible cardinal' and just a few things about them, but I
haven't yet studied them in depth or detail. I very much suggest you
too learn the basics before getting off into inacessible cardinals and
such. You run WAY ahead of yourself when you still don't even
understand the nature of the membership relation in terms of set
theory.

> If this is the case, then I guess I can see that in this
> sense, one could concoct a well ordering. But, no, then there would
> exist an infinite descending sequence of limit ordinals withoin the well
> order. So, that wouldn't work, right. I just don't see that a well order
> can be accomplished in principle on an uncountable set, whether one
> declares an axiom to that effect of not.

You just need to learn it theorem by theorem from the axioms. All it
takes is an introductory set theory textbook, and all of them will
prove the well ordering theorem for you.

MoeBlee

From: Virgil on
In article <46266273(a)news2.lightlink.com>,
Tony Orlow <tony(a)lightlink.com> wrote:

> Virgil wrote:
> > In article <46251314(a)news2.lightlink.com>,
> > Tony Orlow <tony(a)lightlink.com> wrote:
> >
> >
> >> But, I have a question. What, exactly, is the difference between
> >> "equality" and "equivalence"?
> >
> > "Equality" usually means being the same in every detectable respect.
> > "equivalent" usually means the same in one respect, or in a limited
> > number of respects, while still possibly distinguishable in other
> > respects.
> >
> >
> > For example, parity of a natural number is an equivalence.
> >
> > Naturals having the same parity (evenness or oddness) are equivalent
> > with respect to parity even though not equal as natural numbers.
> >
> > 1 and 3 are equivalent with respect to parity but are not equal.
>
> Right. I stand corrected. Thanks you.
>
> But, the question remains in this regard. How do we know we have
> actually looked at all possible respects in which could compare? When we
> know of some way in which two things differ, but under a limited set of
> criteria they are not distinguishable, I can see that they are
> "equivalent" in that "respect". But, how can we be sure that we have
> actually taken into account all respects in which two objects may be
> compared?

By considering context!

"George Washington" and "the first two term President of the United
States" are the same in some respects and different in others, so one
must consider the context in which they are being compared to determine
whether they are at best equivalent or actually equal in all respects
relevant to that context.

There are contexts in which '1.000...' and '0.999...' are considered
equal, and others in which they are considered no more than equivalent,
and in some contexts perhaps not even that.