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From: Michael Stemper on 29 Jul 2010 09:12 In article <8bd5sqFrciU1(a)mid.individual.net>, =?ISO-8859-1?Q?Jos=E9_Carlos_Santos?= <jcsantos(a)fc.up.pt> writes: >On 29-07-2010 11:12, William Elliot wrote: >> What are the solutions to the equations >> >> sin^-1 x = 1/sin x, > >Obviously, it has one and only one solution, namely 0. Huh? sin(0) = 0, so what's i/sin(0) ? -- Michael F. Stemper #include <Standard_Disclaimer> Indians scattered on dawn's highway bleeding; Ghosts crowd the young child's fragile eggshell mind.
From: Ray Vickson on 29 Jul 2010 12:25 On Jul 29, 4:14 am, José Carlos Santos <jcsan...(a)fc.up.pt> wrote: > On 29-07-2010 11:12, William Elliot wrote: > > > What are the solutions to the equations > > > sin^-1 x = 1/sin x, > > Obviously, it has one and only one solution, namely 0. A reveals a solution near 0.9. Maple gives: fsolve(arcsin(x)=1/sin(x),x=.8.. .95); 0.9440390666 <---- numerical solution Certainly, x = 0 is not a solution. > > > cos^-1 x = 1/cos x? > > It has one and only one solution, around 0.739085. I doubt that it is > "nice" number. Again, a plot reveals a solution near 0.4 and Maple gives fsolve(arccos(x)=1/cos(x),x=.4 .. .8); 0.4460476800 <--- numerical solution R.G. Vickson > > Best regards, > > Jose Carlos Santos
From: Passerby on 29 Jul 2010 14:19 On Thu, 29 Jul 2010 03:12:10 -0700, William Elliot <marsh(a)rdrop.remove.com> wrote: >What are the solutions to the equations > > sin^-1 x = 1/sin x, x ~~ +-0.9440390666116078... > > cos^-1 x = 1/cos x? x ~~ 0.446047679999125754...
From: gudi on 29 Jul 2010 15:22 On Jul 29, 3:12 pm, William Elliot <ma...(a)rdrop.remove.com> wrote: > What are the solutions to the equations > > sin^-1 x = 1/sin x, > > cos^-1 x = 1/cos x? The only real roots are approx 0.944039 and 0.446048 respectively, and the periodic complex roots ( period = pi ) can be iterated from complex Newton-Raphson. Narasimham
From: gudi on 29 Jul 2010 15:29 On Jul 29, 3:12 pm, William Elliot <ma...(a)rdrop.remove.com> wrote: > What are the solutions to the equations > > sin^-1 x = 1/sin x, > > cos^-1 x = 1/cos x? The only real roots are approx (+/-)0.944039 and 0.446048 respectively, and the periodic complex roots ( period = pi ) can be iterated from complex Newton-Raphson method. Narasimham
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