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From: Abder-rahman Ali on 7 Jul 2010 11:48
I came across the following script from "Why's poignant guide to Ruby".

http://pastie.org/1034445

And, I have included my questions as comments in the script.

Please let me know what you think.

Thanks.
--
Posted via http://www.ruby-forum.com/.

From: Jesús Gabriel y Galán on 7 Jul 2010 12:13
On Wed, Jul 7, 2010 at 5:48 PM, Abder-rahman Ali
<abder.rahman.ali(a)gmail.com> wrote:
> I came across the following script from "Why's poignant guide to Ruby".
>
> http://pastie.org/1034445
>
> And, I have included my questions as comments in the script.
>
> Please let me know what you think.

def wipe_mutterings_from( sentence )
unless sentence.respond_to? :include? # What is meant by this statement?
raise ArgumentError, "cannot wipe mutterings from a #{ sentence.class }"
end

This statement is calling the respond_to? method of the object refered
by the variable sentence:

http://ruby-doc.org/core/classes/Object.html#M000331

If the method returns true, it means that the object can be sent the
message :include?, that you can call the method #include? of that
object. For example:

irb(main):010:0> [].respond_to? :include?
=> true
irb(main):011:0> "test".respond_to? :include?
=> true
irb(main):012:0> class A
irb(main):013:1> end
=> nil
irb(main):014:0> a = A.new
=> #<A:0xb73f5f2c>
irb(main):015:0> a.respond_to? :include?
=> false
irb(main):016:0> class B
irb(main):017:1> def include?
irb(main):018:2> "test"
irb(main):019:2> end
irb(main):020:1> end
=> nil
irb(main):021:0> b = B.new
=> #<B:0xb73e71fc>
irb(main):022:0> b.respond_to? :include?
=> true



while sentence.include? '('
open = sentence.index( '(' )
close = sentence.index) ')', open) # Why the "open" here?


Check the #index method of String (possibly sentence is a String,
cause the code is checking for substrings):

http://ruby-doc.org/core/classes/String.html#M000784

If you pass a second argument, the search for the substring is started
at that offset from the beginning. In the above snippet, it's checking
for the first ')' after a '('.

sentence[open..close] = '' if close # How is this sentence read?
And, is [open..close] and array AND range?

Check the #[]= method of String:

http://ruby-doc.org/core/classes/String.html#M000772

When passed a range, it's referring to the characters that start and
end at the first and last value of the range, and will substitute the
left hand side (an empty string) for the characters between those
offsets. Basically it's saying: take the substring starting at the
offset "open" and ending at the offset "close" and remove it (sub by
an empty string).

end
end

Hope this helps,

Jesus.

From: Abder-rahman Ali on 7 Jul 2010 15:19
Thanks a lot for your thorough explanation. Really appreciate it.
--
Posted via http://www.ruby-forum.com/.

From: Abder-rahman Ali on 11 Jul 2010 12:26
Hi,

Regarding this part:

sentence[open..close] = '' if close

You explained what it means, but I just want to ask, what is ---> if
close?

Thanks.
--
Posted via http://www.ruby-forum.com/.

From: Colin Bartlett on 11 Jul 2010 12:58
[Note: parts of this message were removed to make it a legal post.]

On Sun, Jul 11, 2010 at 5:26 PM, Abder-rahman Ali <
abder.rahman.ali(a)gmail.com> wrote:

> Hi,
>
> Regarding this part:
>
> sentence[open..close] = '' if close
>
> You explained what it means, but I just want to ask, what is ---> if
> close?
>
You can modify a statment with "if" or "unless".
A short *almost* (but not quite) accurate statement is that it is a
shorthand way of writing:

if close
sentence[open..close] = ''
end

# or

if close then
sentence[open..close] = ''
end

There's a fuller explanation here:
http://ruby-doc.org/docs/ProgrammingRuby/html/tut_expressions.html
at "If and Unless Modifiers"

You can also use "while" and "until" as statement modifiers(see Loops
further down that page), but there is, as Programming Ruby says, a
"wrinkle":
"There's one wrinkle when while and until are used as statement modifiers.
If the statement they are modifying is a begin/end block, the code in the
block will always execute at least one time, regardless of the value of the
boolean expression."

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