From: Bret Cahill on
Does this look familiar?

Wolfram Alpha won't plot it.

An alternate form:

[ (3 integral |(e^(-3 i t)-e^(3 i t)) (e^(-3 i t)+e^(3 i t))|
dt) ] / (6 t-sin(6 t))


Bret Cahill




From: Ray Vickson on
On Jul 19, 9:26 am, Bret Cahill <BretCah...(a)peoplepc.com> wrote:
> Does this look familiar?
>
> Wolfram Alpha won't plot it.
>
> An alternate form:
>
> [ (3  integral |(e^(-3 i t)-e^(3 i t)) (e^(-3 i t)+e^(3 i t))|
> dt) ]  /  (6 t-sin(6 t))
>
> Bret Cahill

If you really mean F = int(f dt)/(6t - sin(6t)) with f = |(e^(-3 i t)-
e^(3 i t)) (e^(-3 i t)+e^(3 i t))|, then I get, using Maple 9.5:
F := -2*signum(sin(3*t)*cos(3*t))*cos(3*t)^2/(6*t-sin(6*t)).
[signum(x) = sign(x) = x/|x| if x <>0, and in my setting, signum(0) =
0.] The plot of F looks somewhat like a damped triangular waveform,
but with slightly curved "hypontenuse".

R.G. Vickson
From: Bret Cahill on
> > Does this look familiar?
>
> > Wolfram Alpha won't plot it.
>
> > An alternate form:
>
> > [ (3  integral |(e^(-3 i t)-e^(3 i t)) (e^(-3 i t)+e^(3 i t))|
> > dt) ]  /  (6 t-sin(6 t))
>
> > Bret Cahill
>
> If you really mean F = int(f dt)/(6t - sin(6t)) with f = |(e^(-3 i t)-
> e^(3 i t)) (e^(-3 i t)+e^(3 i t))|, then I get, using Maple 9.5:
> F := -2*signum(sin(3*t)*cos(3*t))*cos(3*t)^2/(6*t-sin(6*t)).
> [signum(x) = sign(x) = x/|x| if x <>0, and in my setting, signum(0) =
> 0.] The plot of F looks somewhat like a damped triangular waveform,
> but with slightly curved "hypontenuse".

Thanks.

Is this something that shows up in science or engineering very often?


Bret Cahill




From: Bret Cahill on
> > Does this look familiar?
>
> > Wolfram Alpha won't plot it.
>
> > An alternate form:
>
> > [ (3  integral |(e^(-3 i t)-e^(3 i t)) (e^(-3 i t)+e^(3 i t))|
> > dt) ]  /  (6 t-sin(6 t))
>
> > Bret Cahill
>
> If you really mean F = int(f dt)/(6t - sin(6t)) with f = |(e^(-3 i t)-
> e^(3 i t)) (e^(-3 i t)+e^(3 i t))|, then I get, using Maple 9.5:
> F := -2*signum(sin(3*t)*cos(3*t))*cos(3*t)^2/(6*t-sin(6*t)).
> [signum(x) = sign(x) = x/|x| if x <>0, and in my setting, signum(0) =
> 0.] The plot of F looks somewhat like a damped triangular waveform,
> but with slightly curved "hypontenuse".

It is always positive and, except for the waves, basically horizontal?


Bret Cahill