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From: Aishwarya on 21 Jul 2010 17:29
Hello All,
I want to translate a matrix spatially up and down.The following code worked for translating the matrix right and left but I am stuck with doing the up and down translation.Kindly help.

i=1;
fid = fopen('Src4Det5.bin','r+');
a = fread(fid,'double');
a=reshape(a,120,120);
figure,imagesc(a);
a=reshape(a,1,14400);
b=zeros(size(a));
for j=1:size(a(:))-3000
b(j)=a(j+3000);
end
A_MCP(i,:) = b;
size(b)
b=reshape(b,120,120);
figure,imagesc(b);
From: Walter Roberson on 21 Jul 2010 18:03
Aishwarya wrote:

> I want to translate a matrix spatially up and down.The following code
> worked for translating the matrix right and left but I am stuck with
> doing the up and down translation.Kindly help.
>
> i=1;
> fid = fopen('Src4Det5.bin','r+');
> a = fread(fid,'double');
> a=reshape(a,120,120);
> figure,imagesc(a);
> a=reshape(a,1,14400);
> b=zeros(size(a));
> for j=1:size(a(:))-3000
> b(j)=a(j+3000);
> end
> A_MCP(i,:) = b;
> size(b)
> b=reshape(b,120,120);
> figure,imagesc(b);

You asked the same question the other day but did not reply to the comments
given then.

B1 = horzcat(zeros(K,size(a,2)).A)

would have "A" as its right-hand side, moved right by K positions.

B2 = B1(K+1:end,:)

would drop the first K columns of B1, moving it left by K positions.


B3 = vertcat(A, zeros(size(a,1),J))

would have "A" as its top, moved up by J positions.

B4 = B3(:1:end-J)

would drop the bottom J columns of B3, moving it down by J positions.
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