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From: ehsjr on 23 May 2010 22:44 Ade wrote: > don(a)manx.misty.com did gone and wrote: > >>In article <MPG.26634d95671d95009896f8(a)news.enta.net>, Ade wrote: >> > > [diode in series] > >>>That, as it happens, fixed the problem completely (no more afterglow). >>>By using green LEDs on "High" and "Medium", I only needed to add 1 >>>diode, in series with the red LED. >> >> Congratulations! Good! >> > > > Ta :) It was a nice moment, for sure... > > >>>The one downside is it's increased the overall current draw to ~12.5mA >>>when the red LED is lit (vs. 5.6mA when the mid LED is on, and ~9.5mA >>>for the "High" LED). >> >> Are you saying that current draw while the red LED is on increased as a >>result of adding a diode in series with the red LED? (If so, can yiou >>retry your measurements?) > > > On the breadboard, it definitely affected consumption. Total draw (when > the red LED was lit) rose from ~9.5mA to ~13mA. By touching one side of > the diode with my pliers, I could reduce the current to ~7.9mA, by > touching the other side it would go back to 13mA. I decided this was > ludicrous, and so now I've built the circuit on stripboard. Max current > draw @ 5v is now ~8mA with the red LED lit - little different to when > the high green LED is on. The middle LED still uses less current, > presumably for the reasons you explain below. > > Part of the new lower-consumption may be because I've made the voltage > divider with 3M3ohm resistors instead of the 1M ohm specified; only > because I don't have any 1M ohm here, and I didn't want to muck about > with 3x 3M3s on each side like I did on the breadboard. The circuit > still works perfectly - so I'm going to stick with the 3M3's I think. > > >> Or that the red LED is using more current than either green one? >> >> The mid LED may be using less if the 74LS02 has higher output resistance >>or higher voltage drop in its output than the op-amps have. > > > Quite possible. The '02 chip is around 30 years old, so it probably had > a higher resistance/voltage drop from new. > > >> The green LED may have a little more voltage drop than the red one > > plus > >>a diode. > > > The output is very similar now with the two op-amp driven LEDs. Only the > logic-driven LED is lower. The overall brightness of each LED is pretty > similar, however, which makes no sense to me (unless the difference is > too small to make much odds. > > >>>You're right that there's no decoupling caps - and there probably > > ought > >>>to be. Is this likely to be an issue if the circuit is powered from a >>>steady-state DC source (i.e. a battery)? >> >> Sometimes these caps prevent oscillations and absorb power supply noise >>caused by things switching. > > > It's no bother to add some to the stripboard version. > > >>>OK, another question to add to the mix: >>> >>>When in place, this circuit will be powered from a 24v battery (2x truck >>>batteries), stepped down to 5v via a regulator. >>> >>>http://www.dimensionengineering.com/switchingregulators.htm contains a >>>handy (assuming it's right) formula for estimating the waste current >>>that a linear regulator will have to dump as heat. Assuming my circuit >>>draws a maximum of 19mA: >>> >>>(24v-5v) * 13mA = 247mW >> >> That is correct. >> >> Will this have to work if the vehicle is running? (battery voltage more >>like 28V - 299 mW to dissipate) > > > It's possible that the circuit could be accidentally left on when the > vehicle is running (it wouldn't ordinarily be used in that > circumstance). However, now that consumption is less than 9mA in all > conditions, I reckon that regulator will have an even easier job: 171mW > @ 24V or 207mW @ 28V. > > >>>(or, I could hook it to just one of the batteries, and reduce the waste >>>to 91mW, at the risk of unbalancing the battery bank) >>> >>>Does that sound about right, and will a standard 7805 regulator >>>dissipate 247mW without an added heatsink? >> >> This does sound OK to me. I would let things run for a while (at least >>10 minutes) and see if a damp tissue sizzles when touched to the 7805's >>heatsink tab. In the unlikely eent that occurs, a small heatsink should >>easily be sufficient for 299 mW. > > > I lightly burned myself the other day on a 7805 after it had > accidentally tried to feed a short circuit for a few seconds... I like > the sound of the wet tissue test... > You can move some of the heat out of the 7805, by putting a resistor in series between the battery and Vin of the chip. e.g. At 9 mA, a 1K resistor will drop 9 volts, so the 7805 would dissipate (24-9-5)*.009 or ~ 90mW. The resistor would dissipate ~ 81 mW. That said, the 7805 will handle the 171 mW you'd get at 24V Vin and 9mA current, without the added resistor and without a heatsink. Ed |