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From: John Larkin on 4 May 2010 22:45
On Tue, 4 May 2010 18:07:37 -0700 (PDT), Allen Bong
<allenbsf6502(a)gmail.com> wrote:

>On May 5, 3:44�am, John Larkin
><jjlar...(a)highNOTlandTHIStechnologyPART.com> wrote:
>> On Mon, 3 May 2010 23:15:29 -0700 (PDT), Allen Bong
>>
>>
>>
>>
>>
>> <allenbsf6...(a)gmail.com> wrote:
>> >Hi,
>>
>> >I have been playing with op-amp for the past few weeks and I came
>> >across this circuit
>>
>> >http://www.flickr.com/photos/11236051(a)N08/4577591378/sizes/o/
>>
>> >If I am correct, the gain of op-amp U1:B is 2, as (R1+R18)/R18 = 20/10
>> >= 2.
>>
>> >But what's the gain of op-amp U1:A ? �I cant find the resistor which
>> >is going to ground.
>>
>> >TIA,
>>
>> >Allen
>>
>> Wow, that is one ugly circuit!
>>
>> John- Hide quoted text -
>>
>> - Show quoted text -
>
>John,
>
>I agreed with you the design is messy. Do you have a better one that
>does the same job? It must be compact and simple.
>
>Allen

What is it supposed to do?

John

From: Allen Bong on 5 May 2010 00:36
On May 5, 10:45 am, John Larkin
<jjlar...(a)highNOTlandTHIStechnologyPART.com> wrote:
> On Tue, 4 May 2010 18:07:37 -0700 (PDT), Allen Bong
>
>
>
>
>
> <allenbsf6...(a)gmail.com> wrote:
> >On May 5, 3:44 am, John Larkin
> ><jjlar...(a)highNOTlandTHIStechnologyPART.com> wrote:
> >> On Mon, 3 May 2010 23:15:29 -0700 (PDT), Allen Bong
>
> >> <allenbsf6...(a)gmail.com> wrote:
> >> >Hi,
>
> >> >I have been playing with op-amp for the past few weeks and I came
> >> >across this circuit
>
> >> >http://www.flickr.com/photos/11236051(a)N08/4577591378/sizes/o/
>
> >> >If I am correct, the gain of op-amp U1:B is 2, as (R1+R18)/R18 = 20/10
> >> >= 2.
>
> >> >But what's the gain of op-amp U1:A ?  I cant find the resistor which
> >> >is going to ground.
>
> >> >TIA,
>
> >> >Allen
>
> >> Wow, that is one ugly circuit!
>
> >> John- Hide quoted text -
>
> >> - Show quoted text -
>
> >John,
>
> >I agreed with you the design is messy.  Do you have a better one that
> >does the same job?  It must be compact and simple.
>
> >Allen
>
> What is it supposed to do?
>
> John- Hide quoted text -
>
> - Show quoted text -

The circuit is a acoustic guitar active pickup circuit. It was in a
small metal case mounted to the side of the hollow guitar powered by
a
small 9V battery. the 4 volume controls are tone controls each
taking
care of a range of frequencies.

Allen
From: Tim Wescott on 5 May 2010 02:35
Allen Bong wrote:
> On May 5, 10:45 am, John Larkin
> <jjlar...(a)highNOTlandTHIStechnologyPART.com> wrote:
>> On Tue, 4 May 2010 18:07:37 -0700 (PDT), Allen Bong
>>
>>
>>
>>
>>
>> <allenbsf6...(a)gmail.com> wrote:
>>> On May 5, 3:44 am, John Larkin
>>> <jjlar...(a)highNOTlandTHIStechnologyPART.com> wrote:
>>>> On Mon, 3 May 2010 23:15:29 -0700 (PDT), Allen Bong
>>>> <allenbsf6...(a)gmail.com> wrote:
>>>>> Hi,
>>>>> I have been playing with op-amp for the past few weeks and I came
>>>>> across this circuit
>>>>> http://www.flickr.com/photos/11236051(a)N08/4577591378/sizes/o/
>>>>> If I am correct, the gain of op-amp U1:B is 2, as (R1+R18)/R18 = 20/10
>>>>> = 2.
>>>>> But what's the gain of op-amp U1:A ? I cant find the resistor which
>>>>> is going to ground.
>>>>> TIA,
>>>>> Allen
>>>> Wow, that is one ugly circuit!
>>>> John- Hide quoted text -
>>>> - Show quoted text -
>>> John,
>>> I agreed with you the design is messy. Do you have a better one that
>>> does the same job? It must be compact and simple.
>>> Allen
>> What is it supposed to do?
>>
>> John- Hide quoted text -
>>
>> - Show quoted text -
>
> The circuit is a acoustic guitar active pickup circuit. It was in a
> small metal case mounted to the side of the hollow guitar powered by
> a
> small 9V battery. the 4 volume controls are tone controls each
> taking
> care of a range of frequencies.
>
> Allen

With four tone control knobs it's something between a graphics equalizer
and a tone control. Those are the two terms to search on for circuits.

--
Tim Wescott
Control system and signal processing consulting
www.wescottdesign.com
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