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From: 2.7182818284590... on 25 Jul 2010 15:57
Calculate the voltage of this cell:
Zn|1 M Zn2+||1 M Ni2+|Ni

Given:
Zn2+ + 2e- ----> Zn V=-0.763
Ni2+ + 2e- ----> Ni V=-0.250

The way I look at it:
1. One thing gets further oxidized, and the other thing gets reduced.
2. Since both potentials are < 0, this reaction should NOT occur.
Furthermore,
3. one of the reactions CAN'T be Zn --> Zn2+ + 2e-, simply because
you don't have any Zn to start off with! You only have Zn2+.

However, the solution says that this occurs with a volate of 0.513,
which is +0.763 - 0.250.

Please explain.
From: Robert Higgins on 25 Jul 2010 16:42
On Jul 25, 3:57 pm, "2.7182818284590..." <tangent1...(a)gmail.com>
wrote:
> Calculate the voltage of this cell:
> Zn|1 M Zn2+||1 M Ni2+|Ni
>
> Given:
> Zn2+    +    2e-    ---->     Zn          V=-0.763
> Ni2+     +    2e-    ---->     Ni           V=-0.250
>
> The way I look at it:
> 1.  One thing gets further oxidized, and the other thing gets reduced.
> 2.  Since both potentials are < 0, this reaction should NOT occur.
> Furthermore,
> 3.  one of the reactions CAN'T be Zn --> Zn2+ + 2e-,    simply because
> you don't have any Zn to start off with!  You only have Zn2+.
>
> However, the solution says that this occurs with a volate of 0.513,
> which is +0.763 - 0.250.
>
> Please explain.

Please do your own homework problems, preferably after studying first.
From: Autymn D. C. on 26 Jul 2010 17:34
On Jul 25, 12:57 pm, "2.7182818284590..." <tangent1...(a)gmail.com>
wrote:
> Calculate the voltage of this cell:
> Zn|1 M Zn2+||1 M Ni2+|Ni
>
> Given:
> Zn2+    +    2e-    ---->     Zn          V=-0.763
> Ni2+     +    2e-    ---->     Ni           V=-0.250
>
> The way I look at it:
> 1.  One thing gets further oxidized, and the other thing gets reduced.
> 2.  Since both potentials are < 0, this reaction should NOT occur.
> Furthermore,
> 3.  one of the reactions CAN'T be Zn --> Zn2+ + 2e-,    simply because
> you don't have any Zn to start off with!  You only have Zn2+.
>
> However, the solution says that this occurs with a volate of 0.513,
> which is +0.763 - 0.250.
>
> Please explain.

"Given" is for your calculations and not the input.
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